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Wall Section Gross Area given Axial Capacity of Wall Formula

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Gross Area of Column is the total area enclosed by the column. Check FAQs

A g = \frac{ϕP n}{0.55 \cdot ϕ \cdot f' c \cdot (1 - {(\frac{k \cdot l c}{32 \cdot h})}^{2})}

A_g - Gross Area of Column?ϕP_n - Axial Capacity of Wall?ϕ - Strength Reduction Factor for Bearing Walls?f'_c - Specified 28-Day Compressive Strength of Concrete?k - Effective Length Factor?l_c - Vertical Distance between Supports?h - Overall Thickness of Wall?

Wall Section Gross Area given Axial Capacity of Wall Example

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Here is how the Wall Section Gross Area given Axial Capacity of Wall equation looks like with Values.

Here is how the Wall Section Gross Area given Axial Capacity of Wall equation looks like with Units.

Here is how the Wall Section Gross Area given Axial Capacity of Wall equation looks like.

522.6706 = \frac{10}{0.55 \cdot 0.7 \cdot 50 \cdot (1 - {(\frac{0.5 \cdot 1000}{32 \cdot 200})}^{2})}

522.6706mm² = \frac{10kN}{0.55 \cdot 0.7 \cdot 50MPa \cdot (1 - {(\frac{0.5 \cdot 1000mm}{32 \cdot 200mm})}^{2})}

522.6706 = \frac{10}{0.55 \cdot 0.7 \cdot 50 \cdot (1 - {(\frac{0.5 \cdot 1000}{32 \cdot 200})}^{2})}

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Wall Section Gross Area given Axial Capacity of Wall Solution

Follow our step by step solution on how to calculate Wall Section Gross Area given Axial Capacity of Wall?

FIRST Step Consider the formula

A g = \frac{ϕP n}{0.55 \cdot ϕ \cdot f' c \cdot (1 - {(\frac{k \cdot l c}{32 \cdot h})}^{2})}

Next Step Substitute values of Variables

∴

A g = \frac{10kN}{0.55 \cdot 0.7 \cdot 50MPa \cdot (1 - {(\frac{0.5 \cdot 1000mm}{32 \cdot 200mm})}^{2})}

Next Step Convert Units

∴

A g = \frac{10000N}{0.55 \cdot 0.7 \cdot 5E+7Pa \cdot (1 - {(\frac{0.5 \cdot 1m}{32 \cdot 0.2m})}^{2})}

Next Step Prepare to Evaluate

∴

A g = \frac{10000}{0.55 \cdot 0.7 \cdot 5E+7 \cdot (1 - {(\frac{0.5 \cdot 1}{32 \cdot 0.2})}^{2})}

Next Step Evaluate

∴

A g = 0.000522670647946993m²

Next Step Convert to Output's Unit

∴

A g = 522.670647946993mm²

LAST Step Rounding Answer

∴

A g = 522.6706mm²

Wall Section Gross Area given Axial Capacity of Wall Formula Elements

Variables

Gross Area of Column

Gross Area of Column is the total area enclosed by the column.

Symbol: A_g

Measurement: AreaUnit: mm²

Note: Value should be greater than 0.

Formulas to find Gross Area of Column

Axial Capacity of Wall

Axial Capacity of Wall is the capacity of the column to resist axially applied loads.

Symbol: ϕP_n

Measurement: ForceUnit: kN

Note: Value should be greater than 0.

Formulas to find Axial Capacity of Wall

Strength Reduction Factor for Bearing Walls

Strength Reduction Factor for Bearing Walls is the ratio of elastic strength to yield strength.

Symbol: ϕ

Measurement: NAUnit: Unitless

Note: Value should be greater than 0.

Formulas to find Strength Reduction Factor for Bearing Walls

Specified 28-Day Compressive Strength of Concrete

Specified 28-Day Compressive Strength of Concrete is the maximum compressive load concrete can withstand after the concrete mix is formed.

Symbol: f'_c

Measurement: StressUnit: MPa

Note: Value should be greater than 0.

Formulas to find Specified 28-Day Compressive Strength of Concrete

Effective Length Factor

Effective Length Factor is the factor used for the members in the frame. It depends on the ratio of compression member stiffness to the end restraint stiffness.

Symbol: k

Measurement: NAUnit: Unitless

Note: Value should be greater than 0.

Formulas to find Effective Length Factor

Vertical Distance between Supports

Vertical Distance between Supports is the distance between two intermediate supports for a structure in the vertical direction.

Symbol: l_c

Measurement: LengthUnit: mm

Note: Value can be positive or negative.

Formulas to find Vertical Distance between Supports

Overall Thickness of Wall

Overall Thickness of Wall is the wall thickness in millimeters.

Symbol: h

Measurement: LengthUnit: mm

Note: Value should be greater than 0.

Formulas to find Overall Thickness of Wall

Other formulas in Load Bearing Walls category

Go Axial Capacity of Wall

ϕP n = 0.55 \cdot ϕ \cdot f' c \cdot A g \cdot (1 - {(\frac{k \cdot l c}{32 \cdot h})}^{2})

Go 28-Day Concrete Compressive Strength given Axial Capacity of Wall

f' c = \frac{ϕP n}{0.55 \cdot ϕ \cdot A g \cdot (1 - {(\frac{k \cdot l c}{32 \cdot h})}^{2})}

How to Evaluate Wall Section Gross Area given Axial Capacity of Wall?

Wall Section Gross Area given Axial Capacity of Wall evaluator uses Gross Area of Column = (Axial Capacity of Wall)/(0.55*Strength Reduction Factor for Bearing Walls*Specified 28-Day Compressive Strength of Concrete*(1-((Effective Length Factor*Vertical Distance between Supports)/(32*Overall Thickness of Wall))^2)) to evaluate the Gross Area of Column, The Wall Section Gross Area given Axial Capacity of Wall formula is defined as the total area enclosed by the walls. It is the sum of all floors of a building included within the outside faces of its exterior walls, including all vertical penetration areas. Gross Area of Column is denoted by A_g symbol.

How to evaluate Wall Section Gross Area given Axial Capacity of Wall using this online evaluator? To use this online evaluator for Wall Section Gross Area given Axial Capacity of Wall, enter Axial Capacity of Wall (ϕP_n), Strength Reduction Factor for Bearing Walls (ϕ), Specified 28-Day Compressive Strength of Concrete (f'_c), Effective Length Factor (k), Vertical Distance between Supports (l_c) & Overall Thickness of Wall (h) and hit the calculate button.

FAQs on Wall Section Gross Area given Axial Capacity of Wall

What is the formula to find Wall Section Gross Area given Axial Capacity of Wall?

The formula of Wall Section Gross Area given Axial Capacity of Wall is expressed as Gross Area of Column = (Axial Capacity of Wall)/(0.55*Strength Reduction Factor for Bearing Walls*Specified 28-Day Compressive Strength of Concrete*(1-((Effective Length Factor*Vertical Distance between Supports)/(32*Overall Thickness of Wall))^2)). Here is an example- 5.2E+8 = (10000)/(0.55*0.7*50000000*(1-((0.5*1)/(32*0.2))^2)).

How to calculate Wall Section Gross Area given Axial Capacity of Wall?

With Axial Capacity of Wall (ϕP_n), Strength Reduction Factor for Bearing Walls (ϕ), Specified 28-Day Compressive Strength of Concrete (f'_c), Effective Length Factor (k), Vertical Distance between Supports (l_c) & Overall Thickness of Wall (h) we can find Wall Section Gross Area given Axial Capacity of Wall using the formula - Gross Area of Column = (Axial Capacity of Wall)/(0.55*Strength Reduction Factor for Bearing Walls*Specified 28-Day Compressive Strength of Concrete*(1-((Effective Length Factor*Vertical Distance between Supports)/(32*Overall Thickness of Wall))^2)).

Can the Wall Section Gross Area given Axial Capacity of Wall be negative?

No, the Wall Section Gross Area given Axial Capacity of Wall, measured in Area cannot be negative.

Which unit is used to measure Wall Section Gross Area given Axial Capacity of Wall?

Wall Section Gross Area given Axial Capacity of Wall is usually measured using the Square Millimeter[mm²] for Area. Square Meter[mm²], Square Kilometer[mm²], Square Centimeter[mm²] are the few other units in which Wall Section Gross Area given Axial Capacity of Wall can be measured.

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Wall Section Gross Area given Axial Capacity of Wall Formula

Wall Section Gross Area given Axial Capacity of Wall Example

Wall Section Gross Area given Axial Capacity of Wall Solution

Wall Section Gross Area given Axial Capacity of Wall Formula Elements

Other formulas in Load Bearing Walls category

How to Evaluate Wall Section Gross Area given Axial Capacity of Wall?

FAQs on Wall Section Gross Area given Axial Capacity of Wall

Variable Name