Weight of Liquid required to form Immiscible Mixture with Water Formula

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The Weight of Liquid B in a mixture of immiscible liquids. Check FAQs
WB=WwaterPB°MBPowaterMwater
WB - Weight of Liquid B?Wwater - Weight of Water in Immiscible Mixture?PB° - Vapor Pressure of Pure Component B?MB - Molecular Mass of Liquid B?Powater - Partial Pressure of Pure Water?Mwater - Molecular Mass of Water?

Weight of Liquid required to form Immiscible Mixture with Water Example

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Here is how the Weight of Liquid required to form Immiscible Mixture with Water equation looks like with Values.

Here is how the Weight of Liquid required to form Immiscible Mixture with Water equation looks like with Units.

Here is how the Weight of Liquid required to form Immiscible Mixture with Water equation looks like.

0.1Edit=0.12Edit0.25Edit31.8Edit0.53Edit18Edit
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Weight of Liquid required to form Immiscible Mixture with Water Solution

Follow our step by step solution on how to calculate Weight of Liquid required to form Immiscible Mixture with Water?

FIRST Step Consider the formula
WB=WwaterPB°MBPowaterMwater
Next Step Substitute values of Variables
WB=0.12g0.25Pa31.8g0.53Pa18g
Next Step Convert Units
WB=0.0001kg0.25Pa0.0318kg0.53Pa0.018kg
Next Step Prepare to Evaluate
WB=0.00010.250.03180.530.018
Next Step Evaluate
WB=0.0001kg
LAST Step Convert to Output's Unit
WB=0.1g

Weight of Liquid required to form Immiscible Mixture with Water Formula Elements

Variables
Weight of Liquid B
The Weight of Liquid B in a mixture of immiscible liquids.
Symbol: WB
Measurement: WeightUnit: g
Note: Value should be greater than 0.
Weight of Water in Immiscible Mixture
The Weight of Water in Immiscible Mixture with another liquid.
Symbol: Wwater
Measurement: WeightUnit: g
Note: Value should be greater than 0.
Vapor Pressure of Pure Component B
Vapor Pressure of Pure Component B is the pressure exerted by a liquid or solid molecules of only B in a closed system in which they are in equilibrium with the vapour phase.
Symbol: PB°
Measurement: PressureUnit: Pa
Note: Value can be positive or negative.
Molecular Mass of Liquid B
The Molecular Mass of Liquid B in a mixture of immiscible liquids.
Symbol: MB
Measurement: WeightUnit: g
Note: Value should be greater than 0.
Partial Pressure of Pure Water
The Partial Pressure of Pure Water is the pressure exerted by water vapours prior addition to solution.
Symbol: Powater
Measurement: PressureUnit: Pa
Note: Value should be greater than 0.
Molecular Mass of Water
The Molecular Mass of Water is equal to 18g per mole.
Symbol: Mwater
Measurement: WeightUnit: g
Note: Value should be greater than 0.

Other formulas in Immiscible Liquids category

​Go Total Pressure of Mixture of Two Immiscible Liquids
P=PA°+PB°
​Go Partial Vapour Pressure of Immiscible Liquid given Partial Pressure of other Liquid
PA°=WAMBPB°MAWB
​Go Ratio of Partial Vapour Pressures of 2 Immiscible Liquids given Weight and Molecular Mass
PA:B=WAMBWBMA
​Go Ratio of Partial Pressure of 2 Immiscible Liquids given Number of Moles
PA:B=nAnB

How to Evaluate Weight of Liquid required to form Immiscible Mixture with Water?

Weight of Liquid required to form Immiscible Mixture with Water evaluator uses Weight of Liquid B = (Weight of Water in Immiscible Mixture*Vapor Pressure of Pure Component B*Molecular Mass of Liquid B)/(Partial Pressure of Pure Water*Molecular Mass of Water) to evaluate the Weight of Liquid B, The Weight of liquid required to form immiscible mixture with water considering A as water and B as other liquids for corresponding parameters. Weight of Liquid B is denoted by WB symbol.

How to evaluate Weight of Liquid required to form Immiscible Mixture with Water using this online evaluator? To use this online evaluator for Weight of Liquid required to form Immiscible Mixture with Water, enter Weight of Water in Immiscible Mixture (Wwater), Vapor Pressure of Pure Component B (PB°), Molecular Mass of Liquid B (MB), Partial Pressure of Pure Water (Powater) & Molecular Mass of Water (Mwater) and hit the calculate button.

FAQs on Weight of Liquid required to form Immiscible Mixture with Water

What is the formula to find Weight of Liquid required to form Immiscible Mixture with Water?
The formula of Weight of Liquid required to form Immiscible Mixture with Water is expressed as Weight of Liquid B = (Weight of Water in Immiscible Mixture*Vapor Pressure of Pure Component B*Molecular Mass of Liquid B)/(Partial Pressure of Pure Water*Molecular Mass of Water). Here is an example- 78.61635 = (0.00012*0.25*0.0318)/(0.53*0.018).
How to calculate Weight of Liquid required to form Immiscible Mixture with Water?
With Weight of Water in Immiscible Mixture (Wwater), Vapor Pressure of Pure Component B (PB°), Molecular Mass of Liquid B (MB), Partial Pressure of Pure Water (Powater) & Molecular Mass of Water (Mwater) we can find Weight of Liquid required to form Immiscible Mixture with Water using the formula - Weight of Liquid B = (Weight of Water in Immiscible Mixture*Vapor Pressure of Pure Component B*Molecular Mass of Liquid B)/(Partial Pressure of Pure Water*Molecular Mass of Water).
Can the Weight of Liquid required to form Immiscible Mixture with Water be negative?
No, the Weight of Liquid required to form Immiscible Mixture with Water, measured in Weight cannot be negative.
Which unit is used to measure Weight of Liquid required to form Immiscible Mixture with Water?
Weight of Liquid required to form Immiscible Mixture with Water is usually measured using the Gram[g] for Weight. Kilogram[g], Milligram[g], Ton (Metric)[g] are the few other units in which Weight of Liquid required to form Immiscible Mixture with Water can be measured.
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