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Total or Absolute Pressure Formula

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Absolute Pressure is the total pressure measured with respect to absolute zero, which is a perfect vacuum. It is the sum of the gauge pressure and the atmospheric pressure. Check FAQs

P abs = (ρ \cdot [g] \cdot H \cdot \cosh (2 \cdot π \cdot \frac{D Z+d}{λ}) \cdot \frac{\cos (θ)}{2} \cdot \cosh (2 \cdot π \cdot \frac{d}{λ})) - (ρ \cdot [g] \cdot Z) + P atm

P_abs - Absolute Pressure?ρ - Mass Density?H - Wave Height?D_Z+d - Distance above the Bottom?λ - Wavelength?θ - Phase Angle?d - Water Depth?Z - Seabed Elevation?P_atm - Atmospheric Pressure?[g] - Gravitational acceleration on Earth?[g] - Gravitational acceleration on Earth?π - Archimedes' constant?

Total or Absolute Pressure Example

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Here is how the Total or Absolute Pressure equation looks like with Values.

Here is how the Total or Absolute Pressure equation looks like with Units.

Here is how the Total or Absolute Pressure equation looks like.

99511.5029 = (997 \cdot 9.8066 \cdot 3 \cdot \cosh (2 \cdot 3.1416 \cdot \frac{2}{26.8}) \cdot \frac{\cos (60)}{2} \cdot \cosh (2 \cdot 3.1416 \cdot \frac{1.05}{26.8})) - (997 \cdot 9.8066 \cdot 0.908) + 99987

99511.5029Pa = (997kg/m³ \cdot 9.8066m/s² \cdot 3m \cdot \cosh (2 \cdot 3.1416 \cdot \frac{2m}{26.8m}) \cdot \frac{\cos (60°)}{2} \cdot \cosh (2 \cdot 3.1416 \cdot \frac{1.05m}{26.8m})) - (997kg/m³ \cdot 9.8066m/s² \cdot 0.908) + 99987Pa

99511.5029 = (997 \cdot 9.8066 \cdot 3 \cdot \cosh (2 \cdot 3.1416 \cdot \frac{2}{26.8}) \cdot \frac{\cos (60)}{2} \cdot \cosh (2 \cdot 3.1416 \cdot \frac{1.05}{26.8})) - (997 \cdot 9.8066 \cdot 0.908) + 99987

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Total or Absolute Pressure Solution

Follow our step by step solution on how to calculate Total or Absolute Pressure?

FIRST Step Consider the formula

P abs = (ρ \cdot [g] \cdot H \cdot \cosh (2 \cdot π \cdot \frac{D Z+d}{λ}) \cdot \frac{\cos (θ)}{2} \cdot \cosh (2 \cdot π \cdot \frac{d}{λ})) - (ρ \cdot [g] \cdot Z) + P atm

Next Step Substitute values of Variables

∴

P abs = (997kg/m³ \cdot [g] \cdot 3m \cdot \cosh (2 \cdot π \cdot \frac{2m}{26.8m}) \cdot \frac{\cos (60°)}{2} \cdot \cosh (2 \cdot π \cdot \frac{1.05m}{26.8m})) - (997kg/m³ \cdot [g] \cdot 0.908) + 99987Pa

Next Step Substitute values of Constants

∴

P abs = (997kg/m³ \cdot 9.8066m/s² \cdot 3m \cdot \cosh (2 \cdot 3.1416 \cdot \frac{2m}{26.8m}) \cdot \frac{\cos (60°)}{2} \cdot \cosh (2 \cdot 3.1416 \cdot \frac{1.05m}{26.8m})) - (997kg/m³ \cdot 9.8066m/s² \cdot 0.908) + 99987Pa

Next Step Convert Units

∴

P abs = (997kg/m³ \cdot 9.8066m/s² \cdot 3m \cdot \cosh (2 \cdot 3.1416 \cdot \frac{2m}{26.8m}) \cdot \frac{\cos (1.0472rad)}{2} \cdot \cosh (2 \cdot 3.1416 \cdot \frac{1.05m}{26.8m})) - (997kg/m³ \cdot 9.8066m/s² \cdot 0.908) + 99987Pa

Next Step Prepare to Evaluate

∴

P abs = (997 \cdot 9.8066 \cdot 3 \cdot \cosh (2 \cdot 3.1416 \cdot \frac{2}{26.8}) \cdot \frac{\cos (1.0472)}{2} \cdot \cosh (2 \cdot 3.1416 \cdot \frac{1.05}{26.8})) - (997 \cdot 9.8066 \cdot 0.908) + 99987

Next Step Evaluate

∴

P abs = 99511.5029014774Pa

LAST Step Rounding Answer

∴

P abs = 99511.5029Pa

Total or Absolute Pressure Formula Elements

Variables

Constants

Functions

Absolute Pressure

Absolute Pressure is the total pressure measured with respect to absolute zero, which is a perfect vacuum. It is the sum of the gauge pressure and the atmospheric pressure.

Symbol: P_abs

Measurement: PressureUnit: Pa

Note: Value should be greater than 0.

Formulas to find Absolute Pressure

Mass Density

Mass Density is crucial for understanding the distribution of pressures exerted by overlying soil or water layers on underground structures like foundations, tunnels, or pipelines.

Symbol: ρ

Measurement: Mass ConcentrationUnit: kg/m³

Note: Value should be greater than 0.

Formulas to find Mass Density

Wave Height

Wave Height is the vertical distance between the crest and the trough of a wave. Higher wave heights correspond to greater wave forces, which leads to increased structural loading.

Symbol: H

Measurement: LengthUnit: m