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Volume of Conductor Material using Constant (1-Phase 2-Wire US) Formula

GoVoltage of Conductor Material (1-Phase 2-Wire US) Formula

GoVolume of Conductor Material using Area of X-Section (1-Phase 2-Wire US) Formula

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Volume Of Conductor the 3-dimensional space enclosed by a conductor material. Check FAQs

V = 2 \cdot \frac{K}{{(\cos (Φ))}^{2}}

V - Volume Of Conductor?K - Constant Underground AC?Φ - Phase Difference?

Volume of Conductor Material using Constant (1-Phase 2-Wire US) Example

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Here is how the Volume of Conductor Material using Constant (1-Phase 2-Wire US) equation looks like with Values.

Here is how the Volume of Conductor Material using Constant (1-Phase 2-Wire US) equation looks like with Units.

Here is how the Volume of Conductor Material using Constant (1-Phase 2-Wire US) equation looks like.

2.32 = 2 \cdot \frac{0.87}{{(\cos (30))}^{2}}

2.32m³ = 2 \cdot \frac{0.87}{{(\cos (30°))}^{2}}

2.32 = 2 \cdot \frac{0.87}{{(\cos (30))}^{2}}

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Volume of Conductor Material using Constant (1-Phase 2-Wire US) Solution

Follow our step by step solution on how to calculate Volume of Conductor Material using Constant (1-Phase 2-Wire US)?

FIRST Step Consider the formula

V = 2 \cdot \frac{K}{{(\cos (Φ))}^{2}}

Next Step Substitute values of Variables

∴

V = 2 \cdot \frac{0.87}{{(\cos (30°))}^{2}}

Next Step Convert Units

∴

V = 2 \cdot \frac{0.87}{{(\cos (0.5236rad))}^{2}}

Next Step Prepare to Evaluate

∴

V = 2 \cdot \frac{0.87}{{(\cos (0.5236))}^{2}}

LAST Step Evaluate

∴

V = 2.32m³

Volume of Conductor Material using Constant (1-Phase 2-Wire US) Formula Elements

Variables

Functions

Volume Of Conductor

Volume Of Conductor the 3-dimensional space enclosed by a conductor material.

Symbol: V

Measurement: VolumeUnit: m³

Note: Value should be greater than 0.

Formulas to find Volume Of Conductor

Constant Underground AC

Constant Underground AC is defined as the constant of line of a Overhead supply system.

Symbol: K

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Formulas to find Constant Underground AC

Phase Difference

Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.

Symbol: Φ

Measurement: AngleUnit: °

Note: Value should be greater than 0.

Formulas to find Phase Difference

cos

Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle.

Syntax: cos(Angle)

Other Formulas to find Volume Of Conductor

Go Voltage of Conductor Material (1-Phase 2-Wire US)

V = 2 \cdot \frac{K}{{(\cos (Φ))}^{2}}

Go Volume of Conductor Material using Area of X-Section (1-Phase 2-Wire US)

V = A \cdot L \cdot 2

Go Volume of Conductor Material using Load Current (1-Phase 2-Wire US)

V = 4 \cdot (I^{2}) \cdot ρ \cdot \frac{L^{2}}{P loss}

Go Volume of Conductor Material using Line Losses (1-Phase 2-Wire US)

V = 8 \cdot ρ \cdot \frac{{(P \cdot L)}^{2}}{P loss \cdot {(V m \cdot \cos (Φ))}^{2}}

Other formulas in Wire Parameters category

Go Area of X-Section (1-Phase 2-Wire US)

A = (4) \cdot ρ \cdot L \cdot \frac{{(P)}^{2}}{P loss \cdot {(V m \cdot \cos (Φ))}^{2}}

Go Constant (1-Phase 2-Wire US)

K = 4 \cdot ρ \cdot \frac{{(P \cdot L)}^{2}}{P loss \cdot {(V m)}^{2}}

Go Area of X-Section using Volume of Conductor Material (1-Phase 2-Wire US)

A = \frac{V}{2 \cdot L}

Go Length using Area of X-Section (1-Phase 2-Wire US)

L = A \cdot P loss \cdot \frac{{(V m \cdot \cos (Φ))}^{2}}{4 \cdot (P^{2}) \cdot ρ}

How to Evaluate Volume of Conductor Material using Constant (1-Phase 2-Wire US)?

Volume of Conductor Material using Constant (1-Phase 2-Wire US) evaluator uses Volume Of Conductor = 2*Constant Underground AC/(cos(Phase Difference))^2 to evaluate the Volume Of Conductor, The Volume of Conductor Material using Constant (1-Phase 2-Wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a single-phase two-wire overhead system. Volume Of Conductor is denoted by V symbol.

How to evaluate Volume of Conductor Material using Constant (1-Phase 2-Wire US) using this online evaluator? To use this online evaluator for Volume of Conductor Material using Constant (1-Phase 2-Wire US), enter Constant Underground AC (K) & Phase Difference (Φ) and hit the calculate button.

FAQs on Volume of Conductor Material using Constant (1-Phase 2-Wire US)

What is the formula to find Volume of Conductor Material using Constant (1-Phase 2-Wire US)?

The formula of Volume of Conductor Material using Constant (1-Phase 2-Wire US) is expressed as Volume Of Conductor = 2*Constant Underground AC/(cos(Phase Difference))^2. Here is an example- 2.32 = 2*0.87/(cos(0.5235987755982))^2.

How to calculate Volume of Conductor Material using Constant (1-Phase 2-Wire US)?

With Constant Underground AC (K) & Phase Difference (Φ) we can find Volume of Conductor Material using Constant (1-Phase 2-Wire US) using the formula - Volume Of Conductor = 2*Constant Underground AC/(cos(Phase Difference))^2. This formula also uses Cosine function(s).

What are the other ways to Calculate Volume Of Conductor?

Here are the different ways to Calculate Volume Of Conductor-

Volume Of Conductor=2*Constant Underground AC/(cos(Phase Difference))^2
Volume Of Conductor=Area of Underground AC Wire*Length of Underground AC Wire*2
Volume Of Conductor=4*(Current Underground AC^2)*Resistivity*(Length of Underground AC Wire^2)/(Line Losses)

Can the Volume of Conductor Material using Constant (1-Phase 2-Wire US) be negative?

No, the Volume of Conductor Material using Constant (1-Phase 2-Wire US), measured in Volume cannot be negative.

Which unit is used to measure Volume of Conductor Material using Constant (1-Phase 2-Wire US)?

Volume of Conductor Material using Constant (1-Phase 2-Wire US) is usually measured using the Cubic Meter[m³] for Volume. Cubic Centimeter[m³], Cubic Millimeter[m³], Liter[m³] are the few other units in which Volume of Conductor Material using Constant (1-Phase 2-Wire US) can be measured.

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