FormulaDen.com

Physics Chemistry Math Chemical Engineering Civil Electrical Electronics Electronics and Instrumentation Materials Science Mechanical Production Engineering Financial Health

Total Solids Removed Per Day given Sludge Age Formula

Fx Copy

LaTeX Copy

Total Solids Removed Per Day given Sludge Age is the amount of solid material (in terms of weight or volume) that is removed from the wastewater treatment system daily. Check FAQs

M l = \frac{V \cdot X'}{θ c}

M_l - Total Solids Removed Per Day given Sludge Age?V - Volume of Tank?X^' - Mixed Liquor Suspended Solids?θ_c - Sludge Age?

Total Solids Removed Per Day given Sludge Age Example

With values

With units

Only example

Here is how the Total Solids Removed Per Day given Sludge Age equation looks like with Values.

Here is how the Total Solids Removed Per Day given Sludge Age equation looks like with Units.

Here is how the Total Solids Removed Per Day given Sludge Age equation looks like.

2.16 = \frac{9 \cdot 1200}{5}

2.16kg/d = \frac{9m³ \cdot 1200mg/L}{5d}

2.16 = \frac{9 \cdot 1200}{5}

Tip: Use pencil ( Pencil

) icon above to edit Input Values and Units.

Calculate

Recalculate

Solution

Copy

Reset

You are here -

Home » Category

Engineering » Category

Civil » Category

Environmental Engineering » fx Total Solids Removed Per Day given Sludge Age

Total Solids Removed Per Day given Sludge Age Solution

Follow our step by step solution on how to calculate Total Solids Removed Per Day given Sludge Age?

FIRST Step Consider the formula

M l = \frac{V \cdot X'}{θ c}

Next Step Substitute values of Variables

∴

M l = \frac{9m³ \cdot 1200mg/L}{5d}

Next Step Convert Units

∴

M l = \frac{9m³ \cdot 1.2kg/m³}{432000s}

Next Step Prepare to Evaluate

∴

M l = \frac{9 \cdot 1.2}{432000}

Next Step Evaluate

∴

M l = 2.5E-05kg/s

LAST Step Convert to Output's Unit

∴

M l = 2.16kg/d

Total Solids Removed Per Day given Sludge Age Formula Elements

Variables

Total Solids Removed Per Day given Sludge Age

Total Solids Removed Per Day given Sludge Age is the amount of solid material (in terms of weight or volume) that is removed from the wastewater treatment system daily.

Symbol: M_l

Measurement: Mass Flow RateUnit: kg/d

Note: Value should be greater than 0.

Formulas to find Total Solids Removed Per Day given Sludge Age

Volume of Tank

Volume of Tank is defined as the capacity of flocculation and mixing tank.

Symbol: V

Measurement: VolumeUnit: m³

Note: Value should be greater than 0.

Formulas to find Volume of Tank

Mixed Liquor Suspended Solids

Mixed Liquor Suspended Solids is the concentration of suspended solids in the mixed liquor of an aeration tank during the activated sludge process.

Symbol: X^'

Measurement: DensityUnit: mg/L

Note: Value should be between 1000 to 6500.

Formulas to find Mixed Liquor Suspended Solids

Sludge Age

Sludge Age is the average time for which the particle of suspended solids remains in aeration.

Symbol: θ_c

Measurement: TimeUnit: d

Note: Value should be greater than 0.

Formulas to find Sludge Age

How to Evaluate Total Solids Removed Per Day given Sludge Age?

Total Solids Removed Per Day given Sludge Age evaluator uses Total Solids Removed Per Day given Sludge Age = (Volume of Tank*Mixed Liquor Suspended Solids)/Sludge Age to evaluate the Total Solids Removed Per Day given Sludge Age, The Total Solids Removed Per Day given Sludge Age formula is defined as the calculation of total solids removed per day when we have prior information of other parameters used. Total Solids Removed Per Day given Sludge Age is denoted by M_l symbol.

How to evaluate Total Solids Removed Per Day given Sludge Age using this online evaluator? To use this online evaluator for Total Solids Removed Per Day given Sludge Age, enter Volume of Tank (V), Mixed Liquor Suspended Solids (X^') & Sludge Age (θ_c) and hit the calculate button.

FAQs on Total Solids Removed Per Day given Sludge Age

What is the formula to find Total Solids Removed Per Day given Sludge Age?

The formula of Total Solids Removed Per Day given Sludge Age is expressed as Total Solids Removed Per Day given Sludge Age = (Volume of Tank*Mixed Liquor Suspended Solids)/Sludge Age. Here is an example- 186624 = (9*1.2)/432000.

How to calculate Total Solids Removed Per Day given Sludge Age?

With Volume of Tank (V), Mixed Liquor Suspended Solids (X^') & Sludge Age (θ_c) we can find Total Solids Removed Per Day given Sludge Age using the formula - Total Solids Removed Per Day given Sludge Age = (Volume of Tank*Mixed Liquor Suspended Solids)/Sludge Age.

Can the Total Solids Removed Per Day given Sludge Age be negative?

No, the Total Solids Removed Per Day given Sludge Age, measured in Mass Flow Rate cannot be negative.

Which unit is used to measure Total Solids Removed Per Day given Sludge Age?

Total Solids Removed Per Day given Sludge Age is usually measured using the Kilogram per Day[kg/d] for Mass Flow Rate. Kilogram per Second[kg/d], Gram per Second[kg/d], Gram per Hour[kg/d] are the few other units in which Total Solids Removed Per Day given Sludge Age can be measured.

Let Others Know

✖

Facebook

Twitter

Copied!

Total Solids Removed Per Day given Sludge Age Formula

Total Solids Removed Per Day given Sludge Age Example

Total Solids Removed Per Day given Sludge Age Solution

Total Solids Removed Per Day given Sludge Age Formula Elements

How to Evaluate Total Solids Removed Per Day given Sludge Age?

FAQs on Total Solids Removed Per Day given Sludge Age

Variable Name