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Volume of Conductor Material using Line Losses (Single-Phase Two-Wire OS) Formula

GoVolume of Conductor Material(Single-Phase Two-Wire OS) Formula

GoVolume of Conductor Material using Load Current (Single-Phase Two-Wire OS) Formula

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Volume of Conductor is the total volume of the material used to make the conductor of an overhead ac line. Check FAQs

V = \frac{8 \cdot ρ \cdot {(P \cdot L)}^{2}}{P loss \cdot {(V m \cdot \cos (Φ))}^{2}}

V - Volume of Conductor?ρ - Resistivity?P - Power Transmitted?L - Length of Overhead AC Wire?P_loss - Line Losses?V_m - Maximum Voltage Overhead AC?Φ - Phase Difference?

Volume of Conductor Material using Line Losses (Single-Phase Two-Wire OS) Example

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Here is how the Volume of Conductor Material using Line Losses (Single-Phase Two-Wire OS) equation looks like with Values.

Here is how the Volume of Conductor Material using Line Losses (Single-Phase Two-Wire OS) equation looks like with Units.

Here is how the Volume of Conductor Material using Line Losses (Single-Phase Two-Wire OS) equation looks like.

0.513 = \frac{8 \cdot 1.7E-5 \cdot {(890 \cdot 10.63)}^{2}}{8.23 \cdot {(62 \cdot \cos (30))}^{2}}

0.513m³ = \frac{8 \cdot 1.7E-5Ω*m \cdot {(890W \cdot 10.63m)}^{2}}{8.23W \cdot {(62V \cdot \cos (30°))}^{2}}

0.513 = \frac{8 \cdot 1.7E-5 \cdot {(890 \cdot 10.63)}^{2}}{8.23 \cdot {(62 \cdot \cos (30))}^{2}}

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Volume of Conductor Material using Line Losses (Single-Phase Two-Wire OS) Solution

Follow our step by step solution on how to calculate Volume of Conductor Material using Line Losses (Single-Phase Two-Wire OS)?

FIRST Step Consider the formula

V = \frac{8 \cdot ρ \cdot {(P \cdot L)}^{2}}{P loss \cdot {(V m \cdot \cos (Φ))}^{2}}

Next Step Substitute values of Variables

∴

V = \frac{8 \cdot 1.7E-5Ω*m \cdot {(890W \cdot 10.63m)}^{2}}{8.23W \cdot {(62V \cdot \cos (30°))}^{2}}

Next Step Convert Units

∴

V = \frac{8 \cdot 1.7E-5Ω*m \cdot {(890W \cdot 10.63m)}^{2}}{8.23W \cdot {(62V \cdot \cos (0.5236rad))}^{2}}

Next Step Prepare to Evaluate

∴

V = \frac{8 \cdot 1.7E-5 \cdot {(890 \cdot 10.63)}^{2}}{8.23 \cdot {(62 \cdot \cos (0.5236))}^{2}}

Next Step Evaluate

∴

V = 0.513027887138288m³

LAST Step Rounding Answer

∴

V = 0.513m³

Volume of Conductor Material using Line Losses (Single-Phase Two-Wire OS) Formula Elements

Variables

Functions

Volume of Conductor

Volume of Conductor is the total volume of the material used to make the conductor of an overhead ac line.

Symbol: V

Measurement: VolumeUnit: m³

Note: Value can be positive or negative.

Formulas to find Volume of Conductor

Resistivity

Resistivity is the measure of how strongly a material opposes the flow of current through them.

Symbol: ρ

Measurement: Electric ResistivityUnit: Ω*m

Note: Value can be positive or negative.

Formulas to find Resistivity

Power Transmitted

Power Transmitted is defined as the product of current and voltage phasor in a overhead ac line at the receiving end.

Symbol: P

Measurement: PowerUnit: W

Note: Value should be greater than 0.

Formulas to find Power Transmitted

Length of Overhead AC Wire

Length of Overhead AC Wire is the total length of the wire from one end to other end.

Symbol: L

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Length of Overhead AC Wire

Line Losses

Line Losses is defined as the total losses occurring in an Overhead AC line when in use.

Symbol: P_loss

Measurement: PowerUnit: W

Note: Value can be positive or negative.

Formulas to find Line Losses

Maximum Voltage Overhead AC

Maximum Voltage Overhead AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.

Symbol: V_m

Measurement: Electric PotentialUnit: V

Note: Value can be positive or negative.

Formulas to find Maximum Voltage Overhead AC

Phase Difference

Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.

Symbol: Φ

Measurement: AngleUnit: °

Note: Value should be greater than 0.

Formulas to find Phase Difference

cos

Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle.

Syntax: cos(Angle)

Other Formulas to find Volume of Conductor

Go Volume of Conductor Material(Single-Phase Two-Wire OS)

V = 2 \cdot A \cdot L

Go Volume of Conductor Material using Load Current (Single-Phase Two-Wire OS)

V = \frac{4 \cdot (I^{2}) \cdot ρ \cdot (L^{2})}{P loss}

Other formulas in Wire Parameters category

Go Line Losses(Single-Phase Two-Wire OS)

P loss = (2) \cdot ({(I)}^{2}) \cdot R

Go Area of X-Section(Single-Phase Two-Wire OS)

A = \frac{4 \cdot (P^{2}) \cdot ρ \cdot L}{({(\cos (Φ))}^{2}) \cdot P loss \cdot ({V ac}^{2})}

How to Evaluate Volume of Conductor Material using Line Losses (Single-Phase Two-Wire OS)?

Volume of Conductor Material using Line Losses (Single-Phase Two-Wire OS) evaluator uses Volume of Conductor = (8*Resistivity*(Power Transmitted*Length of Overhead AC Wire)^2)/(Line Losses*(Maximum Voltage Overhead AC*cos(Phase Difference))^2) to evaluate the Volume of Conductor, The Volume of Conductor Material using Line Losses (single-Phase two-Wire OS) formula is defined as the 3-dimensional space enclosed by a conductor material of a single-phase two-wire overhead system. Volume of Conductor is denoted by V symbol.

How to evaluate Volume of Conductor Material using Line Losses (Single-Phase Two-Wire OS) using this online evaluator? To use this online evaluator for Volume of Conductor Material using Line Losses (Single-Phase Two-Wire OS), enter Resistivity (ρ), Power Transmitted (P), Length of Overhead AC Wire (L), Line Losses (P_loss), Maximum Voltage Overhead AC (V_m) & Phase Difference (Φ) and hit the calculate button.

FAQs on Volume of Conductor Material using Line Losses (Single-Phase Two-Wire OS)

What is the formula to find Volume of Conductor Material using Line Losses (Single-Phase Two-Wire OS)?

The formula of Volume of Conductor Material using Line Losses (Single-Phase Two-Wire OS) is expressed as Volume of Conductor = (8*Resistivity*(Power Transmitted*Length of Overhead AC Wire)^2)/(Line Losses*(Maximum Voltage Overhead AC*cos(Phase Difference))^2). Here is an example- 0.513028 = (8*1.7E-05*(890*10.63)^2)/(8.23*(62*cos(0.5235987755982))^2).

How to calculate Volume of Conductor Material using Line Losses (Single-Phase Two-Wire OS)?

With Resistivity (ρ), Power Transmitted (P), Length of Overhead AC Wire (L), Line Losses (P_loss), Maximum Voltage Overhead AC (V_m) & Phase Difference (Φ) we can find Volume of Conductor Material using Line Losses (Single-Phase Two-Wire OS) using the formula - Volume of Conductor = (8*Resistivity*(Power Transmitted*Length of Overhead AC Wire)^2)/(Line Losses*(Maximum Voltage Overhead AC*cos(Phase Difference))^2). This formula also uses Cosine (cos) function(s).

What are the other ways to Calculate Volume of Conductor?

Here are the different ways to Calculate Volume of Conductor-

Volume of Conductor=2*Area of Overhead AC Wire*Length of Overhead AC Wire
Volume of Conductor=(4*(Current Overhead AC^2)*Resistivity*(Length of Overhead AC Wire^2))/(Line Losses)

Can the Volume of Conductor Material using Line Losses (Single-Phase Two-Wire OS) be negative?

Yes, the Volume of Conductor Material using Line Losses (Single-Phase Two-Wire OS), measured in Volume can be negative.

Which unit is used to measure Volume of Conductor Material using Line Losses (Single-Phase Two-Wire OS)?

Volume of Conductor Material using Line Losses (Single-Phase Two-Wire OS) is usually measured using the Cubic Meter[m³] for Volume. Cubic Centimeter[m³], Cubic Millimeter[m³], Liter[m³] are the few other units in which Volume of Conductor Material using Line Losses (Single-Phase Two-Wire OS) can be measured.

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Volume of Conductor Material using Line Losses (Single-Phase Two-Wire OS) Formula

​GoVolume of Conductor Material(Single-Phase Two-Wire OS) Formula

​GoVolume of Conductor Material using Load Current (Single-Phase Two-Wire OS) Formula

Volume of Conductor Material using Line Losses (Single-Phase Two-Wire OS) Example

Volume of Conductor Material using Line Losses (Single-Phase Two-Wire OS) Solution

Volume of Conductor Material using Line Losses (Single-Phase Two-Wire OS) Formula Elements

Other Formulas to find Volume of Conductor

Other formulas in Wire Parameters category

How to Evaluate Volume of Conductor Material using Line Losses (Single-Phase Two-Wire OS)?

FAQs on Volume of Conductor Material using Line Losses (Single-Phase Two-Wire OS)

Variable Name

GoVolume of Conductor Material(Single-Phase Two-Wire OS) Formula

GoVolume of Conductor Material using Load Current (Single-Phase Two-Wire OS) Formula