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Weight of Water required to form Immiscible Mixture with Liquid given Weight Formula

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The Weight of Water in Immiscible Mixture with another liquid. Check FAQs

W water = \frac{W B \cdot P o water \cdot M water}{P B ° \cdot M B}

W_water - Weight of Water in Immiscible Mixture?W_B - Weight of Liquid B?P^owater - Partial Pressure of Pure Water?M_water - Molecular Mass of Water?P_B° - Vapor Pressure of Pure Component B?M_B - Molecular Mass of Liquid B?

Weight of Water required to form Immiscible Mixture with Liquid given Weight Example

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Here is how the Weight of Water required to form Immiscible Mixture with Liquid given Weight equation looks like with Values.

Here is how the Weight of Water required to form Immiscible Mixture with Liquid given Weight equation looks like with Units.

Here is how the Weight of Water required to form Immiscible Mixture with Liquid given Weight equation looks like.

0.12 = \frac{0.1 \cdot 0.53 \cdot 18}{0.25 \cdot 31.8}

0.12g = \frac{0.1g \cdot 0.53Pa \cdot 18g}{0.25Pa \cdot 31.8g}

0.12 = \frac{0.1 \cdot 0.53 \cdot 18}{0.25 \cdot 31.8}

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Immiscible Liquids » fx Weight of Water required to form Immiscible Mixture with Liquid given Weight

Weight of Water required to form Immiscible Mixture with Liquid given Weight Solution

Follow our step by step solution on how to calculate Weight of Water required to form Immiscible Mixture with Liquid given Weight?

FIRST Step Consider the formula

W water = \frac{W B \cdot P o water \cdot M water}{P B ° \cdot M B}

Next Step Substitute values of Variables

∴

W water = \frac{0.1g \cdot 0.53Pa \cdot 18g}{0.25Pa \cdot 31.8g}

Next Step Convert Units

∴

W water = \frac{0.0001kg \cdot 0.53Pa \cdot 0.018kg}{0.25Pa \cdot 0.0318kg}

Next Step Prepare to Evaluate

∴

W water = \frac{0.0001 \cdot 0.53 \cdot 0.018}{0.25 \cdot 0.0318}

Next Step Evaluate

∴

W water = 0.00012kg

LAST Step Convert to Output's Unit

∴

W water = 0.12g

Weight of Water required to form Immiscible Mixture with Liquid given Weight Formula Elements

Variables

Weight of Water in Immiscible Mixture

The Weight of Water in Immiscible Mixture with another liquid.

Symbol: W_water

Measurement: WeightUnit: g

Note: Value should be greater than 0.

Formulas to find Weight of Water in Immiscible Mixture

Weight of Liquid B

The Weight of Liquid B in a mixture of immiscible liquids.

Symbol: W_B

Measurement: WeightUnit: g

Note: Value should be greater than 0.

Formulas to find Weight of Liquid B

Partial Pressure of Pure Water

The Partial Pressure of Pure Water is the pressure exerted by water vapours prior addition to solution.

Symbol: P^owater

Measurement: PressureUnit: Pa

Note: Value should be greater than 0.

Formulas to find Partial Pressure of Pure Water

Molecular Mass of Water

The Molecular Mass of Water is equal to 18g per mole.

Symbol: M_water

Measurement: WeightUnit: g

Note: Value should be greater than 0.

Formulas to find Molecular Mass of Water

Vapor Pressure of Pure Component B

Vapor Pressure of Pure Component B is the pressure exerted by a liquid or solid molecules of only B in a closed system in which they are in equilibrium with the vapour phase.

Symbol: P_B°

Measurement: PressureUnit: Pa

Note: Value can be positive or negative.

Formulas to find Vapor Pressure of Pure Component B

Molecular Mass of Liquid B

The Molecular Mass of Liquid B in a mixture of immiscible liquids.

Symbol: M_B

Measurement: WeightUnit: g

Note: Value should be greater than 0.

Formulas to find Molecular Mass of Liquid B

Other formulas in Immiscible Liquids category

Go Total Pressure of Mixture of Two Immiscible Liquids

P = P A ° + P B °

Go Partial Vapour Pressure of Immiscible Liquid given Partial Pressure of other Liquid

P A ° = \frac{W A \cdot M B \cdot P B °}{M A \cdot W B}

Go Ratio of Partial Vapour Pressures of 2 Immiscible Liquids given Weight and Molecular Mass

P A:B = \frac{W A \cdot M B}{W B \cdot M A}

Go Ratio of Partial Pressure of 2 Immiscible Liquids given Number of Moles

P A:B = \frac{n A}{n B}

How to Evaluate Weight of Water required to form Immiscible Mixture with Liquid given Weight?

Weight of Water required to form Immiscible Mixture with Liquid given Weight evaluator uses Weight of Water in Immiscible Mixture = (Weight of Liquid B*Partial Pressure of Pure Water*Molecular Mass of Water)/(Vapor Pressure of Pure Component B*Molecular Mass of Liquid B) to evaluate the Weight of Water in Immiscible Mixture, The Weight of Water required to form Immiscible Mixture with Liquid given Weight considering A as water and B as other liquids for corresponding parameters. Weight of Water in Immiscible Mixture is denoted by W_water symbol.

How to evaluate Weight of Water required to form Immiscible Mixture with Liquid given Weight using this online evaluator? To use this online evaluator for Weight of Water required to form Immiscible Mixture with Liquid given Weight, enter Weight of Liquid B (W_B), Partial Pressure of Pure Water (P^owater), Molecular Mass of Water (M_water), Vapor Pressure of Pure Component B (P_B°) & Molecular Mass of Liquid B (M_B) and hit the calculate button.

FAQs on Weight of Water required to form Immiscible Mixture with Liquid given Weight

What is the formula to find Weight of Water required to form Immiscible Mixture with Liquid given Weight?

The formula of Weight of Water required to form Immiscible Mixture with Liquid given Weight is expressed as Weight of Water in Immiscible Mixture = (Weight of Liquid B*Partial Pressure of Pure Water*Molecular Mass of Water)/(Vapor Pressure of Pure Component B*Molecular Mass of Liquid B). Here is an example- 152.64 = (0.0001*0.53*0.018)/(0.25*0.0318).

How to calculate Weight of Water required to form Immiscible Mixture with Liquid given Weight?

With Weight of Liquid B (W_B), Partial Pressure of Pure Water (P^owater), Molecular Mass of Water (M_water), Vapor Pressure of Pure Component B (P_B°) & Molecular Mass of Liquid B (M_B) we can find Weight of Water required to form Immiscible Mixture with Liquid given Weight using the formula - Weight of Water in Immiscible Mixture = (Weight of Liquid B*Partial Pressure of Pure Water*Molecular Mass of Water)/(Vapor Pressure of Pure Component B*Molecular Mass of Liquid B).

Can the Weight of Water required to form Immiscible Mixture with Liquid given Weight be negative?

No, the Weight of Water required to form Immiscible Mixture with Liquid given Weight, measured in Weight cannot be negative.

Which unit is used to measure Weight of Water required to form Immiscible Mixture with Liquid given Weight?

Weight of Water required to form Immiscible Mixture with Liquid given Weight is usually measured using the Gram[g] for Weight. Kilogram[g], Milligram[g], Ton (Metric)[g] are the few other units in which Weight of Water required to form Immiscible Mixture with Liquid given Weight can be measured.

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Weight of Water required to form Immiscible Mixture with Liquid given Weight Formula

Weight of Water required to form Immiscible Mixture with Liquid given Weight Example

Weight of Water required to form Immiscible Mixture with Liquid given Weight Solution

Weight of Water required to form Immiscible Mixture with Liquid given Weight Formula Elements

Other formulas in Immiscible Liquids category

How to Evaluate Weight of Water required to form Immiscible Mixture with Liquid given Weight?

FAQs on Weight of Water required to form Immiscible Mixture with Liquid given Weight

Variable Name