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Volume of Conductor Material (2-Wire Mid-Point DC US) Formula

GoVolume of Conductor Material using Area and Length (2-Wire Mid-Point DC US) Formula

GoVolume of Conductor Material using Load Current (2-Wire Mid-Point DC US) Formula

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Volume Of Conductor the 3-dimensional space enclosed by a conductor material. Check FAQs

V = 4 \cdot ρ \cdot (P^{2}) \cdot \frac{l^{2}}{P line \cdot ({V m}^{2})}

V - Volume Of Conductor?ρ - Resistivity?P - Power Transmitted?l - Length of Wire DC?P_line - Line Losses?V_m - Maximum Voltage?

Volume of Conductor Material (2-Wire Mid-Point DC US) Example

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Here is how the Volume of Conductor Material (2-Wire Mid-Point DC US) equation looks like with Values.

Here is how the Volume of Conductor Material (2-Wire Mid-Point DC US) equation looks like with Units.

Here is how the Volume of Conductor Material (2-Wire Mid-Point DC US) equation looks like.

0.029 = 4 \cdot 1.7E-5 \cdot (300^{2}) \cdot \frac{{3.2}^{2}}{0.6 \cdot (60^{2})}

0.029m³ = 4 \cdot 1.7E-5Ω*m \cdot ({300W}^{2}) \cdot \frac{{3.2m}^{2}}{0.6W \cdot ({60V}^{2})}

0.029 = 4 \cdot 1.7E-5 \cdot (300^{2}) \cdot \frac{{3.2}^{2}}{0.6 \cdot (60^{2})}

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Volume of Conductor Material (2-Wire Mid-Point DC US) Solution

Follow our step by step solution on how to calculate Volume of Conductor Material (2-Wire Mid-Point DC US)?

FIRST Step Consider the formula

V = 4 \cdot ρ \cdot (P^{2}) \cdot \frac{l^{2}}{P line \cdot ({V m}^{2})}

Next Step Substitute values of Variables

∴

V = 4 \cdot 1.7E-5Ω*m \cdot ({300W}^{2}) \cdot \frac{{3.2m}^{2}}{0.6W \cdot ({60V}^{2})}

Next Step Prepare to Evaluate

∴

V = 4 \cdot 1.7E-5 \cdot (300^{2}) \cdot \frac{{3.2}^{2}}{0.6 \cdot (60^{2})}

Next Step Evaluate

∴

V = 0.0290133333333333m³

LAST Step Rounding Answer

∴

V = 0.029m³

Volume of Conductor Material (2-Wire Mid-Point DC US) Formula Elements

Variables

Volume Of Conductor

Volume Of Conductor the 3-dimensional space enclosed by a conductor material.

Symbol: V

Measurement: VolumeUnit: m³

Note: Value can be positive or negative.

Formulas to find Volume Of Conductor

Resistivity

Resistivity is the measure of how strongly a material opposes the flow of current through them.

Symbol: ρ

Measurement: Electric ResistivityUnit: Ω*m

Note: Value can be positive or negative.

Formulas to find Resistivity

Power Transmitted

Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.

Symbol: P

Measurement: PowerUnit: W

Note: Value should be greater than 0.

Formulas to find Power Transmitted

Length of Wire DC

Length of Wire DC is the measurement or extent of something from end to end.

Symbol: l

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Length of Wire DC

Line Losses

Line Losses is defined as the losses that are produced in the line.

Symbol: P_line

Measurement: PowerUnit: W

Note: Value can be positive or negative.

Formulas to find Line Losses

Maximum Voltage

Maximum Voltage the highest voltage rating for electrical devices.

Symbol: V_m

Measurement: Electric PotentialUnit: V

Note: Value can be positive or negative.

Formulas to find Maximum Voltage

Other Formulas to find Volume Of Conductor

Go Volume of Conductor Material using Area and Length (2-Wire Mid-Point DC US)

V = 2 \cdot A \cdot l

Go Volume of Conductor Material using Load Current (2-Wire Mid-Point DC US)

V = 4 \cdot ρ \cdot ({C 1}^{2}) \cdot \frac{l^{2}}{P line}

Go Volume of Conductor Material using Resistance (2-Wire Mid-Point DC US)

V = \frac{4 \cdot A \cdot R 1 \cdot (P^{2}) \cdot (l)}{P line \cdot ({V m}^{2})}

Other formulas in Wire Parameters category

Go Line Losses using Area of X-Section (2-Wire Mid-Point Earthed DC US)

P line = \frac{2 \cdot ρ \cdot l \cdot (P^{2})}{A \cdot ({V m}^{2} \cdot {\cos (θ)}^{2})}

Go Line Losses using Volume of Conductor Material (2-Wire Mid-Point DC US)

P line = 4 \cdot ρ \cdot \frac{P^{2} \cdot l^{2}}{{V m}^{2} \cdot V}

Go Length using Area of X-Section (2-Wire Mid-Point Earthed DC US)

l = A \cdot P line \cdot \frac{{V m}^{2}}{2 \cdot (P^{2}) \cdot ρ}

Go Length using Volume of Conductor Material (2-Wire Mid-Point DC US)

l = \sqrt{\frac{V \cdot P line}{4 \cdot ({C 1}^{2}) \cdot (ρ)}}

How to Evaluate Volume of Conductor Material (2-Wire Mid-Point DC US)?

Volume of Conductor Material (2-Wire Mid-Point DC US) evaluator uses Volume Of Conductor = 4*Resistivity*(Power Transmitted^2)*(Length of Wire DC^2)/(Line Losses*(Maximum Voltage^2)) to evaluate the Volume Of Conductor, The Volume of Conductor Material (2-wire Mid-point DC US) formula is defined as the 3-dimensional space enclosed by a conductor material of a DC two-wire mid-point underground system. Volume Of Conductor is denoted by V symbol.

How to evaluate Volume of Conductor Material (2-Wire Mid-Point DC US) using this online evaluator? To use this online evaluator for Volume of Conductor Material (2-Wire Mid-Point DC US), enter Resistivity (ρ), Power Transmitted (P), Length of Wire DC (l), Line Losses (P_line) & Maximum Voltage (V_m) and hit the calculate button.

FAQs on Volume of Conductor Material (2-Wire Mid-Point DC US)

What is the formula to find Volume of Conductor Material (2-Wire Mid-Point DC US)?

The formula of Volume of Conductor Material (2-Wire Mid-Point DC US) is expressed as Volume Of Conductor = 4*Resistivity*(Power Transmitted^2)*(Length of Wire DC^2)/(Line Losses*(Maximum Voltage^2)). Here is an example- 0.029013 = 4*1.7E-05*(300^2)*(3.2^2)/(0.6*(60^2)).

How to calculate Volume of Conductor Material (2-Wire Mid-Point DC US)?

With Resistivity (ρ), Power Transmitted (P), Length of Wire DC (l), Line Losses (P_line) & Maximum Voltage (V_m) we can find Volume of Conductor Material (2-Wire Mid-Point DC US) using the formula - Volume Of Conductor = 4*Resistivity*(Power Transmitted^2)*(Length of Wire DC^2)/(Line Losses*(Maximum Voltage^2)).

What are the other ways to Calculate Volume Of Conductor?

Here are the different ways to Calculate Volume Of Conductor-

Volume Of Conductor=2*Area of underground dc wire*Length of Wire DC
Volume Of Conductor=4*Resistivity*(Current underground DC^2)*(Length of Wire DC^2)/(Line Losses)
Volume Of Conductor=(4*Area of underground dc wire*Resistance underground DC*(Power Transmitted^2)*(Length of Wire DC))/(Line Losses*(Maximum Voltage^2))

Can the Volume of Conductor Material (2-Wire Mid-Point DC US) be negative?

Yes, the Volume of Conductor Material (2-Wire Mid-Point DC US), measured in Volume can be negative.

Which unit is used to measure Volume of Conductor Material (2-Wire Mid-Point DC US)?

Volume of Conductor Material (2-Wire Mid-Point DC US) is usually measured using the Cubic Meter[m³] for Volume. Cubic Centimeter[m³], Cubic Millimeter[m³], Liter[m³] are the few other units in which Volume of Conductor Material (2-Wire Mid-Point DC US) can be measured.

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Volume of Conductor Material (2-Wire Mid-Point DC US) Formula

​GoVolume of Conductor Material using Area and Length (2-Wire Mid-Point DC US) Formula

​GoVolume of Conductor Material using Load Current (2-Wire Mid-Point DC US) Formula

Volume of Conductor Material (2-Wire Mid-Point DC US) Example

Volume of Conductor Material (2-Wire Mid-Point DC US) Solution

Volume of Conductor Material (2-Wire Mid-Point DC US) Formula Elements

Other Formulas to find Volume Of Conductor

Other formulas in Wire Parameters category

How to Evaluate Volume of Conductor Material (2-Wire Mid-Point DC US)?

FAQs on Volume of Conductor Material (2-Wire Mid-Point DC US)

Variable Name

GoVolume of Conductor Material using Area and Length (2-Wire Mid-Point DC US) Formula

GoVolume of Conductor Material using Load Current (2-Wire Mid-Point DC US) Formula