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Volume of Conductor Material using Load Current (2-Phase 4-Wire OS) Formula

GoVolume of Conductor Material(2-Phase 4-Wire OS) Formula

GoVolume of Conductor Material using Area of X-Section(2-Phase 4-Wire OS) Formula

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Volume of Conductor is the total volume of the material used to make the conductor of an overhead ac line. Check FAQs

V = 16 \cdot ρ \cdot \frac{{(I \cdot L)}^{2}}{P loss}

V - Volume of Conductor?ρ - Resistivity?I - Current Overhead AC?L - Length of Overhead AC Wire?P_loss - Line Losses?

Volume of Conductor Material using Load Current (2-Phase 4-Wire OS) Example

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Here is how the Volume of Conductor Material using Load Current (2-Phase 4-Wire OS) equation looks like with Values.

Here is how the Volume of Conductor Material using Load Current (2-Phase 4-Wire OS) equation looks like with Units.

Here is how the Volume of Conductor Material using Load Current (2-Phase 4-Wire OS) equation looks like.

0.1778 = 16 \cdot 1.7E-5 \cdot \frac{{(6.9 \cdot 10.63)}^{2}}{8.23}

0.1778m³ = 16 \cdot 1.7E-5Ω*m \cdot \frac{{(6.9A \cdot 10.63m)}^{2}}{8.23W}

0.1778 = 16 \cdot 1.7E-5 \cdot \frac{{(6.9 \cdot 10.63)}^{2}}{8.23}

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Volume of Conductor Material using Load Current (2-Phase 4-Wire OS) Solution

Follow our step by step solution on how to calculate Volume of Conductor Material using Load Current (2-Phase 4-Wire OS)?

FIRST Step Consider the formula

V = 16 \cdot ρ \cdot \frac{{(I \cdot L)}^{2}}{P loss}

Next Step Substitute values of Variables

∴

V = 16 \cdot 1.7E-5Ω*m \cdot \frac{{(6.9A \cdot 10.63m)}^{2}}{8.23W}

Next Step Prepare to Evaluate

∴

V = 16 \cdot 1.7E-5 \cdot \frac{{(6.9 \cdot 10.63)}^{2}}{8.23}

Next Step Evaluate

∴

V = 0.177800828098177m³

LAST Step Rounding Answer

∴

V = 0.1778m³

Volume of Conductor Material using Load Current (2-Phase 4-Wire OS) Formula Elements

Variables

Volume of Conductor

Volume of Conductor is the total volume of the material used to make the conductor of an overhead ac line.

Symbol: V

Measurement: VolumeUnit: m³

Note: Value can be positive or negative.

Formulas to find Volume of Conductor

Resistivity

Resistivity is the measure of how strongly a material opposes the flow of current through them.

Symbol: ρ

Measurement: Electric ResistivityUnit: Ω*m

Note: Value can be positive or negative.

Formulas to find Resistivity

Current Overhead AC

Current Overhead AC is defined as the current flowing through the overhead ac supply wire.

Symbol: I

Measurement: Electric CurrentUnit: A

Note: Value can be positive or negative.

Formulas to find Current Overhead AC

Length of Overhead AC Wire

Length of Overhead AC Wire is the total length of the wire from one end to other end.

Symbol: L

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Length of Overhead AC Wire

Line Losses

Line Losses is defined as the total losses occurring in an Overhead AC line when in use.

Symbol: P_loss

Measurement: PowerUnit: W

Note: Value can be positive or negative.

Formulas to find Line Losses

Other Formulas to find Volume of Conductor

Go Volume of Conductor Material(2-Phase 4-Wire OS)

V = (4) \cdot A \cdot L

Go Volume of Conductor Material using Area of X-Section(2-Phase 4-Wire OS)

V = (4) \cdot A \cdot L

Go Volume of Conductor Material using Line Losses (2-Phase 4-Wire OS)

V = 2 \cdot ρ \cdot \frac{{(P \cdot L)}^{2}}{P loss \cdot {(V m \cdot \cos (Φ))}^{2}}

Other formulas in Wire Parameters category

Go Line Losses(2-Phase 4-Wire OS)

P loss = (4) \cdot ({(I)}^{2}) \cdot R

Go Constant(2-Phase 4-Wire OS)

K = \frac{4 \cdot (P^{2}) \cdot ρ \cdot L}{P loss \cdot ({V ac}^{2})}

Go Area of X-Section(2-Phase 4-Wire OS)

A = (P^{2}) \cdot ρ \cdot \frac{L}{({(\cos (Φ))}^{2}) \cdot P loss \cdot ({V m}^{2}) \cdot 2}

Go Line Losses using Area of X-Section(2-Phase 4-Wire OS)

P loss = \frac{L \cdot ρ \cdot (P^{2})}{2 \cdot A \cdot ({V m}^{2}) \cdot ({(\cos (Φ))}^{2})}

How to Evaluate Volume of Conductor Material using Load Current (2-Phase 4-Wire OS)?

Volume of Conductor Material using Load Current (2-Phase 4-Wire OS) evaluator uses Volume of Conductor = 16*Resistivity*(Current Overhead AC*Length of Overhead AC Wire)^2/(Line Losses) to evaluate the Volume of Conductor, The Volume of Conductor Material using Load Current (2-Phase 4-Wire OS) formula is defined as the 3-dimensional space enclosed by a conductor material of a two-phase four-wire overhead system. Volume of Conductor is denoted by V symbol.

How to evaluate Volume of Conductor Material using Load Current (2-Phase 4-Wire OS) using this online evaluator? To use this online evaluator for Volume of Conductor Material using Load Current (2-Phase 4-Wire OS), enter Resistivity (ρ), Current Overhead AC (I), Length of Overhead AC Wire (L) & Line Losses (P_loss) and hit the calculate button.

FAQs on Volume of Conductor Material using Load Current (2-Phase 4-Wire OS)

What is the formula to find Volume of Conductor Material using Load Current (2-Phase 4-Wire OS)?

The formula of Volume of Conductor Material using Load Current (2-Phase 4-Wire OS) is expressed as Volume of Conductor = 16*Resistivity*(Current Overhead AC*Length of Overhead AC Wire)^2/(Line Losses). Here is an example- 0.177801 = 16*1.7E-05*(6.9*10.63)^2/(8.23).

How to calculate Volume of Conductor Material using Load Current (2-Phase 4-Wire OS)?

With Resistivity (ρ), Current Overhead AC (I), Length of Overhead AC Wire (L) & Line Losses (P_loss) we can find Volume of Conductor Material using Load Current (2-Phase 4-Wire OS) using the formula - Volume of Conductor = 16*Resistivity*(Current Overhead AC*Length of Overhead AC Wire)^2/(Line Losses).

What are the other ways to Calculate Volume of Conductor?

Here are the different ways to Calculate Volume of Conductor-

Volume of Conductor=(4)*Area of Overhead AC Wire*Length of Overhead AC Wire
Volume of Conductor=(4)*Area of Overhead AC Wire*Length of Overhead AC Wire
Volume of Conductor=2*Resistivity*(Power Transmitted*Length of Overhead AC Wire)^2/(Line Losses*(Maximum Voltage Overhead AC*cos(Phase Difference))^2)

Can the Volume of Conductor Material using Load Current (2-Phase 4-Wire OS) be negative?

Yes, the Volume of Conductor Material using Load Current (2-Phase 4-Wire OS), measured in Volume can be negative.

Which unit is used to measure Volume of Conductor Material using Load Current (2-Phase 4-Wire OS)?

Volume of Conductor Material using Load Current (2-Phase 4-Wire OS) is usually measured using the Cubic Meter[m³] for Volume. Cubic Centimeter[m³], Cubic Millimeter[m³], Liter[m³] are the few other units in which Volume of Conductor Material using Load Current (2-Phase 4-Wire OS) can be measured.

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Volume of Conductor Material using Load Current (2-Phase 4-Wire OS) Formula

​GoVolume of Conductor Material(2-Phase 4-Wire OS) Formula

​GoVolume of Conductor Material using Area of X-Section(2-Phase 4-Wire OS) Formula

Volume of Conductor Material using Load Current (2-Phase 4-Wire OS) Example

Volume of Conductor Material using Load Current (2-Phase 4-Wire OS) Solution

Volume of Conductor Material using Load Current (2-Phase 4-Wire OS) Formula Elements

Other Formulas to find Volume of Conductor

Other formulas in Wire Parameters category

How to Evaluate Volume of Conductor Material using Load Current (2-Phase 4-Wire OS)?

FAQs on Volume of Conductor Material using Load Current (2-Phase 4-Wire OS)

Variable Name

GoVolume of Conductor Material(2-Phase 4-Wire OS) Formula

GoVolume of Conductor Material using Area of X-Section(2-Phase 4-Wire OS) Formula