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Volume of Core in Short Axially Loaded Columns with Helical Ties Formula

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Volume of core is the volume of the core of a given spiral reinforcement. Check FAQs

V c = (\frac{π}{4}) \cdot {d c}^{2} \cdot P

V_c - Volume of Core?d_c - Diameter of Core?P - Pitch of Spiral Reinforcement?π - Archimedes' constant?

Volume of Core in Short Axially Loaded Columns with Helical Ties Example

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Here is how the Volume of Core in Short Axially Loaded Columns with Helical Ties equation looks like with Values.

Here is how the Volume of Core in Short Axially Loaded Columns with Helical Ties equation looks like with Units.

Here is how the Volume of Core in Short Axially Loaded Columns with Helical Ties equation looks like.

176714.5868 = (\frac{3.1416}{4}) \cdot 150^{2} \cdot 10

176714.5868m³ = (\frac{3.1416}{4}) \cdot {150mm}^{2} \cdot 10mm

176714.5868 = (\frac{3.1416}{4}) \cdot 150^{2} \cdot 10

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Volume of Core in Short Axially Loaded Columns with Helical Ties Solution

Follow our step by step solution on how to calculate Volume of Core in Short Axially Loaded Columns with Helical Ties?

FIRST Step Consider the formula

V c = (\frac{π}{4}) \cdot {d c}^{2} \cdot P

Next Step Substitute values of Variables

∴

V c = (\frac{π}{4}) \cdot {150mm}^{2} \cdot 10mm

Next Step Substitute values of Constants

∴

V c = (\frac{3.1416}{4}) \cdot {150mm}^{2} \cdot 10mm

Next Step Prepare to Evaluate

∴

V c = (\frac{3.1416}{4}) \cdot 150^{2} \cdot 10

Next Step Evaluate

∴

V c = 176714.586764426m³

LAST Step Rounding Answer

∴

V c = 176714.5868m³

Volume of Core in Short Axially Loaded Columns with Helical Ties Formula Elements

Variables

Constants

Volume of Core

Volume of core is the volume of the core of a given spiral reinforcement.

Symbol: V_c

Measurement: VolumeUnit: m³

Note: Value should be greater than 0.

Formulas to find Volume of Core

Diameter of Core

Diameter of core is the diameter of the core of a given spiral reinforcement.

Symbol: d_c

Measurement: LengthUnit: mm

Note: Value should be greater than 0.

Formulas to find Diameter of Core

Pitch of Spiral Reinforcement

Pitch of Spiral Reinforcement gives us a certain amount of flexural reinforcement.

Symbol: P

Measurement: LengthUnit: mm

Note: Value should be greater than 0.

Formulas to find Pitch of Spiral Reinforcement

Archimedes' constant

Archimedes' constant is a mathematical constant that represents the ratio of the circumference of a circle to its diameter.

Symbol: π

Value: 3.14159265358979323846264338327950288

Other formulas in Short Axially Loaded Columns with Helical Ties category

Go Factored Axial Load on Member of Spiral Columns

P f = 1.05 \cdot (0.4 \cdot f ck \cdot A c + 0.67 \cdot f y \cdot A st)

Go Characteristic Compressive Strength of Concrete given Factored Axial Load in Spiral Columns

f ck = \frac{(\frac{P f}{1.05}) - 0.67 \cdot f y \cdot A st}{0.4 \cdot A c}

Go Area of Concrete given Factored Axial Load

A c = \frac{(\frac{P f}{1.05}) - 0.67 \cdot f y \cdot A st}{0.4 \cdot f ck}

Go Characteristic Strength of Compression Reinforcement given Factored Load in Spiral Columns

f y = \frac{(\frac{P f}{1.05}) - (0.4 \cdot f ck \cdot A c)}{0.67 \cdot A st}

How to Evaluate Volume of Core in Short Axially Loaded Columns with Helical Ties?

Volume of Core in Short Axially Loaded Columns with Helical Ties evaluator uses Volume of Core = (pi/4)*Diameter of Core^(2)*Pitch of Spiral Reinforcement to evaluate the Volume of Core, The Volume of Core in Short Axially Loaded Columns with Helical Ties formula is defined as the volume of the core of the given column. Volume of Core is denoted by V_c symbol.

How to evaluate Volume of Core in Short Axially Loaded Columns with Helical Ties using this online evaluator? To use this online evaluator for Volume of Core in Short Axially Loaded Columns with Helical Ties, enter Diameter of Core (d_c) & Pitch of Spiral Reinforcement (P) and hit the calculate button.

FAQs on Volume of Core in Short Axially Loaded Columns with Helical Ties

What is the formula to find Volume of Core in Short Axially Loaded Columns with Helical Ties?

The formula of Volume of Core in Short Axially Loaded Columns with Helical Ties is expressed as Volume of Core = (pi/4)*Diameter of Core^(2)*Pitch of Spiral Reinforcement. Here is an example- 176714.6 = (pi/4)*0.15^(2)*0.01.

How to calculate Volume of Core in Short Axially Loaded Columns with Helical Ties?

With Diameter of Core (d_c) & Pitch of Spiral Reinforcement (P) we can find Volume of Core in Short Axially Loaded Columns with Helical Ties using the formula - Volume of Core = (pi/4)*Diameter of Core^(2)*Pitch of Spiral Reinforcement. This formula also uses Archimedes' constant .

Can the Volume of Core in Short Axially Loaded Columns with Helical Ties be negative?

No, the Volume of Core in Short Axially Loaded Columns with Helical Ties, measured in Volume cannot be negative.

Which unit is used to measure Volume of Core in Short Axially Loaded Columns with Helical Ties?

Volume of Core in Short Axially Loaded Columns with Helical Ties is usually measured using the Cubic Meter[m³] for Volume. Cubic Centimeter[m³], Cubic Millimeter[m³], Liter[m³] are the few other units in which Volume of Core in Short Axially Loaded Columns with Helical Ties can be measured.

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Volume of Core in Short Axially Loaded Columns with Helical Ties Formula

Volume of Core in Short Axially Loaded Columns with Helical Ties Example

Volume of Core in Short Axially Loaded Columns with Helical Ties Solution

Volume of Core in Short Axially Loaded Columns with Helical Ties Formula Elements

Other formulas in Short Axially Loaded Columns with Helical Ties category

How to Evaluate Volume of Core in Short Axially Loaded Columns with Helical Ties?

FAQs on Volume of Core in Short Axially Loaded Columns with Helical Ties

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