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Volume of Conductor Material using Resistance (DC Two-Wire US) Formula

GoVolume of Conductor Material using Area and Length(DC Two-Wire US) Formula

GoVolume of Conductor Material using Load Current (DC Two-Wire US) Formula

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Volume Of Conductor the 3-dimensional space enclosed by a conductor material. Check FAQs

V = \frac{4 \cdot (P^{2}) \cdot R 1 \cdot A \cdot l}{P line \cdot ({V m}^{2})}

V - Volume Of Conductor?P - Power Transmitted?R₁ - Resistance underground DC?A - Area of underground dc wire?l - Length of Wire DC?P_line - Line Losses?V_m - Maximum Voltage?

Volume of Conductor Material using Resistance (DC Two-Wire US) Example

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Here is how the Volume of Conductor Material using Resistance (DC Two-Wire US) equation looks like with Values.

Here is how the Volume of Conductor Material using Resistance (DC Two-Wire US) equation looks like with Units.

Here is how the Volume of Conductor Material using Resistance (DC Two-Wire US) equation looks like.

853.3333 = \frac{4 \cdot (300^{2}) \cdot 5 \cdot 0.32 \cdot 3.2}{0.6 \cdot (60^{2})}

853.3333m³ = \frac{4 \cdot ({300W}^{2}) \cdot 5Ω \cdot 0.32m² \cdot 3.2m}{0.6W \cdot ({60V}^{2})}

853.3333 = \frac{4 \cdot (300^{2}) \cdot 5 \cdot 0.32 \cdot 3.2}{0.6 \cdot (60^{2})}

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Volume of Conductor Material using Resistance (DC Two-Wire US) Solution

Follow our step by step solution on how to calculate Volume of Conductor Material using Resistance (DC Two-Wire US)?

FIRST Step Consider the formula

V = \frac{4 \cdot (P^{2}) \cdot R 1 \cdot A \cdot l}{P line \cdot ({V m}^{2})}

Next Step Substitute values of Variables

∴

V = \frac{4 \cdot ({300W}^{2}) \cdot 5Ω \cdot 0.32m² \cdot 3.2m}{0.6W \cdot ({60V}^{2})}

Next Step Prepare to Evaluate

∴

V = \frac{4 \cdot (300^{2}) \cdot 5 \cdot 0.32 \cdot 3.2}{0.6 \cdot (60^{2})}

Next Step Evaluate

∴

V = 853.333333333333m³

LAST Step Rounding Answer

∴

V = 853.3333m³

Volume of Conductor Material using Resistance (DC Two-Wire US) Formula Elements

Variables

Volume Of Conductor

Volume Of Conductor the 3-dimensional space enclosed by a conductor material.

Symbol: V

Measurement: VolumeUnit: m³

Note: Value can be positive or negative.

Formulas to find Volume Of Conductor

Power Transmitted

Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.

Symbol: P

Measurement: PowerUnit: W

Note: Value should be greater than 0.

Formulas to find Power Transmitted

Resistance underground DC

Resistance underground DC is defined as the time rate of flow of charge through a cross-sectional area.

Symbol: R₁

Measurement: Electric ResistanceUnit: Ω

Note: Value can be positive or negative.

Formulas to find Resistance underground DC

Area of underground dc wire

The Area of underground dc wire is the amount of two-dimensional space taken up by an object.

Symbol: A

Measurement: AreaUnit: m²

Note: Value can be positive or negative.

Formulas to find Area of underground dc wire

Length of Wire DC

Length of Wire DC is the measurement or extent of something from end to end.

Symbol: l

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Length of Wire DC

Line Losses

Line Losses is defined as the losses that are produced in the line.

Symbol: P_line

Measurement: PowerUnit: W

Note: Value can be positive or negative.

Formulas to find Line Losses

Maximum Voltage

Maximum Voltage the highest voltage rating for electrical devices.

Symbol: V_m

Measurement: Electric PotentialUnit: V

Note: Value can be positive or negative.

Formulas to find Maximum Voltage

Other Formulas to find Volume Of Conductor

Go Volume of Conductor Material using Area and Length(DC Two-Wire US)

V = A \cdot l \cdot 2

Go Volume of Conductor Material using Load Current (DC Two-Wire US)

V = 4 \cdot ρ \cdot (l^{2}) \cdot \frac{{C 1}^{2}}{P line}

Other formulas in Wire Parameters category

Go Length using Area of X-Section (DC Two-Wire US)

l = A \cdot P line \cdot \frac{{V m}^{2}}{2 \cdot ρ \cdot (P^{2})}

Go Length using Line Losses (DC Two-Wire US)

l = A \cdot \frac{P line}{2 \cdot ρ \cdot ({C 1}^{2})}

How to Evaluate Volume of Conductor Material using Resistance (DC Two-Wire US)?

Volume of Conductor Material using Resistance (DC Two-Wire US) evaluator uses Volume Of Conductor = (4*(Power Transmitted^2)*Resistance underground DC*Area of underground dc wire*Length of Wire DC)/(Line Losses*(Maximum Voltage^2)) to evaluate the Volume Of Conductor, The Volume of Conductor Material using Resistance (DC Two-Wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a DC Two-Wire underground system. Volume Of Conductor is denoted by V symbol.

How to evaluate Volume of Conductor Material using Resistance (DC Two-Wire US) using this online evaluator? To use this online evaluator for Volume of Conductor Material using Resistance (DC Two-Wire US), enter Power Transmitted (P), Resistance underground DC (R₁), Area of underground dc wire (A), Length of Wire DC (l), Line Losses (P_line) & Maximum Voltage (V_m) and hit the calculate button.

FAQs on Volume of Conductor Material using Resistance (DC Two-Wire US)

What is the formula to find Volume of Conductor Material using Resistance (DC Two-Wire US)?

The formula of Volume of Conductor Material using Resistance (DC Two-Wire US) is expressed as Volume Of Conductor = (4*(Power Transmitted^2)*Resistance underground DC*Area of underground dc wire*Length of Wire DC)/(Line Losses*(Maximum Voltage^2)). Here is an example- 853.3333 = (4*(300^2)*5*0.32*3.2)/(0.6*(60^2)).

How to calculate Volume of Conductor Material using Resistance (DC Two-Wire US)?

With Power Transmitted (P), Resistance underground DC (R₁), Area of underground dc wire (A), Length of Wire DC (l), Line Losses (P_line) & Maximum Voltage (V_m) we can find Volume of Conductor Material using Resistance (DC Two-Wire US) using the formula - Volume Of Conductor = (4*(Power Transmitted^2)*Resistance underground DC*Area of underground dc wire*Length of Wire DC)/(Line Losses*(Maximum Voltage^2)).

What are the other ways to Calculate Volume Of Conductor?

Here are the different ways to Calculate Volume Of Conductor-

Volume Of Conductor=Area of underground dc wire*Length of Wire DC*2
Volume Of Conductor=4*Resistivity*(Length of Wire DC^2)*(Current underground DC^2)/Line Losses
Volume Of Conductor=4*(Power Transmitted^2)*Resistivity*(Length of Wire DC^2)/(Line Losses*(Maximum Voltage^2))

Can the Volume of Conductor Material using Resistance (DC Two-Wire US) be negative?

Yes, the Volume of Conductor Material using Resistance (DC Two-Wire US), measured in Volume can be negative.

Which unit is used to measure Volume of Conductor Material using Resistance (DC Two-Wire US)?

Volume of Conductor Material using Resistance (DC Two-Wire US) is usually measured using the Cubic Meter[m³] for Volume. Cubic Centimeter[m³], Cubic Millimeter[m³], Liter[m³] are the few other units in which Volume of Conductor Material using Resistance (DC Two-Wire US) can be measured.

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Volume of Conductor Material using Resistance (DC Two-Wire US) Formula

​GoVolume of Conductor Material using Area and Length(DC Two-Wire US) Formula

​GoVolume of Conductor Material using Load Current (DC Two-Wire US) Formula

Volume of Conductor Material using Resistance (DC Two-Wire US) Example

Volume of Conductor Material using Resistance (DC Two-Wire US) Solution

Volume of Conductor Material using Resistance (DC Two-Wire US) Formula Elements

Other Formulas to find Volume Of Conductor

Other formulas in Wire Parameters category

How to Evaluate Volume of Conductor Material using Resistance (DC Two-Wire US)?

FAQs on Volume of Conductor Material using Resistance (DC Two-Wire US)

Variable Name

GoVolume of Conductor Material using Area and Length(DC Two-Wire US) Formula

GoVolume of Conductor Material using Load Current (DC Two-Wire US) Formula