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Voltage of Conductor Material (1-Phase 2-Wire US) Formula

GoVolume of Conductor Material using Area of X-Section (1-Phase 2-Wire US) Formula

GoVolume of Conductor Material using Load Current (1-Phase 2-Wire US) Formula

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Volume Of Conductor the 3-dimensional space enclosed by a conductor material. Check FAQs

V = 2 \cdot \frac{K}{{(\cos (Φ))}^{2}}

V - Volume Of Conductor?K - Constant Underground AC?Φ - Phase Difference?

Voltage of Conductor Material (1-Phase 2-Wire US) Example

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Here is how the Voltage of Conductor Material (1-Phase 2-Wire US) equation looks like with Values.

Here is how the Voltage of Conductor Material (1-Phase 2-Wire US) equation looks like with Units.

Here is how the Voltage of Conductor Material (1-Phase 2-Wire US) equation looks like.

2.32 = 2 \cdot \frac{0.87}{{(\cos (30))}^{2}}

2.32m³ = 2 \cdot \frac{0.87}{{(\cos (30°))}^{2}}

2.32 = 2 \cdot \frac{0.87}{{(\cos (30))}^{2}}

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Voltage of Conductor Material (1-Phase 2-Wire US) Solution

Follow our step by step solution on how to calculate Voltage of Conductor Material (1-Phase 2-Wire US)?

FIRST Step Consider the formula

V = 2 \cdot \frac{K}{{(\cos (Φ))}^{2}}

Next Step Substitute values of Variables

∴

V = 2 \cdot \frac{0.87}{{(\cos (30°))}^{2}}

Next Step Convert Units

∴

V = 2 \cdot \frac{0.87}{{(\cos (0.5236rad))}^{2}}

Next Step Prepare to Evaluate

∴

V = 2 \cdot \frac{0.87}{{(\cos (0.5236))}^{2}}

LAST Step Evaluate

∴

V = 2.32m³

Voltage of Conductor Material (1-Phase 2-Wire US) Formula Elements

Variables

Functions

Volume Of Conductor

Volume Of Conductor the 3-dimensional space enclosed by a conductor material.

Symbol: V

Measurement: VolumeUnit: m³

Note: Value should be greater than 0.

Formulas to find Volume Of Conductor

Constant Underground AC

Constant Underground AC is defined as the constant of line of a Overhead supply system.

Symbol: K

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Formulas to find Constant Underground AC

Phase Difference

Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.

Symbol: Φ

Measurement: AngleUnit: °

Note: Value should be greater than 0.

Formulas to find Phase Difference

cos

Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle.

Syntax: cos(Angle)

Other Formulas to find Volume Of Conductor

Go Volume of Conductor Material using Area of X-Section (1-Phase 2-Wire US)

V = A \cdot L \cdot 2

Go Volume of Conductor Material using Load Current (1-Phase 2-Wire US)

V = 4 \cdot (I^{2}) \cdot ρ \cdot \frac{L^{2}}{P loss}

Go Volume of Conductor Material using Line Losses (1-Phase 2-Wire US)

V = 8 \cdot ρ \cdot \frac{{(P \cdot L)}^{2}}{P loss \cdot {(V m \cdot \cos (Φ))}^{2}}

Go Volume of Conductor Material using Constant (1-Phase 2-Wire US)

V = 2 \cdot \frac{K}{{(\cos (Φ))}^{2}}

Other formulas in Wire Parameters category

Go Area of X-Section (1-Phase 2-Wire US)

A = (4) \cdot ρ \cdot L \cdot \frac{{(P)}^{2}}{P loss \cdot {(V m \cdot \cos (Φ))}^{2}}

Go Constant (1-Phase 2-Wire US)

K = 4 \cdot ρ \cdot \frac{{(P \cdot L)}^{2}}{P loss \cdot {(V m)}^{2}}

Go Area of X-Section using Volume of Conductor Material (1-Phase 2-Wire US)

A = \frac{V}{2 \cdot L}

Go Length using Area of X-Section (1-Phase 2-Wire US)

L = A \cdot P loss \cdot \frac{{(V m \cdot \cos (Φ))}^{2}}{4 \cdot (P^{2}) \cdot ρ}

How to Evaluate Voltage of Conductor Material (1-Phase 2-Wire US)?

Voltage of Conductor Material (1-Phase 2-Wire US) evaluator uses Volume Of Conductor = 2*Constant Underground AC/(cos(Phase Difference))^2 to evaluate the Volume Of Conductor, The Voltage of Conductor Material (1-Phase 2-Wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a single-phase two-wire overhead system. Volume Of Conductor is denoted by V symbol.

How to evaluate Voltage of Conductor Material (1-Phase 2-Wire US) using this online evaluator? To use this online evaluator for Voltage of Conductor Material (1-Phase 2-Wire US), enter Constant Underground AC (K) & Phase Difference (Φ) and hit the calculate button.

FAQs on Voltage of Conductor Material (1-Phase 2-Wire US)

What is the formula to find Voltage of Conductor Material (1-Phase 2-Wire US)?

The formula of Voltage of Conductor Material (1-Phase 2-Wire US) is expressed as Volume Of Conductor = 2*Constant Underground AC/(cos(Phase Difference))^2. Here is an example- 2.32 = 2*0.87/(cos(0.5235987755982))^2.

How to calculate Voltage of Conductor Material (1-Phase 2-Wire US)?

With Constant Underground AC (K) & Phase Difference (Φ) we can find Voltage of Conductor Material (1-Phase 2-Wire US) using the formula - Volume Of Conductor = 2*Constant Underground AC/(cos(Phase Difference))^2. This formula also uses Cosine (cos) function(s).

What are the other ways to Calculate Volume Of Conductor?

Here are the different ways to Calculate Volume Of Conductor-

Volume Of Conductor=Area of Underground AC Wire*Length of Underground AC Wire*2
Volume Of Conductor=4*(Current Underground AC^2)*Resistivity*(Length of Underground AC Wire^2)/(Line Losses)
Volume Of Conductor=8*Resistivity*(Power Transmitted*Length of Underground AC Wire)^2/(Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2)

Can the Voltage of Conductor Material (1-Phase 2-Wire US) be negative?

No, the Voltage of Conductor Material (1-Phase 2-Wire US), measured in Volume cannot be negative.

Which unit is used to measure Voltage of Conductor Material (1-Phase 2-Wire US)?

Voltage of Conductor Material (1-Phase 2-Wire US) is usually measured using the Cubic Meter[m³] for Volume. Cubic Centimeter[m³], Cubic Millimeter[m³], Liter[m³] are the few other units in which Voltage of Conductor Material (1-Phase 2-Wire US) can be measured.

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