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Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc. of Reactant A Formula

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Time is used to defined as the period of time that is required for the reactant to given a certain amount of product in a chemical reaction. Check FAQs

t = (\frac{1}{k f'}) \cdot (\frac{{x eq}^{2}}{2 \cdot A 0 \cdot (A 0 - x eq)}) \cdot \ln (\frac{x \cdot (A 0 - 2 \cdot x eq) + A 0 \cdot x eq}{A 0 \cdot (x eq - x)})

t - Time?k_f' - Forward Reaction Rate Constant for 2nd Order?x_eq - Concentration of Reactant at Equilibrium?A₀ - Initial Concentration of Reactant A?x - Concentration of Product at Time t?

Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc. of Reactant A Example

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Here is how the Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc. of Reactant A equation looks like with Values.

Here is how the Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc. of Reactant A equation looks like with Units.

Here is how the Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc. of Reactant A equation looks like.

43348.5303 = (\frac{1}{0.0062}) \cdot (\frac{70^{2}}{2 \cdot 100 \cdot (100 - 70)}) \cdot \ln (\frac{27.5 \cdot (100 - 2 \cdot 70) + 100 \cdot 70}{100 \cdot (70 - 27.5)})

43348.5303s = (\frac{1}{0.0062L/(mol*s)}) \cdot (\frac{{70mol/L}^{2}}{2 \cdot 100mol/L \cdot (100mol/L - 70mol/L)}) \cdot \ln (\frac{27.5mol/L \cdot (100mol/L - 2 \cdot 70mol/L) + 100mol/L \cdot 70mol/L}{100mol/L \cdot (70mol/L - 27.5mol/L)})

43348.5303 = (\frac{1}{0.0062}) \cdot (\frac{70^{2}}{2 \cdot 100 \cdot (100 - 70)}) \cdot \ln (\frac{27.5 \cdot (100 - 2 \cdot 70) + 100 \cdot 70}{100 \cdot (70 - 27.5)})

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Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc. of Reactant A Solution

Follow our step by step solution on how to calculate Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc. of Reactant A?

FIRST Step Consider the formula

t = (\frac{1}{k f'}) \cdot (\frac{{x eq}^{2}}{2 \cdot A 0 \cdot (A 0 - x eq)}) \cdot \ln (\frac{x \cdot (A 0 - 2 \cdot x eq) + A 0 \cdot x eq}{A 0 \cdot (x eq - x)})

Next Step Substitute values of Variables

∴

t = (\frac{1}{0.0062L/(mol*s)}) \cdot (\frac{{70mol/L}^{2}}{2 \cdot 100mol/L \cdot (100mol/L - 70mol/L)}) \cdot \ln (\frac{27.5mol/L \cdot (100mol/L - 2 \cdot 70mol/L) + 100mol/L \cdot 70mol/L}{100mol/L \cdot (70mol/L - 27.5mol/L)})

Next Step Convert Units

∴

t = (\frac{1}{6.2E-6m³/(mol*s)}) \cdot (\frac{{70000mol/m³}^{2}}{2 \cdot 100000mol/m³ \cdot (100000mol/m³ - 70000mol/m³)}) \cdot \ln (\frac{27500mol/m³ \cdot (100000mol/m³ - 2 \cdot 70000mol/m³) + 100000mol/m³ \cdot 70000mol/m³}{100000mol/m³ \cdot (70000mol/m³ - 27500mol/m³)})

Next Step Prepare to Evaluate

∴

t = (\frac{1}{6.2E-6}) \cdot (\frac{70000^{2}}{2 \cdot 100000 \cdot (100000 - 70000)}) \cdot \ln (\frac{27500 \cdot (100000 - 2 \cdot 70000) + 100000 \cdot 70000}{100000 \cdot (70000 - 27500)})

Next Step Evaluate

∴

t = 43348.5302880045s

LAST Step Rounding Answer

∴

t = 43348.5303s

Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc. of Reactant A Formula Elements

Variables

Functions

Time

Time is used to defined as the period of time that is required for the reactant to given a certain amount of product in a chemical reaction.

Symbol: t

Measurement: TimeUnit: s

Note: Value should be greater than -1.

Formulas to find Time

Forward Reaction Rate Constant for 2nd Order

Forward Reaction Rate Constant for 2nd Order is used to define the relationship between the molar concentration of the reactants and the rate of the chemical reaction in forward direction.

Symbol: k_f'

Measurement: Second Order Reaction Rate ConstantUnit: L/(mol*s)

Note: Value should be greater than 0.

Formulas to find Forward Reaction Rate Constant for 2nd Order

Concentration of Reactant at Equilibrium

Concentration of Reactant at Equilibrium is defined as the amount of reactant present when the reaction is at equilibrium condition.

Symbol: x_eq

Measurement: Molar ConcentrationUnit: mol/L

Note: Value should be greater than 0.

Formulas to find Concentration of Reactant at Equilibrium

Initial Concentration of Reactant A

Initial Concentration of Reactant A is defined as the concentration of the reactant A at time t=0.

Symbol: A₀

Measurement: Molar ConcentrationUnit: mol/L

Note: Value should be greater than 0.

Formulas to find Initial Concentration of Reactant A

Concentration of Product at Time t

Concentration of Product at Time t is defined as the amount of reactant that has been converted into product in a time interval of t.

Symbol: x

Measurement: Molar ConcentrationUnit: mol/L

Note: Value should be greater than 0.

Formulas to find Concentration of Product at Time t

The natural logarithm, also known as the logarithm to the base e, is the inverse function of the natural exponential function.

Syntax: ln(Number)

Other formulas in Second Order Opposed by Second Order Reactions category

Go Forward Rxn Rate Const for 2nd Order Opposed by 2nd Order Rxn given Ini Conc of Reactant A

k fA' = (\frac{1}{t}) \cdot (\frac{{x eq}^{2}}{2 \cdot A 0 \cdot (A 0 - x eq)}) \cdot \ln (\frac{x \cdot (A 0 - 2 \cdot x eq) + A 0 \cdot x eq}{A 0 \cdot (x eq - x)})

Go Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc of Reactant B

t 2nd = (\frac{1}{k f'}) \cdot (\frac{{x eq}^{2}}{2 \cdot B 0 \cdot (B 0 - x eq)}) \cdot \ln (\frac{x \cdot (B 0 - 2 \cdot x eq) + B 0 \cdot x eq}{B 0 \cdot (x eq - x)})

Go Forward Rxn. Rate Const. for 2nd Order Opposed by 2nd Order Rxn. given Ini. Conc. of Reactant B

k f' = (\frac{1}{t}) \cdot (\frac{{x eq}^{2}}{2 \cdot B 0 \cdot (B 0 - x eq)}) \cdot \ln (\frac{x \cdot (B 0 - 2 \cdot x eq) + B 0 \cdot x eq}{B 0 \cdot (x eq - x)})

Go Backward Reaction Rate Constant for 2nd Order Opposed by 2nd Order Reaction

k b' = k f' \cdot \frac{(A 0 - x eq) \cdot (B 0 - x eq)}{{x eq}^{2}}

How to Evaluate Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc. of Reactant A?

Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc. of Reactant A evaluator uses Time = (1/Forward Reaction Rate Constant for 2nd Order)*(Concentration of Reactant at Equilibrium^2/(2*Initial Concentration of Reactant A*(Initial Concentration of Reactant A-Concentration of Reactant at Equilibrium)))*ln((Concentration of Product at Time t*(Initial Concentration of Reactant A-2*Concentration of Reactant at Equilibrium)+Initial Concentration of Reactant A*Concentration of Reactant at Equilibrium)/(Initial Concentration of Reactant A*(Concentration of Reactant at Equilibrium-Concentration of Product at Time t))) to evaluate the Time, The Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc. of Reactant A formula is defined as the time interval required to convert a particular concentration reactant to a certain concentration of product in a First Order Opposed by First Order Reaction. Time is denoted by t symbol.

How to evaluate Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc. of Reactant A using this online evaluator? To use this online evaluator for Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc. of Reactant A, enter Forward Reaction Rate Constant for 2nd Order (k_f'), Concentration of Reactant at Equilibrium (x_eq), Initial Concentration of Reactant A (A₀) & Concentration of Product at Time t (x) and hit the calculate button.

FAQs on Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc. of Reactant A

What is the formula to find Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc. of Reactant A?

The formula of Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc. of Reactant A is expressed as Time = (1/Forward Reaction Rate Constant for 2nd Order)*(Concentration of Reactant at Equilibrium^2/(2*Initial Concentration of Reactant A*(Initial Concentration of Reactant A-Concentration of Reactant at Equilibrium)))*ln((Concentration of Product at Time t*(Initial Concentration of Reactant A-2*Concentration of Reactant at Equilibrium)+Initial Concentration of Reactant A*Concentration of Reactant at Equilibrium)/(Initial Concentration of Reactant A*(Concentration of Reactant at Equilibrium-Concentration of Product at Time t))). Here is an example- 159460.7 = (1/6.18E-06)*(70000^2/(2*100000*(100000-70000)))*ln((27500*(100000-2*70000)+100000*70000)/(100000*(70000-27500))).

How to calculate Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc. of Reactant A?

With Forward Reaction Rate Constant for 2nd Order (k_f'), Concentration of Reactant at Equilibrium (x_eq), Initial Concentration of Reactant A (A₀) & Concentration of Product at Time t (x) we can find Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc. of Reactant A using the formula - Time = (1/Forward Reaction Rate Constant for 2nd Order)*(Concentration of Reactant at Equilibrium^2/(2*Initial Concentration of Reactant A*(Initial Concentration of Reactant A-Concentration of Reactant at Equilibrium)))*ln((Concentration of Product at Time t*(Initial Concentration of Reactant A-2*Concentration of Reactant at Equilibrium)+Initial Concentration of Reactant A*Concentration of Reactant at Equilibrium)/(Initial Concentration of Reactant A*(Concentration of Reactant at Equilibrium-Concentration of Product at Time t))). This formula also uses Natural Logarithm (ln) function(s).

Can the Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc. of Reactant A be negative?

Yes, the Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc. of Reactant A, measured in Time can be negative.

Which unit is used to measure Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc. of Reactant A?

Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc. of Reactant A is usually measured using the Second[s] for Time. Millisecond[s], Microsecond[s], Nanosecond[s] are the few other units in which Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc. of Reactant A can be measured.

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Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc. of Reactant A Formula

Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc. of Reactant A Example

Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc. of Reactant A Solution

Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc. of Reactant A Formula Elements

Other formulas in Second Order Opposed by Second Order Reactions category

How to Evaluate Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc. of Reactant A?

FAQs on Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc. of Reactant A

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