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Volume of Conductor Material Main(2 Phase 4 Wire US) Formula

GoVolume of Conductor Material (2 Phase 4 Wire US) Formula

GoVolume of Conductor Material using Load Current (2 Phase 4 Wire US) Formula

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Volume Of Conductor the 3-dimensional space enclosed by a conductor material. Check FAQs

V = 8 \cdot (P^{2}) \cdot ρ \cdot \frac{L^{2}}{P loss \cdot ({V m}^{2}) \cdot ({\cos (Φ)}^{2})}

V - Volume Of Conductor?P - Power Transmitted?ρ - Resistivity?L - Length of Underground AC Wire?P_loss - Line Losses?V_m - Maximum Voltage Underground AC?Φ - Phase Difference?

Volume of Conductor Material Main(2 Phase 4 Wire US) Example

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Here is how the Volume of Conductor Material Main(2 Phase 4 Wire US) equation looks like with Values.

Here is how the Volume of Conductor Material Main(2 Phase 4 Wire US) equation looks like with Units.

Here is how the Volume of Conductor Material Main(2 Phase 4 Wire US) equation looks like.

0.0666 = 8 \cdot (300^{2}) \cdot 1.7E-5 \cdot \frac{24^{2}}{2.67 \cdot (230^{2}) \cdot ({\cos (30)}^{2})}

0.0666m³ = 8 \cdot ({300W}^{2}) \cdot 1.7E-5Ω*m \cdot \frac{{24m}^{2}}{2.67W \cdot ({230V}^{2}) \cdot ({\cos (30°)}^{2})}

0.0666 = 8 \cdot (300^{2}) \cdot 1.7E-5 \cdot \frac{24^{2}}{2.67 \cdot (230^{2}) \cdot ({\cos (30)}^{2})}

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Volume of Conductor Material Main(2 Phase 4 Wire US) Solution

Follow our step by step solution on how to calculate Volume of Conductor Material Main(2 Phase 4 Wire US)?

FIRST Step Consider the formula

V = 8 \cdot (P^{2}) \cdot ρ \cdot \frac{L^{2}}{P loss \cdot ({V m}^{2}) \cdot ({\cos (Φ)}^{2})}

Next Step Substitute values of Variables

∴

V = 8 \cdot ({300W}^{2}) \cdot 1.7E-5Ω*m \cdot \frac{{24m}^{2}}{2.67W \cdot ({230V}^{2}) \cdot ({\cos (30°)}^{2})}

Next Step Convert Units

∴

V = 8 \cdot ({300W}^{2}) \cdot 1.7E-5Ω*m \cdot \frac{{24m}^{2}}{2.67W \cdot ({230V}^{2}) \cdot ({\cos (0.5236rad)}^{2})}

Next Step Prepare to Evaluate

∴

V = 8 \cdot (300^{2}) \cdot 1.7E-5 \cdot \frac{24^{2}}{2.67 \cdot (230^{2}) \cdot ({\cos (0.5236)}^{2})}

Next Step Evaluate

∴

V = 0.066554236316136m³

LAST Step Rounding Answer

∴

V = 0.0666m³

Volume of Conductor Material Main(2 Phase 4 Wire US) Formula Elements

Variables

Functions

Volume Of Conductor

Volume Of Conductor the 3-dimensional space enclosed by a conductor material.

Symbol: V

Measurement: VolumeUnit: m³

Note: Value should be greater than 0.

Formulas to find Volume Of Conductor

Power Transmitted

Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.

Symbol: P

Measurement: PowerUnit: W

Note: Value can be positive or negative.

Formulas to find Power Transmitted

Resistivity

Resistivity is the measure of how strongly a material opposes the flow of current through them.

Symbol: ρ

Measurement: Electric ResistivityUnit: Ω*m

Note: Value can be positive or negative.

Formulas to find Resistivity

Length of Underground AC Wire

Length of Underground AC Wire is the total length of the wire from one end to other end.

Symbol: L

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Length of Underground AC Wire

Line Losses

Line Losses is defined as the total losses occurring in an Underground AC line when in use.

Symbol: P_loss

Measurement: PowerUnit: W

Note: Value can be positive or negative.

Formulas to find Line Losses

Maximum Voltage Underground AC

Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.

Symbol: V_m

Measurement: Electric PotentialUnit: V

Note: Value can be positive or negative.

Formulas to find Maximum Voltage Underground AC

Phase Difference

Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.

Symbol: Φ

Measurement: AngleUnit: °

Note: Value should be greater than 0.

Formulas to find Phase Difference

cos

Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle.

Syntax: cos(Angle)

Other Formulas to find Volume Of Conductor

Go Volume of Conductor Material (2 Phase 4 Wire US)

V = 2 \cdot A \cdot L

Go Volume of Conductor Material using Load Current (2 Phase 4 Wire US)

V = {(I \cdot L)}^{2} \cdot 4 \cdot \frac{ρ}{P loss}

Other formulas in Wire Parameters category

Go Line Losses using Area of X-Section (2 Phase 4 Wire US)

P loss = 4 \cdot ρ \cdot L \cdot \frac{P^{2}}{A \cdot ({V m}^{2}) \cdot ({\cos (Φ)}^{2})}

Go Line Losses (2 Phase 4 Wire US)

P loss = 2 \cdot (I^{2}) \cdot R

How to Evaluate Volume of Conductor Material Main(2 Phase 4 Wire US)?

Volume of Conductor Material Main(2 Phase 4 Wire US) evaluator uses Volume Of Conductor = 8*(Power Transmitted^2)*Resistivity*(Length of Underground AC Wire^2)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2)) to evaluate the Volume Of Conductor, The Volume of Conductor Material Main(2 phase 4 wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a 2-phase 4-wire underground system. Volume Of Conductor is denoted by V symbol.

How to evaluate Volume of Conductor Material Main(2 Phase 4 Wire US) using this online evaluator? To use this online evaluator for Volume of Conductor Material Main(2 Phase 4 Wire US), enter Power Transmitted (P), Resistivity (ρ), Length of Underground AC Wire (L), Line Losses (P_loss), Maximum Voltage Underground AC (V_m) & Phase Difference (Φ) and hit the calculate button.

FAQs on Volume of Conductor Material Main(2 Phase 4 Wire US)

What is the formula to find Volume of Conductor Material Main(2 Phase 4 Wire US)?

The formula of Volume of Conductor Material Main(2 Phase 4 Wire US) is expressed as Volume Of Conductor = 8*(Power Transmitted^2)*Resistivity*(Length of Underground AC Wire^2)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2)). Here is an example- 0.066554 = 8*(300^2)*1.7E-05*(24^2)/(2.67*(230^2)*(cos(0.5235987755982)^2)).

How to calculate Volume of Conductor Material Main(2 Phase 4 Wire US)?

With Power Transmitted (P), Resistivity (ρ), Length of Underground AC Wire (L), Line Losses (P_loss), Maximum Voltage Underground AC (V_m) & Phase Difference (Φ) we can find Volume of Conductor Material Main(2 Phase 4 Wire US) using the formula - Volume Of Conductor = 8*(Power Transmitted^2)*Resistivity*(Length of Underground AC Wire^2)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2)). This formula also uses Cosine function(s).

What are the other ways to Calculate Volume Of Conductor?

Here are the different ways to Calculate Volume Of Conductor-

Volume Of Conductor=2*Area of Underground AC Wire*Length of Underground AC Wire
Volume Of Conductor=(Current Underground AC*Length of Underground AC Wire)^2*4*Resistivity/Line Losses
Volume Of Conductor=2*Constant Underground AC/(cos(Phase Difference)^2)

Can the Volume of Conductor Material Main(2 Phase 4 Wire US) be negative?

No, the Volume of Conductor Material Main(2 Phase 4 Wire US), measured in Volume cannot be negative.

Which unit is used to measure Volume of Conductor Material Main(2 Phase 4 Wire US)?

Volume of Conductor Material Main(2 Phase 4 Wire US) is usually measured using the Cubic Meter[m³] for Volume. Cubic Centimeter[m³], Cubic Millimeter[m³], Liter[m³] are the few other units in which Volume of Conductor Material Main(2 Phase 4 Wire US) can be measured.

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Volume of Conductor Material Main(2 Phase 4 Wire US) Formula

​GoVolume of Conductor Material (2 Phase 4 Wire US) Formula

​GoVolume of Conductor Material using Load Current (2 Phase 4 Wire US) Formula

Volume of Conductor Material Main(2 Phase 4 Wire US) Example

Volume of Conductor Material Main(2 Phase 4 Wire US) Solution

Volume of Conductor Material Main(2 Phase 4 Wire US) Formula Elements

Other Formulas to find Volume Of Conductor

Other formulas in Wire Parameters category

How to Evaluate Volume of Conductor Material Main(2 Phase 4 Wire US)?

FAQs on Volume of Conductor Material Main(2 Phase 4 Wire US)

Variable Name

GoVolume of Conductor Material (2 Phase 4 Wire US) Formula

GoVolume of Conductor Material using Load Current (2 Phase 4 Wire US) Formula