FormulaDen.com

Physics Chemistry Math Chemical Engineering Civil Electrical Electronics Electronics and Instrumentation Materials Science Mechanical Production Engineering Financial Health

Volume of Conductor Material when Resistance is Given(3 Phase 3 Wire US) Formula

GoVolume of Conductor Material (3 Phase 3 Wire US) Formula

GoVolume of Conductor Material when Area and Length is Given(3 Phase 3 Wire US) Formula

Fx Copy

LaTeX Copy

Volume Of Conductor the 3-dimensional space enclosed by a conductor material. Check FAQs

V = \frac{6 \cdot R \cdot A \cdot (P^{2}) \cdot (L)}{P loss \cdot ({V m}^{2}) \cdot ({\cos (Φ)}^{2})}

V - Volume Of Conductor?R - Resistance Underground AC?A - Area of Underground AC Wire?P - Power Transmitted?L - Length of Underground AC Wire?P_loss - Line Losses?V_m - Maximum Voltage Underground AC?Φ - Phase Difference?

Volume of Conductor Material when Resistance is Given(3 Phase 3 Wire US) Example

With values

With units

Only example

Here is how the Volume of Conductor Material when Resistance is Given(3 Phase 3 Wire US) equation looks like with Values.

Here is how the Volume of Conductor Material when Resistance is Given(3 Phase 3 Wire US) equation looks like with Units.

Here is how the Volume of Conductor Material when Resistance is Given(3 Phase 3 Wire US) equation looks like.

782.991 = \frac{6 \cdot 5 \cdot 1.28 \cdot (300^{2}) \cdot (24)}{2.67 \cdot (230^{2}) \cdot ({\cos (30)}^{2})}

782.991m³ = \frac{6 \cdot 5Ω \cdot 1.28m² \cdot ({300W}^{2}) \cdot (24m)}{2.67W \cdot ({230V}^{2}) \cdot ({\cos (30°)}^{2})}

782.991 = \frac{6 \cdot 5 \cdot 1.28 \cdot (300^{2}) \cdot (24)}{2.67 \cdot (230^{2}) \cdot ({\cos (30)}^{2})}

Tip: Use pencil ( Pencil

) icon above to edit Input Values and Units.

Calculate

Recalculate

Solution

Copy

Reset

You are here -

Home » Category

Engineering » Category

Electrical » Category

Power System » fx Volume of Conductor Material when Resistance is Given(3 Phase 3 Wire US)

Volume of Conductor Material when Resistance is Given(3 Phase 3 Wire US) Solution

Follow our step by step solution on how to calculate Volume of Conductor Material when Resistance is Given(3 Phase 3 Wire US)?

FIRST Step Consider the formula

V = \frac{6 \cdot R \cdot A \cdot (P^{2}) \cdot (L)}{P loss \cdot ({V m}^{2}) \cdot ({\cos (Φ)}^{2})}

Next Step Substitute values of Variables

∴

V = \frac{6 \cdot 5Ω \cdot 1.28m² \cdot ({300W}^{2}) \cdot (24m)}{2.67W \cdot ({230V}^{2}) \cdot ({\cos (30°)}^{2})}

Next Step Convert Units

∴

V = \frac{6 \cdot 5Ω \cdot 1.28m² \cdot ({300W}^{2}) \cdot (24m)}{2.67W \cdot ({230V}^{2}) \cdot ({\cos (0.5236rad)}^{2})}

Next Step Prepare to Evaluate

∴

V = \frac{6 \cdot 5 \cdot 1.28 \cdot (300^{2}) \cdot (24)}{2.67 \cdot (230^{2}) \cdot ({\cos (0.5236)}^{2})}

Next Step Evaluate

∴

V = 782.991015483953m³

LAST Step Rounding Answer

∴

V = 782.991m³

Volume of Conductor Material when Resistance is Given(3 Phase 3 Wire US) Formula Elements

Variables

Functions

Volume Of Conductor

Volume Of Conductor the 3-dimensional space enclosed by a conductor material.

Symbol: V

Measurement: VolumeUnit: m³

Note: Value should be greater than 0.

Formulas to find Volume Of Conductor

Resistance Underground AC

Resistance Underground AC is defined as the property of the wire or line that opposes the flow of current through it.

Symbol: R

Measurement: Electric ResistanceUnit: Ω

Note: Value can be positive or negative.

Formulas to find Resistance Underground AC

Area of Underground AC Wire

Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.

Symbol: A

Measurement: AreaUnit: m²

Note: Value can be positive or negative.

Formulas to find Area of Underground AC Wire

Power Transmitted

Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.

Symbol: P

Measurement: PowerUnit: W

Note: Value can be positive or negative.

Formulas to find Power Transmitted

Length of Underground AC Wire

Length of Underground AC Wire is the total length of the wire from one end to other end.

Symbol: L

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Length of Underground AC Wire

Line Losses

Line Losses is defined as the total losses occurring in an Underground AC line when in use.

Symbol: P_loss

Measurement: PowerUnit: W

Note: Value can be positive or negative.

Formulas to find Line Losses

Maximum Voltage Underground AC

Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.

Symbol: V_m

Measurement: Electric PotentialUnit: V

Note: Value can be positive or negative.

Formulas to find Maximum Voltage Underground AC

Phase Difference

Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.

Symbol: Φ

Measurement: AngleUnit: °

Note: Value should be greater than 0.

Formulas to find Phase Difference

cos

Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle.

Syntax: cos(Angle)

Other Formulas to find Volume Of Conductor

Go Volume of Conductor Material (3 Phase 3 Wire US)

V = 6 \cdot ρ \cdot (P^{2}) \cdot \frac{L^{2}}{P loss \cdot ({V m}^{2}) \cdot ({\cos (Φ)}^{2})}

Go Volume of Conductor Material when Area and Length is Given(3 Phase 3 Wire US)

V = 3 \cdot A \cdot L

Other formulas in Wire Parameters category

Go Area of X Section using Volume of Conductor Material (3 Phase 3 Wire US)

A = \frac{V}{(3) \cdot L}

Go Constant using Volume of Conductor Material (3 Phase 3 Wire US)

K = V \cdot \frac{{(\cos (Φ))}^{2}}{1.5}

How to Evaluate Volume of Conductor Material when Resistance is Given(3 Phase 3 Wire US)?

Volume of Conductor Material when Resistance is Given(3 Phase 3 Wire US) evaluator uses Volume Of Conductor = (6*Resistance Underground AC*Area of Underground AC Wire*(Power Transmitted^2)*(Length of Underground AC Wire))/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2)) to evaluate the Volume Of Conductor, The Volume of Conductor Material when Resistance is Given(3 phase 3 wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a three-phase three-wire earthed underground system. Volume Of Conductor is denoted by V symbol.

How to evaluate Volume of Conductor Material when Resistance is Given(3 Phase 3 Wire US) using this online evaluator? To use this online evaluator for Volume of Conductor Material when Resistance is Given(3 Phase 3 Wire US), enter Resistance Underground AC (R), Area of Underground AC Wire (A), Power Transmitted (P), Length of Underground AC Wire (L), Line Losses (P_loss), Maximum Voltage Underground AC (V_m) & Phase Difference (Φ) and hit the calculate button.

FAQs on Volume of Conductor Material when Resistance is Given(3 Phase 3 Wire US)

What is the formula to find Volume of Conductor Material when Resistance is Given(3 Phase 3 Wire US)?

The formula of Volume of Conductor Material when Resistance is Given(3 Phase 3 Wire US) is expressed as Volume Of Conductor = (6*Resistance Underground AC*Area of Underground AC Wire*(Power Transmitted^2)*(Length of Underground AC Wire))/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2)). Here is an example- 782.991 = (6*5*1.28*(300^2)*(24))/(2.67*(230^2)*(cos(0.5235987755982)^2)).

How to calculate Volume of Conductor Material when Resistance is Given(3 Phase 3 Wire US)?

With Resistance Underground AC (R), Area of Underground AC Wire (A), Power Transmitted (P), Length of Underground AC Wire (L), Line Losses (P_loss), Maximum Voltage Underground AC (V_m) & Phase Difference (Φ) we can find Volume of Conductor Material when Resistance is Given(3 Phase 3 Wire US) using the formula - Volume Of Conductor = (6*Resistance Underground AC*Area of Underground AC Wire*(Power Transmitted^2)*(Length of Underground AC Wire))/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2)). This formula also uses Cosine (cos) function(s).

What are the other ways to Calculate Volume Of Conductor?

Here are the different ways to Calculate Volume Of Conductor-

Volume Of Conductor=6*Resistivity*(Power Transmitted^2)*(Length of Underground AC Wire^2)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2))
Volume Of Conductor=3*Area of Underground AC Wire*Length of Underground AC Wire
Volume Of Conductor=Constant Underground AC*1.5/(cos(Phase Difference)^2)

Can the Volume of Conductor Material when Resistance is Given(3 Phase 3 Wire US) be negative?

No, the Volume of Conductor Material when Resistance is Given(3 Phase 3 Wire US), measured in Volume cannot be negative.

Which unit is used to measure Volume of Conductor Material when Resistance is Given(3 Phase 3 Wire US)?

Volume of Conductor Material when Resistance is Given(3 Phase 3 Wire US) is usually measured using the Cubic Meter[m³] for Volume. Cubic Centimeter[m³], Cubic Millimeter[m³], Liter[m³] are the few other units in which Volume of Conductor Material when Resistance is Given(3 Phase 3 Wire US) can be measured.

Let Others Know

✖

Facebook

Twitter

Copied!

: Value
: Unit

Volume of Conductor Material when Resistance is Given(3 Phase 3 Wire US) Formula

​GoVolume of Conductor Material (3 Phase 3 Wire US) Formula

​GoVolume of Conductor Material when Area and Length is Given(3 Phase 3 Wire US) Formula

Volume of Conductor Material when Resistance is Given(3 Phase 3 Wire US) Example

Volume of Conductor Material when Resistance is Given(3 Phase 3 Wire US) Solution

Volume of Conductor Material when Resistance is Given(3 Phase 3 Wire US) Formula Elements

Other Formulas to find Volume Of Conductor

Other formulas in Wire Parameters category

How to Evaluate Volume of Conductor Material when Resistance is Given(3 Phase 3 Wire US)?

FAQs on Volume of Conductor Material when Resistance is Given(3 Phase 3 Wire US)

Variable Name

GoVolume of Conductor Material (3 Phase 3 Wire US) Formula

GoVolume of Conductor Material when Area and Length is Given(3 Phase 3 Wire US) Formula