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Volume of Wasted Sludge Per Day given Oxygen Demand and Ultimate BOD Both Formula

GoVolume of Wasted Sludge Per Day given Oxygen Required in Aeration Tank Formula

GoVolume of Wasted Sludge Per Day given Oxygen Demand of Biomass Formula

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Volume of Wasted Sludge is the amount of sludge that is removed or wasted from a wastewater treatment process on a daily basis. Check FAQs

Q w' = \frac{(\frac{Q s \cdot (Q i - Q)}{\frac{BOD5}{BOD u}}) - O 2}{D O2 \cdot X}

Q_w' - Volume of Wasted Sludge?Q_s - Sewage Discharge?Q_i - Influent BOD?Q - Effluent BOD?BOD5 - 5 Days BOD?BOD^u - Ultimate BOD?O₂ - Theoretical Oxygen Requirement?D^O2 - Oxygen Demand of Biomass?X - MLSS?

Volume of Wasted Sludge Per Day given Oxygen Demand and Ultimate BOD Both Example

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Here is how the Volume of Wasted Sludge Per Day given Oxygen Demand and Ultimate BOD Both equation looks like with Values.

Here is how the Volume of Wasted Sludge Per Day given Oxygen Demand and Ultimate BOD Both equation looks like with Units.

Here is how the Volume of Wasted Sludge Per Day given Oxygen Demand and Ultimate BOD Both equation looks like.

0.0777 = \frac{(\frac{10 \cdot (13.2 - 0.4)}{\frac{1.36}{2}}) - 2.5}{2.02 \cdot 1200}

0.0777m³/s = \frac{(\frac{10m³/s \cdot (13.2mg/L - 0.4mg/L)}{\frac{1.36mg/L}{2mg/L}}) - 2.5mg/d}{2.02 \cdot 1200mg/L}

0.0777 = \frac{(\frac{10 \cdot (13.2 - 0.4)}{\frac{1.36}{2}}) - 2.5}{2.02 \cdot 1200}

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Volume of Wasted Sludge Per Day given Oxygen Demand and Ultimate BOD Both Solution

Follow our step by step solution on how to calculate Volume of Wasted Sludge Per Day given Oxygen Demand and Ultimate BOD Both?

FIRST Step Consider the formula

Q w' = \frac{(\frac{Q s \cdot (Q i - Q)}{\frac{BOD5}{BOD u}}) - O 2}{D O2 \cdot X}

Next Step Substitute values of Variables

∴

Q w' = \frac{(\frac{10m³/s \cdot (13.2mg/L - 0.4mg/L)}{\frac{1.36mg/L}{2mg/L}}) - 2.5mg/d}{2.02 \cdot 1200mg/L}

Next Step Convert Units

∴

Q w' = \frac{(\frac{10m³/s \cdot (0.0132kg/m³ - 0.0004kg/m³)}{\frac{0.0014kg/m³}{0.002kg/m³}}) - 2.9E-11kg/s}{2.02 \cdot 1.2kg/m³}

Next Step Prepare to Evaluate

∴

Q w' = \frac{(\frac{10 \cdot (0.0132 - 0.0004)}{\frac{0.0014}{0.002}}) - 2.9E-11}{2.02 \cdot 1.2}

Next Step Evaluate

∴

Q w' = 0.0776548242940231m³/s

LAST Step Rounding Answer

∴

Q w' = 0.0777m³/s

Volume of Wasted Sludge Per Day given Oxygen Demand and Ultimate BOD Both Formula Elements

Variables

Volume of Wasted Sludge

Volume of Wasted Sludge is the amount of sludge that is removed or wasted from a wastewater treatment process on a daily basis.

Symbol: Q_w'

Measurement: Volumetric Flow RateUnit: m³/s

Note: Value should be greater than 0.

Formulas to find Volume of Wasted Sludge

Sewage Discharge

Sewage Discharge is the flow rate of sewage when it is being discharged in the river.

Symbol: Q_s

Measurement: Volumetric Flow RateUnit: m³/s

Note: Value should be greater than 0.

Formulas to find Sewage Discharge

Influent BOD

Influent BOD is the total amount of BOD which is present in the incoming sewage.

Symbol: Q_i

Measurement: DensityUnit: mg/L

Note: Value should be greater than 0.

Formulas to find Influent BOD

Effluent BOD

Effluent BOD is the amount of BOD present in the outing sewage.

Symbol: Q

Measurement: DensityUnit: mg/L

Note: Value should be greater than 0.

Formulas to find Effluent BOD

5 Days BOD

5 Days BOD is an indicator of how much oxygen is utilized by a natural water sample in five days at 20 degrees C.

Symbol: BOD5

Measurement: DensityUnit: mg/L

Note: Value should be greater than 0.

Formulas to find 5 Days BOD

Ultimate BOD

Ultimate BOD is the amount of oxygen required to decompose all of the organic material after infinite time.

Symbol: BOD^u

Measurement: DensityUnit: mg/L

Note: Value should be greater than 0.

Formulas to find Ultimate BOD

Theoretical Oxygen Requirement

Theoretical Oxygen Requirement is the calculated amount of oxygen required to oxidize a compound to its final oxidation products.

Symbol: O₂

Measurement: Mass Flow RateUnit: mg/d

Note: Value should be greater than 0.

Formulas to find Theoretical Oxygen Requirement

Oxygen Demand of Biomass

Oxygen Demand of Biomass is the amount of oxygen required by the microorganisms to decompose organic matter present in biomass.

Symbol: D^O2

Measurement: NAUnit: Unitless

Note: Value should be greater than 0.

Formulas to find Oxygen Demand of Biomass

MLSS

MLSS is the sum of volatile suspended solids (organics) and fixed suspended solids (inorganics).

Symbol: X

Measurement: DensityUnit: mg/L

Note: Value should be between 1000 to 6500.

Formulas to find MLSS

Other Formulas to find Volume of Wasted Sludge

Go Volume of Wasted Sludge Per Day given Oxygen Required in Aeration Tank

Q w' = \frac{(\frac{Q s \cdot (Q i - Q)}{f}) - O 2}{1.42 \cdot X}

Go Volume of Wasted Sludge Per Day given Oxygen Demand of Biomass

Q w' = \frac{(\frac{Q s \cdot (Q i - Q)}{f}) - O 2}{D O2 \cdot X}

How to Evaluate Volume of Wasted Sludge Per Day given Oxygen Demand and Ultimate BOD Both?

Volume of Wasted Sludge Per Day given Oxygen Demand and Ultimate BOD Both evaluator uses Volume of Wasted Sludge = (((Sewage Discharge*(Influent BOD-Effluent BOD))/(5 Days BOD/Ultimate BOD))-Theoretical Oxygen Requirement)/(Oxygen Demand of Biomass*MLSS) to evaluate the Volume of Wasted Sludge, The Volume of Wasted Sludge Per Day given Oxygen Demand and Ultimate BOD Both formula is defined as the calculation of volume of wasted sludge per day when we have prior information of oxygen demand and ultimate BOD both. Volume of Wasted Sludge is denoted by Q_w' symbol.

How to evaluate Volume of Wasted Sludge Per Day given Oxygen Demand and Ultimate BOD Both using this online evaluator? To use this online evaluator for Volume of Wasted Sludge Per Day given Oxygen Demand and Ultimate BOD Both, enter Sewage Discharge (Q_s), Influent BOD (Q_i), Effluent BOD (Q), 5 Days BOD (BOD5), Ultimate BOD (BOD^u), Theoretical Oxygen Requirement (O₂), Oxygen Demand of Biomass (D^O2) & MLSS (X) and hit the calculate button.

FAQs on Volume of Wasted Sludge Per Day given Oxygen Demand and Ultimate BOD Both

What is the formula to find Volume of Wasted Sludge Per Day given Oxygen Demand and Ultimate BOD Both?

The formula of Volume of Wasted Sludge Per Day given Oxygen Demand and Ultimate BOD Both is expressed as Volume of Wasted Sludge = (((Sewage Discharge*(Influent BOD-Effluent BOD))/(5 Days BOD/Ultimate BOD))-Theoretical Oxygen Requirement)/(Oxygen Demand of Biomass*MLSS). Here is an example- 0.077655 = (((10*(0.0132-0.0004))/(0.00136/0.002))-2.89351851851852E-11)/(2.02*1.2).

How to calculate Volume of Wasted Sludge Per Day given Oxygen Demand and Ultimate BOD Both?

With Sewage Discharge (Q_s), Influent BOD (Q_i), Effluent BOD (Q), 5 Days BOD (BOD5), Ultimate BOD (BOD^u), Theoretical Oxygen Requirement (O₂), Oxygen Demand of Biomass (D^O2) & MLSS (X) we can find Volume of Wasted Sludge Per Day given Oxygen Demand and Ultimate BOD Both using the formula - Volume of Wasted Sludge = (((Sewage Discharge*(Influent BOD-Effluent BOD))/(5 Days BOD/Ultimate BOD))-Theoretical Oxygen Requirement)/(Oxygen Demand of Biomass*MLSS).

What are the other ways to Calculate Volume of Wasted Sludge?

Here are the different ways to Calculate Volume of Wasted Sludge-

Volume of Wasted Sludge=(((Sewage Discharge*(Influent BOD-Effluent BOD))/Ratio of BOD to Ultimate BOD)-Theoretical Oxygen Requirement)/(1.42*MLSS)
Volume of Wasted Sludge=(((Sewage Discharge*(Influent BOD-Effluent BOD))/Ratio of BOD to Ultimate BOD)-Theoretical Oxygen Requirement)/(Oxygen Demand of Biomass*MLSS)
Volume of Wasted Sludge=(((Sewage Discharge*(Influent BOD-Effluent BOD))/(5 Days BOD/Ultimate BOD))-Theoretical Oxygen Requirement)/(1.42*MLSS)

Can the Volume of Wasted Sludge Per Day given Oxygen Demand and Ultimate BOD Both be negative?

No, the Volume of Wasted Sludge Per Day given Oxygen Demand and Ultimate BOD Both, measured in Volumetric Flow Rate cannot be negative.

Which unit is used to measure Volume of Wasted Sludge Per Day given Oxygen Demand and Ultimate BOD Both?

Volume of Wasted Sludge Per Day given Oxygen Demand and Ultimate BOD Both is usually measured using the Cubic Meter per Second[m³/s] for Volumetric Flow Rate. Cubic Meter per Day[m³/s], Cubic Meter per Hour[m³/s], Cubic Meter per Minute[m³/s] are the few other units in which Volume of Wasted Sludge Per Day given Oxygen Demand and Ultimate BOD Both can be measured.

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Volume of Wasted Sludge Per Day given Oxygen Demand and Ultimate BOD Both Formula

​GoVolume of Wasted Sludge Per Day given Oxygen Required in Aeration Tank Formula

​GoVolume of Wasted Sludge Per Day given Oxygen Demand of Biomass Formula

Volume of Wasted Sludge Per Day given Oxygen Demand and Ultimate BOD Both Example

Volume of Wasted Sludge Per Day given Oxygen Demand and Ultimate BOD Both Solution

Volume of Wasted Sludge Per Day given Oxygen Demand and Ultimate BOD Both Formula Elements

Other Formulas to find Volume of Wasted Sludge

How to Evaluate Volume of Wasted Sludge Per Day given Oxygen Demand and Ultimate BOD Both?

FAQs on Volume of Wasted Sludge Per Day given Oxygen Demand and Ultimate BOD Both

Variable Name

GoVolume of Wasted Sludge Per Day given Oxygen Required in Aeration Tank Formula

GoVolume of Wasted Sludge Per Day given Oxygen Demand of Biomass Formula