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Ultimate BOD given Oxygen Required in Aeration Tank Formula

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Ultimate BOD given Oxygen Required is represents the total amount of oxygen consumed by microorganisms during the biochemical oxidation of organic matter in a water sample. Check FAQs

BOD uo = \frac{BOD5}{Q s \cdot (Q i - Q)} / (O 2 + (1.42 \cdot Q w \cdot X R))

BOD_uo - Ultimate BOD given Oxygen Required?BOD5 - 5 Days BOD?Q_s - Sewage Discharge?Q_i - Influent BOD?Q - Effluent BOD?O₂ - Theoretical Oxygen Requirement?Q_w - Volume of Wasted Sludge per day?X^R - MLSS in Returned or Wasted Sludge?

Ultimate BOD given Oxygen Required in Aeration Tank Example

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Here is how the Ultimate BOD given Oxygen Required in Aeration Tank equation looks like with Values.

Here is how the Ultimate BOD given Oxygen Required in Aeration Tank equation looks like with Units.

Here is how the Ultimate BOD given Oxygen Required in Aeration Tank equation looks like.

0.0006 = \frac{1.36}{10 \cdot (13.2 - 0.4)} / (2.5 + (1.42 \cdot 9.5 \cdot 1.4))

0.0006mg/L = \frac{1.36mg/L}{10m³/s \cdot (13.2mg/L - 0.4mg/L)} / (2.5mg/d + (1.42 \cdot 9.5m³/s \cdot 1.4mg/L))

0.0006 = \frac{1.36}{10 \cdot (13.2 - 0.4)} / (2.5 + (1.42 \cdot 9.5 \cdot 1.4))

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Ultimate BOD given Oxygen Required in Aeration Tank Solution

Follow our step by step solution on how to calculate Ultimate BOD given Oxygen Required in Aeration Tank?

FIRST Step Consider the formula

BOD uo = \frac{BOD5}{Q s \cdot (Q i - Q)} / (O 2 + (1.42 \cdot Q w \cdot X R))

Next Step Substitute values of Variables

∴

BOD uo = \frac{1.36mg/L}{10m³/s \cdot (13.2mg/L - 0.4mg/L)} / (2.5mg/d + (1.42 \cdot 9.5m³/s \cdot 1.4mg/L))

Next Step Convert Units

∴

BOD uo = \frac{1.36mg/L}{10m³/s \cdot (13.2mg/L - 0.4mg/L)} / (2.9E-11kg/s + (1.42 \cdot 9.5m³/s \cdot 1.4mg/L))

Next Step Prepare to Evaluate

∴

BOD uo = \frac{1.36}{10 \cdot (13.2 - 0.4)} / (2.9E-11 + (1.42 \cdot 9.5 \cdot 1.4))

Next Step Evaluate

∴

BOD uo = 5.62586042570355E-07kg/m³

Next Step Convert to Output's Unit

∴

BOD uo = 0.000562586042570355mg/L

LAST Step Rounding Answer

∴

BOD uo = 0.0006mg/L

Ultimate BOD given Oxygen Required in Aeration Tank Formula Elements

Variables

Ultimate BOD given Oxygen Required

Ultimate BOD given Oxygen Required is represents the total amount of oxygen consumed by microorganisms during the biochemical oxidation of organic matter in a water sample.

Symbol: BOD_uo

Measurement: DensityUnit: mg/L

Note: Value should be greater than 0.

Formulas to find Ultimate BOD given Oxygen Required

5 Days BOD

5 Days BOD is an indicator of how much oxygen is utilized by a natural water sample in five days at 20 degrees C.

Symbol: BOD5

Measurement: DensityUnit: mg/L

Note: Value should be greater than 0.

Formulas to find 5 Days BOD

Sewage Discharge

Sewage Discharge is the flow rate of sewage when it is being discharged in the river.

Symbol: Q_s

Measurement: Volumetric Flow RateUnit: m³/s

Note: Value should be greater than 0.

Formulas to find Sewage Discharge

Influent BOD

Influent BOD is the total amount of BOD which is present in the incoming sewage.

Symbol: Q_i

Measurement: DensityUnit: mg/L

Note: Value should be greater than 0.

Formulas to find Influent BOD

Effluent BOD

Effluent BOD is the amount of BOD present in the outing sewage.

Symbol: Q

Measurement: DensityUnit: mg/L

Note: Value should be greater than 0.

Formulas to find Effluent BOD

Theoretical Oxygen Requirement

Theoretical Oxygen Requirement is the calculated amount of oxygen required to oxidize a compound to its final oxidation products.

Symbol: O₂

Measurement: Mass Flow RateUnit: mg/d

Note: Value should be greater than 0.

Formulas to find Theoretical Oxygen Requirement

Volume of Wasted Sludge per day

Volume of Wasted Sludge per day is the amount of sludge that is removed or wasted from a wastewater treatment process on a daily basis.

Symbol: Q_w

Measurement: Volumetric Flow RateUnit: m³/s

Note: Value should be greater than 0.

Formulas to find Volume of Wasted Sludge per day

MLSS in Returned or Wasted Sludge

MLSS in Returned or Wasted Sludge is the mixed liquor suspended solids in returned sludge in terms of mg per liter.

Symbol: X^R

Measurement: DensityUnit: mg/L

Note: Value should be greater than 0.

Formulas to find MLSS in Returned or Wasted Sludge

Other formulas in Ultimate BOD category

Go Ultimate BOD given Ratio of BOD to Ultimate BOD

BOD u = \frac{BOD5}{f}

Go Ultimate Biochemical Oxygen Demand

BOD u = \frac{BOD5}{0.68}

How to Evaluate Ultimate BOD given Oxygen Required in Aeration Tank?

Ultimate BOD given Oxygen Required in Aeration Tank evaluator uses Ultimate BOD given Oxygen Required = 5 Days BOD/(Sewage Discharge*(Influent BOD-Effluent BOD))/(Theoretical Oxygen Requirement+(1.42*Volume of Wasted Sludge per day*MLSS in Returned or Wasted Sludge)) to evaluate the Ultimate BOD given Oxygen Required, The Ultimate BOD given Oxygen Required in Aeration Tank formula is defined as the calculation of ultimate BOD when we have prior information of oxygen required in aeration tank. Ultimate BOD given Oxygen Required is denoted by BOD_uo symbol.

How to evaluate Ultimate BOD given Oxygen Required in Aeration Tank using this online evaluator? To use this online evaluator for Ultimate BOD given Oxygen Required in Aeration Tank, enter 5 Days BOD (BOD5), Sewage Discharge (Q_s), Influent BOD (Q_i), Effluent BOD (Q), Theoretical Oxygen Requirement (O₂), Volume of Wasted Sludge per day (Q_w) & MLSS in Returned or Wasted Sludge (X^R) and hit the calculate button.

FAQs on Ultimate BOD given Oxygen Required in Aeration Tank

What is the formula to find Ultimate BOD given Oxygen Required in Aeration Tank?

The formula of Ultimate BOD given Oxygen Required in Aeration Tank is expressed as Ultimate BOD given Oxygen Required = 5 Days BOD/(Sewage Discharge*(Influent BOD-Effluent BOD))/(Theoretical Oxygen Requirement+(1.42*Volume of Wasted Sludge per day*MLSS in Returned or Wasted Sludge)). Here is an example- 0.562586 = 0.00136/(10*(0.0132-0.0004))/(2.89351851851852E-11+(1.42*9.5*0.0014)).

How to calculate Ultimate BOD given Oxygen Required in Aeration Tank?

With 5 Days BOD (BOD5), Sewage Discharge (Q_s), Influent BOD (Q_i), Effluent BOD (Q), Theoretical Oxygen Requirement (O₂), Volume of Wasted Sludge per day (Q_w) & MLSS in Returned or Wasted Sludge (X^R) we can find Ultimate BOD given Oxygen Required in Aeration Tank using the formula - Ultimate BOD given Oxygen Required = 5 Days BOD/(Sewage Discharge*(Influent BOD-Effluent BOD))/(Theoretical Oxygen Requirement+(1.42*Volume of Wasted Sludge per day*MLSS in Returned or Wasted Sludge)).

Can the Ultimate BOD given Oxygen Required in Aeration Tank be negative?

No, the Ultimate BOD given Oxygen Required in Aeration Tank, measured in Density cannot be negative.

Which unit is used to measure Ultimate BOD given Oxygen Required in Aeration Tank?

Ultimate BOD given Oxygen Required in Aeration Tank is usually measured using the Milligram per Liter[mg/L] for Density. Kilogram per Cubic Meter[mg/L], Kilogram per Cubic Centimeter[mg/L], Gram per Cubic Meter[mg/L] are the few other units in which Ultimate BOD given Oxygen Required in Aeration Tank can be measured.

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Ultimate BOD given Oxygen Required in Aeration Tank Formula

Ultimate BOD given Oxygen Required in Aeration Tank Example

Ultimate BOD given Oxygen Required in Aeration Tank Solution

Ultimate BOD given Oxygen Required in Aeration Tank Formula Elements

Other formulas in Ultimate BOD category

How to Evaluate Ultimate BOD given Oxygen Required in Aeration Tank?

FAQs on Ultimate BOD given Oxygen Required in Aeration Tank

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