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Time taken for 2nd Order Opposed by 1st Order Reaction given Initial Conc of Reactant A Formula

GoTime taken for 1st Order Opposed by 1st Order Reaction Formula

GoTime taken for 1st Order Opposed by 1st Order Reaction given Initial Concentration of Reactant Formula

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Time is used to defined as the period of time that is required for the reactant to given a certain amount of product in a chemical reaction. Check FAQs

t = (\frac{1}{k f'}) \cdot (\frac{x eq}{({A 0}^{2}) - ({x eq}^{2})}) \cdot \ln (\frac{x eq \cdot ({A 0}^{2} - x \cdot x eq)}{{A 0}^{2} \cdot (x eq - x)})

t - Time?k_f' - Forward Reaction Rate Constant for 2nd Order?x_eq - Concentration of Reactant at Equilibrium?A₀ - Initial Concentration of Reactant A?x - Concentration of Product at Time t?

Time taken for 2nd Order Opposed by 1st Order Reaction given Initial Conc of Reactant A Example

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Here is how the Time taken for 2nd Order Opposed by 1st Order Reaction given Initial Conc of Reactant A equation looks like with Values.

Here is how the Time taken for 2nd Order Opposed by 1st Order Reaction given Initial Conc of Reactant A equation looks like with Units.

Here is how the Time taken for 2nd Order Opposed by 1st Order Reaction given Initial Conc of Reactant A equation looks like.

0.6334 = (\frac{1}{0.0062}) \cdot (\frac{70}{(100^{2}) - (70^{2})}) \cdot \ln (\frac{70 \cdot (100^{2} - 27.5 \cdot 70)}{100^{2} \cdot (70 - 27.5)})

0.6334s = (\frac{1}{0.0062L/(mol*s)}) \cdot (\frac{70mol/L}{({100mol/L}^{2}) - ({70mol/L}^{2})}) \cdot \ln (\frac{70mol/L \cdot ({100mol/L}^{2} - 27.5mol/L \cdot 70mol/L)}{{100mol/L}^{2} \cdot (70mol/L - 27.5mol/L)})

0.6334 = (\frac{1}{0.0062}) \cdot (\frac{70}{(100^{2}) - (70^{2})}) \cdot \ln (\frac{70 \cdot (100^{2} - 27.5 \cdot 70)}{100^{2} \cdot (70 - 27.5)})

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Time taken for 2nd Order Opposed by 1st Order Reaction given Initial Conc of Reactant A Solution

Follow our step by step solution on how to calculate Time taken for 2nd Order Opposed by 1st Order Reaction given Initial Conc of Reactant A?

FIRST Step Consider the formula

t = (\frac{1}{k f'}) \cdot (\frac{x eq}{({A 0}^{2}) - ({x eq}^{2})}) \cdot \ln (\frac{x eq \cdot ({A 0}^{2} - x \cdot x eq)}{{A 0}^{2} \cdot (x eq - x)})

Next Step Substitute values of Variables

∴

t = (\frac{1}{0.0062L/(mol*s)}) \cdot (\frac{70mol/L}{({100mol/L}^{2}) - ({70mol/L}^{2})}) \cdot \ln (\frac{70mol/L \cdot ({100mol/L}^{2} - 27.5mol/L \cdot 70mol/L)}{{100mol/L}^{2} \cdot (70mol/L - 27.5mol/L)})

Next Step Convert Units

∴

t = (\frac{1}{6.2E-6m³/(mol*s)}) \cdot (\frac{70000mol/m³}{({100000mol/m³}^{2}) - ({70000mol/m³}^{2})}) \cdot \ln (\frac{70000mol/m³ \cdot ({100000mol/m³}^{2} - 27500mol/m³ \cdot 70000mol/m³)}{{100000mol/m³}^{2} \cdot (70000mol/m³ - 27500mol/m³)})

Next Step Prepare to Evaluate

∴

t = (\frac{1}{6.2E-6}) \cdot (\frac{70000}{(100000^{2}) - (70000^{2})}) \cdot \ln (\frac{70000 \cdot (100000^{2} - 27500 \cdot 70000)}{100000^{2} \cdot (70000 - 27500)})

Next Step Evaluate

∴

t = 0.63336905756572s

LAST Step Rounding Answer

∴

t = 0.6334s

Time taken for 2nd Order Opposed by 1st Order Reaction given Initial Conc of Reactant A Formula Elements

Variables

Functions

Time

Time is used to defined as the period of time that is required for the reactant to given a certain amount of product in a chemical reaction.

Symbol: t

Measurement: TimeUnit: s

Note: Value should be greater than -1.

Formulas to find Time

Forward Reaction Rate Constant for 2nd Order

Forward Reaction Rate Constant for 2nd Order is used to define the relationship between the molar concentration of the reactants and the rate of the chemical reaction in forward direction.

Symbol: k_f'

Measurement: Second Order Reaction Rate ConstantUnit: L/(mol*s)

Note: Value should be greater than 0.

Formulas to find Forward Reaction Rate Constant for 2nd Order

Concentration of Reactant at Equilibrium

Concentration of Reactant at Equilibrium is defined as the amount of reactant present when the reaction is at equilibrium condition.

Symbol: x_eq

Measurement: Molar ConcentrationUnit: mol/L

Note: Value should be greater than 0.

Formulas to find Concentration of Reactant at Equilibrium

Initial Concentration of Reactant A

Initial Concentration of Reactant A is defined as the concentration of the reactant A at time t=0.

Symbol: A₀

Measurement: Molar ConcentrationUnit: mol/L

Note: Value should be greater than 0.

Formulas to find Initial Concentration of Reactant A

Concentration of Product at Time t

Concentration of Product at Time t is defined as the amount of reactant that has been converted into product in a time interval of t.

Symbol: x

Measurement: Molar ConcentrationUnit: mol/L

Note: Value should be greater than 0.

Formulas to find Concentration of Product at Time t

The natural logarithm, also known as the logarithm to the base e, is the inverse function of the natural exponential function.

Syntax: ln(Number)

Other Formulas to find Time

Go Time taken for 1st Order Opposed by 1st Order Reaction

t = \frac{\ln (\frac{x eq}{x eq - x})}{k f + k b}

Go Time taken for 1st Order Opposed by 1st Order Reaction given Initial Concentration of Reactant

t = (\frac{1}{k f}) \cdot (\frac{x eq}{A 0}) \cdot \ln (\frac{x eq}{x eq - x})

Go Time taken when Initial Concentration of Reactant B greater than 0

t = \frac{1}{k f} \cdot \ln (\frac{x eq}{x eq - x}) \cdot (\frac{B 0 + x eq}{A 0 + B 0})

Go Time Taken for Completion of Reaction

t = (\frac{1}{k f}) \cdot (\frac{x eq}{2 \cdot A 0 - x eq}) \cdot \ln (\frac{A 0 \cdot x eq + x \cdot (A 0 - x eq)}{A 0 \cdot (x eq - x)})

Other formulas in Second Order Opposed by First Order Reactions category

Go Product Conc for 1st Order Opposed by 1st Order Rxn given Initial Conc of B greater than 0

x = x eq \cdot (1 - \exp (- k f \cdot (\frac{A 0 + B 0}{B 0 + x eq}) \cdot t))

Go Product Conc of First Order Opposed by First Order Reaction given Initial Conc of Reactant

x = x eq \cdot (1 - \exp (- k f \cdot t \cdot (\frac{A 0}{x eq})))

Go Product Concentration of 1st Order Opposed by 1st Order Reaction at given Time t

x = x eq \cdot (1 - \exp (- (k f + k b) \cdot t))

Go Reactant Concentration at given Time t

A = A 0 \cdot (\frac{k f}{k f + k b}) \cdot ((\frac{k b}{k f}) + \exp (- (k f + k b) \cdot t))

How to Evaluate Time taken for 2nd Order Opposed by 1st Order Reaction given Initial Conc of Reactant A?

Time taken for 2nd Order Opposed by 1st Order Reaction given Initial Conc of Reactant A evaluator uses Time = (1/Forward Reaction Rate Constant for 2nd Order)*(Concentration of Reactant at Equilibrium/((Initial Concentration of Reactant A^2)-(Concentration of Reactant at Equilibrium^2)))*ln((Concentration of Reactant at Equilibrium*(Initial Concentration of Reactant A^2-Concentration of Product at Time t*Concentration of Reactant at Equilibrium))/(Initial Concentration of Reactant A^2*(Concentration of Reactant at Equilibrium-Concentration of Product at Time t))) to evaluate the Time, The Time taken for 2nd Order Opposed by 1st Order Reaction given Initial Conc of Reactant A formula is defined as the time interval required to convert a particular concentration reactant to a certain concentration of product in a First Order Opposed by First Order Reaction. Time is denoted by t symbol.

How to evaluate Time taken for 2nd Order Opposed by 1st Order Reaction given Initial Conc of Reactant A using this online evaluator? To use this online evaluator for Time taken for 2nd Order Opposed by 1st Order Reaction given Initial Conc of Reactant A, enter Forward Reaction Rate Constant for 2nd Order (k_f'), Concentration of Reactant at Equilibrium (x_eq), Initial Concentration of Reactant A (A₀) & Concentration of Product at Time t (x) and hit the calculate button.

FAQs on Time taken for 2nd Order Opposed by 1st Order Reaction given Initial Conc of Reactant A

What is the formula to find Time taken for 2nd Order Opposed by 1st Order Reaction given Initial Conc of Reactant A?

The formula of Time taken for 2nd Order Opposed by 1st Order Reaction given Initial Conc of Reactant A is expressed as Time = (1/Forward Reaction Rate Constant for 2nd Order)*(Concentration of Reactant at Equilibrium/((Initial Concentration of Reactant A^2)-(Concentration of Reactant at Equilibrium^2)))*ln((Concentration of Reactant at Equilibrium*(Initial Concentration of Reactant A^2-Concentration of Product at Time t*Concentration of Reactant at Equilibrium))/(Initial Concentration of Reactant A^2*(Concentration of Reactant at Equilibrium-Concentration of Product at Time t))). Here is an example- 2.329893 = (1/6.18E-06)*(70000/((100000^2)-(70000^2)))*ln((70000*(100000^2-27500*70000))/(100000^2*(70000-27500))).

How to calculate Time taken for 2nd Order Opposed by 1st Order Reaction given Initial Conc of Reactant A?

With Forward Reaction Rate Constant for 2nd Order (k_f'), Concentration of Reactant at Equilibrium (x_eq), Initial Concentration of Reactant A (A₀) & Concentration of Product at Time t (x) we can find Time taken for 2nd Order Opposed by 1st Order Reaction given Initial Conc of Reactant A using the formula - Time = (1/Forward Reaction Rate Constant for 2nd Order)*(Concentration of Reactant at Equilibrium/((Initial Concentration of Reactant A^2)-(Concentration of Reactant at Equilibrium^2)))*ln((Concentration of Reactant at Equilibrium*(Initial Concentration of Reactant A^2-Concentration of Product at Time t*Concentration of Reactant at Equilibrium))/(Initial Concentration of Reactant A^2*(Concentration of Reactant at Equilibrium-Concentration of Product at Time t))). This formula also uses Natural Logarithm (ln) function(s).

What are the other ways to Calculate Time?

Here are the different ways to Calculate Time-

Time=ln(Concentration of Reactant at Equilibrium/(Concentration of Reactant at Equilibrium-Concentration of Product at Time t))/(Forward Reaction Rate Constant+Backward Reaction Rate Constant)
Time=(1/Forward Reaction Rate Constant)*(Concentration of Reactant at Equilibrium/Initial Concentration of Reactant A)*ln(Concentration of Reactant at Equilibrium/(Concentration of Reactant at Equilibrium-Concentration of Product at Time t))
Time=1/Forward Reaction Rate Constant*ln(Concentration of Reactant at Equilibrium/(Concentration of Reactant at Equilibrium-Concentration of Product at Time t))*((Initial Concentration of Reactant B+Concentration of Reactant at Equilibrium)/(Initial Concentration of Reactant A+Initial Concentration of Reactant B))

Can the Time taken for 2nd Order Opposed by 1st Order Reaction given Initial Conc of Reactant A be negative?

Yes, the Time taken for 2nd Order Opposed by 1st Order Reaction given Initial Conc of Reactant A, measured in Time can be negative.

Which unit is used to measure Time taken for 2nd Order Opposed by 1st Order Reaction given Initial Conc of Reactant A?

Time taken for 2nd Order Opposed by 1st Order Reaction given Initial Conc of Reactant A is usually measured using the Second[s] for Time. Millisecond[s], Microsecond[s], Nanosecond[s] are the few other units in which Time taken for 2nd Order Opposed by 1st Order Reaction given Initial Conc of Reactant A can be measured.

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Time taken for 2nd Order Opposed by 1st Order Reaction given Initial Conc of Reactant A Formula

​GoTime taken for 1st Order Opposed by 1st Order Reaction Formula

​GoTime taken for 1st Order Opposed by 1st Order Reaction given Initial Concentration of Reactant Formula

Time taken for 2nd Order Opposed by 1st Order Reaction given Initial Conc of Reactant A Example

Time taken for 2nd Order Opposed by 1st Order Reaction given Initial Conc of Reactant A Solution

Time taken for 2nd Order Opposed by 1st Order Reaction given Initial Conc of Reactant A Formula Elements

Other Formulas to find Time

Other formulas in Second Order Opposed by First Order Reactions category

How to Evaluate Time taken for 2nd Order Opposed by 1st Order Reaction given Initial Conc of Reactant A?

FAQs on Time taken for 2nd Order Opposed by 1st Order Reaction given Initial Conc of Reactant A

Variable Name

GoTime taken for 1st Order Opposed by 1st Order Reaction Formula

GoTime taken for 1st Order Opposed by 1st Order Reaction given Initial Concentration of Reactant Formula