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Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc of Reactant B Formula

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Time for 2nd Order is used to defined as the period of time that is required for the reactant to given a certain amount of product in a chemical reaction. Check FAQs

t 2nd = (\frac{1}{k f'}) \cdot (\frac{{x eq}^{2}}{2 \cdot B 0 \cdot (B 0 - x eq)}) \cdot \ln (\frac{x \cdot (B 0 - 2 \cdot x eq) + B 0 \cdot x eq}{B 0 \cdot (x eq - x)})

t_2nd - Time for 2nd Order?k_f' - Forward Reaction Rate Constant for 2nd Order?x_eq - Concentration of Reactant at Equilibrium?B₀ - Initial Concentration of Reactant B?x - Concentration of Product at Time t?

Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc of Reactant B Example

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Here is how the Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc of Reactant B equation looks like with Values.

Here is how the Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc of Reactant B equation looks like with Units.

Here is how the Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc of Reactant B equation looks like.

74302.8643 = (\frac{1}{0.0062}) \cdot (\frac{70^{2}}{2 \cdot 80 \cdot (80 - 70)}) \cdot \ln (\frac{27.5 \cdot (80 - 2 \cdot 70) + 80 \cdot 70}{80 \cdot (70 - 27.5)})

74302.8643s = (\frac{1}{0.0062L/(mol*s)}) \cdot (\frac{{70mol/L}^{2}}{2 \cdot 80mol/L \cdot (80mol/L - 70mol/L)}) \cdot \ln (\frac{27.5mol/L \cdot (80mol/L - 2 \cdot 70mol/L) + 80mol/L \cdot 70mol/L}{80mol/L \cdot (70mol/L - 27.5mol/L)})

74302.8643 = (\frac{1}{0.0062}) \cdot (\frac{70^{2}}{2 \cdot 80 \cdot (80 - 70)}) \cdot \ln (\frac{27.5 \cdot (80 - 2 \cdot 70) + 80 \cdot 70}{80 \cdot (70 - 27.5)})

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Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc of Reactant B Solution

Follow our step by step solution on how to calculate Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc of Reactant B?

FIRST Step Consider the formula

t 2nd = (\frac{1}{k f'}) \cdot (\frac{{x eq}^{2}}{2 \cdot B 0 \cdot (B 0 - x eq)}) \cdot \ln (\frac{x \cdot (B 0 - 2 \cdot x eq) + B 0 \cdot x eq}{B 0 \cdot (x eq - x)})

Next Step Substitute values of Variables

∴

t 2nd = (\frac{1}{0.0062L/(mol*s)}) \cdot (\frac{{70mol/L}^{2}}{2 \cdot 80mol/L \cdot (80mol/L - 70mol/L)}) \cdot \ln (\frac{27.5mol/L \cdot (80mol/L - 2 \cdot 70mol/L) + 80mol/L \cdot 70mol/L}{80mol/L \cdot (70mol/L - 27.5mol/L)})

Next Step Convert Units

∴

t 2nd = (\frac{1}{6.2E-6m³/(mol*s)}) \cdot (\frac{{70000mol/m³}^{2}}{2 \cdot 80000mol/m³ \cdot (80000mol/m³ - 70000mol/m³)}) \cdot \ln (\frac{27500mol/m³ \cdot (80000mol/m³ - 2 \cdot 70000mol/m³) + 80000mol/m³ \cdot 70000mol/m³}{80000mol/m³ \cdot (70000mol/m³ - 27500mol/m³)})

Next Step Prepare to Evaluate

∴

t 2nd = (\frac{1}{6.2E-6}) \cdot (\frac{70000^{2}}{2 \cdot 80000 \cdot (80000 - 70000)}) \cdot \ln (\frac{27500 \cdot (80000 - 2 \cdot 70000) + 80000 \cdot 70000}{80000 \cdot (70000 - 27500)})

Next Step Evaluate

∴

t 2nd = 74302.8642521726s

LAST Step Rounding Answer

∴

t 2nd = 74302.8643s

Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc of Reactant B Formula Elements

Variables

Functions

Time for 2nd Order

Time for 2nd Order is used to defined as the period of time that is required for the reactant to given a certain amount of product in a chemical reaction.

Symbol: t_2nd

Measurement: TimeUnit: s

Note: Value can be positive or negative.

Formulas to find Time for 2nd Order

Forward Reaction Rate Constant for 2nd Order

Forward Reaction Rate Constant for 2nd Order is used to define the relationship between the molar concentration of the reactants and the rate of the chemical reaction in forward direction.

Symbol: k_f'

Measurement: Second Order Reaction Rate ConstantUnit: L/(mol*s)

Note: Value should be greater than 0.

Formulas to find Forward Reaction Rate Constant for 2nd Order

Concentration of Reactant at Equilibrium

Concentration of Reactant at Equilibrium is defined as the amount of reactant present when the reaction is at equilibrium condition.

Symbol: x_eq

Measurement: Molar ConcentrationUnit: mol/L

Note: Value should be greater than 0.

Formulas to find Concentration of Reactant at Equilibrium

Initial Concentration of Reactant B

Initial Concentration of Reactant B is defined as the initial concentration of the reactant B at time t=0.

Symbol: B₀

Measurement: Molar ConcentrationUnit: mol/L

Note: Value should be greater than 0.

Formulas to find Initial Concentration of Reactant B

Concentration of Product at Time t

Concentration of Product at Time t is defined as the amount of reactant that has been converted into product in a time interval of t.

Symbol: x

Measurement: Molar ConcentrationUnit: mol/L

Note: Value should be greater than 0.

Formulas to find Concentration of Product at Time t

The natural logarithm, also known as the logarithm to the base e, is the inverse function of the natural exponential function.

Syntax: ln(Number)

Other formulas in Second Order Opposed by Second Order Reactions category

Go Product Conc for 1st Order Opposed by 1st Order Rxn given Initial Conc of B greater than 0

x = x eq \cdot (1 - \exp (- k f \cdot (\frac{A 0 + B 0}{B 0 + x eq}) \cdot t))

Go Product Conc of First Order Opposed by First Order Reaction given Initial Conc of Reactant

x = x eq \cdot (1 - \exp (- k f \cdot t \cdot (\frac{A 0}{x eq})))

Go Product Concentration of 1st Order Opposed by 1st Order Reaction at given Time t

x = x eq \cdot (1 - \exp (- (k f + k b) \cdot t))

Go Reactant Concentration at given Time t

A = A 0 \cdot (\frac{k f}{k f + k b}) \cdot ((\frac{k b}{k f}) + \exp (- (k f + k b) \cdot t))

How to Evaluate Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc of Reactant B?

Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc of Reactant B evaluator uses Time for 2nd Order = (1/Forward Reaction Rate Constant for 2nd Order)*(Concentration of Reactant at Equilibrium^2/(2*Initial Concentration of Reactant B*(Initial Concentration of Reactant B-Concentration of Reactant at Equilibrium)))*ln((Concentration of Product at Time t*(Initial Concentration of Reactant B-2*Concentration of Reactant at Equilibrium)+Initial Concentration of Reactant B*Concentration of Reactant at Equilibrium)/(Initial Concentration of Reactant B*(Concentration of Reactant at Equilibrium-Concentration of Product at Time t))) to evaluate the Time for 2nd Order, The Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc of Reactant B formula is defined as the time interval required to convert a particular concentration reactant to a certain concentration of product in a Second Order Opposed by Second Order Reaction. Time for 2nd Order is denoted by t_2nd symbol.

How to evaluate Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc of Reactant B using this online evaluator? To use this online evaluator for Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc of Reactant B, enter Forward Reaction Rate Constant for 2nd Order (k_f'), Concentration of Reactant at Equilibrium (x_eq), Initial Concentration of Reactant B (B₀) & Concentration of Product at Time t (x) and hit the calculate button.

FAQs on Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc of Reactant B

What is the formula to find Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc of Reactant B?

The formula of Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc of Reactant B is expressed as Time for 2nd Order = (1/Forward Reaction Rate Constant for 2nd Order)*(Concentration of Reactant at Equilibrium^2/(2*Initial Concentration of Reactant B*(Initial Concentration of Reactant B-Concentration of Reactant at Equilibrium)))*ln((Concentration of Product at Time t*(Initial Concentration of Reactant B-2*Concentration of Reactant at Equilibrium)+Initial Concentration of Reactant B*Concentration of Reactant at Equilibrium)/(Initial Concentration of Reactant B*(Concentration of Reactant at Equilibrium-Concentration of Product at Time t))). Here is an example- 7.4E+10 = (1/6.18E-06)*(70000^2/(2*80000*(80000-70000)))*ln((27500*(80000-2*70000)+80000*70000)/(80000*(70000-27500))).

How to calculate Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc of Reactant B?

With Forward Reaction Rate Constant for 2nd Order (k_f'), Concentration of Reactant at Equilibrium (x_eq), Initial Concentration of Reactant B (B₀) & Concentration of Product at Time t (x) we can find Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc of Reactant B using the formula - Time for 2nd Order = (1/Forward Reaction Rate Constant for 2nd Order)*(Concentration of Reactant at Equilibrium^2/(2*Initial Concentration of Reactant B*(Initial Concentration of Reactant B-Concentration of Reactant at Equilibrium)))*ln((Concentration of Product at Time t*(Initial Concentration of Reactant B-2*Concentration of Reactant at Equilibrium)+Initial Concentration of Reactant B*Concentration of Reactant at Equilibrium)/(Initial Concentration of Reactant B*(Concentration of Reactant at Equilibrium-Concentration of Product at Time t))). This formula also uses Natural Logarithm (ln) function(s).

Can the Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc of Reactant B be negative?

Yes, the Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc of Reactant B, measured in Time can be negative.

Which unit is used to measure Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc of Reactant B?

Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc of Reactant B is usually measured using the Second[s] for Time. Millisecond[s], Microsecond[s], Nanosecond[s] are the few other units in which Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc of Reactant B can be measured.

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Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc of Reactant B Formula

Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc of Reactant B Example

Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc of Reactant B Solution

Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc of Reactant B Formula Elements

Other formulas in Second Order Opposed by Second Order Reactions category

How to Evaluate Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc of Reactant B?

FAQs on Time taken for 2nd Order Opposed by 2nd Order Reaction given Initial Conc of Reactant B

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