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Voltage of Moving Iron Voltmeter Formula

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Voltage is a measure of the potential energy per unit charge between two points in an electrical circuit. It represents the force that drives electric charges to move in a circuit. Check FAQs

V = I m \cdot \sqrt{{(R i_m + R S)}^{2} + {(ω \cdot L)}^{2}}

V - Voltage?I_m - Meter Current?R_{i_m} - Meter Internal Resistance?R_S - Series Resistance?ω - Angular Frequency?L - Inductance?

Voltage of Moving Iron Voltmeter Example

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Here is how the Voltage of Moving Iron Voltmeter equation looks like with Values.

Here is how the Voltage of Moving Iron Voltmeter equation looks like with Units.

Here is how the Voltage of Moving Iron Voltmeter equation looks like.

6.5849 = 0.22 \cdot \sqrt{{(5.5 + 24)}^{2} + {(1.12 \cdot 4.52)}^{2}}

6.5849V = 0.22A \cdot \sqrt{{(5.5Ω + 24Ω)}^{2} + {(1.12rad/s \cdot 4.52H)}^{2}}

6.5849 = 0.22 \cdot \sqrt{{(5.5 + 24)}^{2} + {(1.12 \cdot 4.52)}^{2}}

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Voltage of Moving Iron Voltmeter Solution

Follow our step by step solution on how to calculate Voltage of Moving Iron Voltmeter?

FIRST Step Consider the formula

V = I m \cdot \sqrt{{(R i_m + R S)}^{2} + {(ω \cdot L)}^{2}}

Next Step Substitute values of Variables

∴

V = 0.22A \cdot \sqrt{{(5.5Ω + 24Ω)}^{2} + {(1.12rad/s \cdot 4.52H)}^{2}}

Next Step Prepare to Evaluate

∴

V = 0.22 \cdot \sqrt{{(5.5 + 24)}^{2} + {(1.12 \cdot 4.52)}^{2}}

Next Step Evaluate

∴

V = 6.58486826428472V

LAST Step Rounding Answer

∴

V = 6.5849V

Voltage of Moving Iron Voltmeter Formula Elements

Variables

Functions

Voltage

Voltage is a measure of the potential energy per unit charge between two points in an electrical circuit. It represents the force that drives electric charges to move in a circuit.

Symbol: V

Measurement: Electric PotentialUnit: V

Note: Value should be greater than 0.

Formulas to find Voltage

Meter Current

Meter Current refers to the current flowing through a measuring instrument having some inherent internal resistance.

Symbol: I_m

Measurement: Electric CurrentUnit: A

Note: Value should be greater than 0.

Formulas to find Meter Current

Meter Internal Resistance

Meter Internal Resistance refers to the inherent resistance present within a measuring instrument.

Symbol: R_{i_m}

Measurement: Electric ResistanceUnit: Ω

Note: Value should be greater than 0.

Formulas to find Meter Internal Resistance

Series Resistance

Series Resistance is the value of series resistance attached to the pmmc-based voltmeter.

Symbol: R_S

Measurement: Electric ResistanceUnit: Ω

Note: Value should be greater than 0.

Formulas to find Series Resistance

Angular Frequency

Angular frequency is a measure of how quickly an object rotates or oscillates. It indicates the rate of change of the phase of a sinusoidal waveform.

Symbol: ω

Measurement: Angular VelocityUnit: rad/s

Note: Value should be greater than 0.

Formulas to find Angular Frequency

Inductance

Inductance is defined as the ability of a circuit element to store energy in the form of a magnetic field when current flows through it.

Symbol: L

Measurement: InductanceUnit: H

Note: Value should be greater than 0.

Formulas to find Inductance

sqrt

A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number.

Syntax: sqrt(Number)

Other formulas in Voltmeter Specifications category

Go Voltage Multiplying Power of Moving Iron Voltmeter

m = \sqrt{\frac{{(R i_m + R S)}^{2} + {(ω \cdot L)}^{2}}{{(R i_m)}^{2} + {(ω \cdot L)}^{2}}}

Go Deflecting Torque of Electrodynamometer Voltmeter

T = {(\frac{V t}{Z})}^{2} \cdot dM|dθ \cdot \cos (ϕ)

Go Deflection Angle of Electrodynamometer Voltmeter

θ = \frac{{V t}^{2} \cdot dM|dθ \cdot \cos (ϕ)}{k \cdot Z^{2}}

Go Additional Capacitance

C a = C self + C v

How to Evaluate Voltage of Moving Iron Voltmeter?

Voltage of Moving Iron Voltmeter evaluator uses Voltage = Meter Current*sqrt((Meter Internal Resistance+Series Resistance)^2+(Angular Frequency*Inductance)^2) to evaluate the Voltage, The Voltage of Moving Iron Voltmeter gives the measurement of the voltage across the meter, which has an internal resistance and inductance. Voltage is denoted by V symbol.

How to evaluate Voltage of Moving Iron Voltmeter using this online evaluator? To use this online evaluator for Voltage of Moving Iron Voltmeter, enter Meter Current (I_m), Meter Internal Resistance (R_{i_m}), Series Resistance (R_S), Angular Frequency (ω) & Inductance (L) and hit the calculate button.

FAQs on Voltage of Moving Iron Voltmeter

What is the formula to find Voltage of Moving Iron Voltmeter?

The formula of Voltage of Moving Iron Voltmeter is expressed as Voltage = Meter Current*sqrt((Meter Internal Resistance+Series Resistance)^2+(Angular Frequency*Inductance)^2). Here is an example- 10.17661 = 0.22*sqrt((5.5+24)^2+(1.12*4.52)^2).

How to calculate Voltage of Moving Iron Voltmeter?

With Meter Current (I_m), Meter Internal Resistance (R_{i_m}), Series Resistance (R_S), Angular Frequency (ω) & Inductance (L) we can find Voltage of Moving Iron Voltmeter using the formula - Voltage = Meter Current*sqrt((Meter Internal Resistance+Series Resistance)^2+(Angular Frequency*Inductance)^2). This formula also uses Square Root (sqrt) function(s).

Can the Voltage of Moving Iron Voltmeter be negative?

No, the Voltage of Moving Iron Voltmeter, measured in Electric Potential cannot be negative.

Which unit is used to measure Voltage of Moving Iron Voltmeter?

Voltage of Moving Iron Voltmeter is usually measured using the Volt[V] for Electric Potential. Millivolt[V], Microvolt[V], Nanovolt[V] are the few other units in which Voltage of Moving Iron Voltmeter can be measured.

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Voltage of Moving Iron Voltmeter Formula

Voltage of Moving Iron Voltmeter Example

Voltage of Moving Iron Voltmeter Solution

Voltage of Moving Iron Voltmeter Formula Elements

Other formulas in Voltmeter Specifications category

How to Evaluate Voltage of Moving Iron Voltmeter?

FAQs on Voltage of Moving Iron Voltmeter

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