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Total Surface Area of Truncated Icosidodecahedron given Circumsphere Radius Formula

GoTotal Surface Area of Truncated Icosidodecahedron Formula

GoTotal Surface Area of Truncated Icosidodecahedron given Volume Formula

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Total Surface Area of Truncated Icosidodecahedron is the total quantity of plane enclosed by the entire surface of the Truncated Icosidodecahedron. Check FAQs

TSA = 30 \cdot {(\frac{2 \cdot r c}{\sqrt{31 + (12 \cdot \sqrt{5})}})}^{2} \cdot (1 + \sqrt{3} + \sqrt{5 + (2 \cdot \sqrt{5})})

TSA - Total Surface Area of Truncated Icosidodecahedron?r_c - Circumsphere Radius of Truncated Icosidodecahedron?

Total Surface Area of Truncated Icosidodecahedron given Circumsphere Radius Example

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Here is how the Total Surface Area of Truncated Icosidodecahedron given Circumsphere Radius equation looks like with Values.

Here is how the Total Surface Area of Truncated Icosidodecahedron given Circumsphere Radius equation looks like with Units.

Here is how the Total Surface Area of Truncated Icosidodecahedron given Circumsphere Radius equation looks like.

17407.2584 = 30 \cdot {(\frac{2 \cdot 38}{\sqrt{31 + (12 \cdot \sqrt{5})}})}^{2} \cdot (1 + \sqrt{3} + \sqrt{5 + (2 \cdot \sqrt{5})})

17407.2584m² = 30 \cdot {(\frac{2 \cdot 38m}{\sqrt{31 + (12 \cdot \sqrt{5})}})}^{2} \cdot (1 + \sqrt{3} + \sqrt{5 + (2 \cdot \sqrt{5})})

17407.2584 = 30 \cdot {(\frac{2 \cdot 38}{\sqrt{31 + (12 \cdot \sqrt{5})}})}^{2} \cdot (1 + \sqrt{3} + \sqrt{5 + (2 \cdot \sqrt{5})})

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Total Surface Area of Truncated Icosidodecahedron given Circumsphere Radius Solution

Follow our step by step solution on how to calculate Total Surface Area of Truncated Icosidodecahedron given Circumsphere Radius?

FIRST Step Consider the formula

TSA = 30 \cdot {(\frac{2 \cdot r c}{\sqrt{31 + (12 \cdot \sqrt{5})}})}^{2} \cdot (1 + \sqrt{3} + \sqrt{5 + (2 \cdot \sqrt{5})})

Next Step Substitute values of Variables

∴

TSA = 30 \cdot {(\frac{2 \cdot 38m}{\sqrt{31 + (12 \cdot \sqrt{5})}})}^{2} \cdot (1 + \sqrt{3} + \sqrt{5 + (2 \cdot \sqrt{5})})

Next Step Prepare to Evaluate

∴

TSA = 30 \cdot {(\frac{2 \cdot 38}{\sqrt{31 + (12 \cdot \sqrt{5})}})}^{2} \cdot (1 + \sqrt{3} + \sqrt{5 + (2 \cdot \sqrt{5})})

Next Step Evaluate

∴

TSA = 17407.2583973304m²

LAST Step Rounding Answer

∴

TSA = 17407.2584m²

Total Surface Area of Truncated Icosidodecahedron given Circumsphere Radius Formula Elements

Variables

Functions

Total Surface Area of Truncated Icosidodecahedron

Total Surface Area of Truncated Icosidodecahedron is the total quantity of plane enclosed by the entire surface of the Truncated Icosidodecahedron.

Symbol: TSA

Measurement: AreaUnit: m²

Note: Value should be greater than 0.

Formulas to find Total Surface Area of Truncated Icosidodecahedron

Circumsphere Radius of Truncated Icosidodecahedron

Circumsphere Radius of Truncated Icosidodecahedron is the radius of the sphere that contains the Truncated Icosidodecahedron in such a way that all the vertices are lying on the sphere.

Symbol: r_c

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Circumsphere Radius of Truncated Icosidodecahedron

sqrt

A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number.

Syntax: sqrt(Number)

Other Formulas to find Total Surface Area of Truncated Icosidodecahedron

Go Total Surface Area of Truncated Icosidodecahedron

TSA = 30 \cdot {l e}^{2} \cdot (1 + \sqrt{3} + \sqrt{5 + (2 \cdot \sqrt{5})})

Go Total Surface Area of Truncated Icosidodecahedron given Volume

TSA = 30 \cdot {(\frac{V}{5 \cdot (19 + (10 \cdot \sqrt{5}))})}^{\frac{2}{3}} \cdot (1 + \sqrt{3} + \sqrt{5 + (2 \cdot \sqrt{5})})

Go Total Surface Area of Truncated Icosidodecahedron given Midsphere Radius

TSA = 30 \cdot {(\frac{2 \cdot r m}{\sqrt{30 + (12 \cdot \sqrt{5})}})}^{2} \cdot (1 + \sqrt{3} + \sqrt{5 + (2 \cdot \sqrt{5})})

Go Total Surface Area of Truncated Icosidodecahedron given Surface to Volume Ratio

TSA = 30 \cdot {(\frac{6 \cdot (1 + \sqrt{3} + \sqrt{5 + (2 \cdot \sqrt{5})})}{R A/V \cdot (19 + (10 \cdot \sqrt{5}))})}^{2} \cdot (1 + \sqrt{3} + \sqrt{5 + (2 \cdot \sqrt{5})})

How to Evaluate Total Surface Area of Truncated Icosidodecahedron given Circumsphere Radius?

Total Surface Area of Truncated Icosidodecahedron given Circumsphere Radius evaluator uses Total Surface Area of Truncated Icosidodecahedron = 30*((2*Circumsphere Radius of Truncated Icosidodecahedron)/(sqrt(31+(12*sqrt(5)))))^2*(1+sqrt(3)+sqrt(5+(2*sqrt(5)))) to evaluate the Total Surface Area of Truncated Icosidodecahedron, Total Surface Area of Truncated Icosidodecahedron given Circumsphere Radius formula is defined as the total quantity of plane enclosed by the entire surface of the Truncated Icosidodecahedron, and calculated using the circumsphere radius of the Truncated Icosidodecahedron. Total Surface Area of Truncated Icosidodecahedron is denoted by TSA symbol.

How to evaluate Total Surface Area of Truncated Icosidodecahedron given Circumsphere Radius using this online evaluator? To use this online evaluator for Total Surface Area of Truncated Icosidodecahedron given Circumsphere Radius, enter Circumsphere Radius of Truncated Icosidodecahedron (r_c) and hit the calculate button.

FAQs on Total Surface Area of Truncated Icosidodecahedron given Circumsphere Radius

What is the formula to find Total Surface Area of Truncated Icosidodecahedron given Circumsphere Radius?

The formula of Total Surface Area of Truncated Icosidodecahedron given Circumsphere Radius is expressed as Total Surface Area of Truncated Icosidodecahedron = 30*((2*Circumsphere Radius of Truncated Icosidodecahedron)/(sqrt(31+(12*sqrt(5)))))^2*(1+sqrt(3)+sqrt(5+(2*sqrt(5)))). Here is an example- 17407.26 = 30*((2*38)/(sqrt(31+(12*sqrt(5)))))^2*(1+sqrt(3)+sqrt(5+(2*sqrt(5)))).

How to calculate Total Surface Area of Truncated Icosidodecahedron given Circumsphere Radius?

With Circumsphere Radius of Truncated Icosidodecahedron (r_c) we can find Total Surface Area of Truncated Icosidodecahedron given Circumsphere Radius using the formula - Total Surface Area of Truncated Icosidodecahedron = 30*((2*Circumsphere Radius of Truncated Icosidodecahedron)/(sqrt(31+(12*sqrt(5)))))^2*(1+sqrt(3)+sqrt(5+(2*sqrt(5)))). This formula also uses Square Root (sqrt) function(s).

What are the other ways to Calculate Total Surface Area of Truncated Icosidodecahedron?

Here are the different ways to Calculate Total Surface Area of Truncated Icosidodecahedron-

Total Surface Area of Truncated Icosidodecahedron=30*Edge Length of Truncated Icosidodecahedron^2*(1+sqrt(3)+sqrt(5+(2*sqrt(5))))
Total Surface Area of Truncated Icosidodecahedron=30*(Volume of Truncated Icosidodecahedron/(5*(19+(10*sqrt(5)))))^(2/3)*(1+sqrt(3)+sqrt(5+(2*sqrt(5))))
Total Surface Area of Truncated Icosidodecahedron=30*((2*Midsphere Radius of Truncated Icosidodecahedron)/(sqrt(30+(12*sqrt(5)))))^2*(1+sqrt(3)+sqrt(5+(2*sqrt(5))))

Can the Total Surface Area of Truncated Icosidodecahedron given Circumsphere Radius be negative?

No, the Total Surface Area of Truncated Icosidodecahedron given Circumsphere Radius, measured in Area cannot be negative.

Which unit is used to measure Total Surface Area of Truncated Icosidodecahedron given Circumsphere Radius?

Total Surface Area of Truncated Icosidodecahedron given Circumsphere Radius is usually measured using the Square Meter[m²] for Area. Square Kilometer[m²], Square Centimeter[m²], Square Millimeter[m²] are the few other units in which Total Surface Area of Truncated Icosidodecahedron given Circumsphere Radius can be measured.

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