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Time Period of One Complete Oscillations Formula

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Time Period of Rolling is the time taken by a wave to complete one oscillation. Check FAQs

T = 2 \cdot π \cdot {(\frac{{k G}^{2}}{[g] \cdot GM})}^{\frac{1}{2}}

T - Time Period of Rolling?k_G - Radius of Gyration of Body?GM - Metacentric Height?[g] - Gravitational acceleration on Earth?π - Archimedes' constant?

Time Period of One Complete Oscillations Example

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Here is how the Time Period of One Complete Oscillations equation looks like with Values.

Here is how the Time Period of One Complete Oscillations equation looks like with Units.

Here is how the Time Period of One Complete Oscillations equation looks like.

5.4396 = 2 \cdot 3.1416 \cdot {(\frac{{0.105}^{2}}{9.8066 \cdot 0.0015})}^{\frac{1}{2}}

5.4396s = 2 \cdot 3.1416 \cdot {(\frac{{0.105m}^{2}}{9.8066m/s² \cdot 0.0015m})}^{\frac{1}{2}}

5.4396 = 2 \cdot 3.1416 \cdot {(\frac{{0.105}^{2}}{9.8066 \cdot 0.0015})}^{\frac{1}{2}}

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Time Period of One Complete Oscillations Solution

Follow our step by step solution on how to calculate Time Period of One Complete Oscillations?

FIRST Step Consider the formula

T = 2 \cdot π \cdot {(\frac{{k G}^{2}}{[g] \cdot GM})}^{\frac{1}{2}}

Next Step Substitute values of Variables

∴

T = 2 \cdot π \cdot {(\frac{{0.105m}^{2}}{[g] \cdot 0.0015m})}^{\frac{1}{2}}

Next Step Substitute values of Constants

∴

T = 2 \cdot 3.1416 \cdot {(\frac{{0.105m}^{2}}{9.8066m/s² \cdot 0.0015m})}^{\frac{1}{2}}

Next Step Prepare to Evaluate

∴

T = 2 \cdot 3.1416 \cdot {(\frac{{0.105}^{2}}{9.8066 \cdot 0.0015})}^{\frac{1}{2}}

Next Step Evaluate

∴

T = 5.43955284311121s

LAST Step Rounding Answer

∴

T = 5.4396s

Time Period of One Complete Oscillations Formula Elements

Variables

Constants

Time Period of Rolling

Time Period of Rolling is the time taken by a wave to complete one oscillation.

Symbol: T

Measurement: TimeUnit: s

Note: Value can be positive or negative.

Formulas to find Time Period of Rolling

Radius of Gyration of Body

The Radius of Gyration of Body is defined as the radial distance to a point that would have a moment of inertia the same as the body's actual distribution of mass.

Symbol: k_G

Measurement: LengthUnit: m

Note: Value can be positive or negative.

Formulas to find Radius of Gyration of Body

Metacentric Height

Metacentric Height is the vertical distance between the center of buoyance of the body and center of gravity.where B stands for center of buoyancy and G stands for center of gravity.

Symbol: GM

Measurement: LengthUnit: m

Note: Value can be positive or negative.

Formulas to find Metacentric Height

Gravitational acceleration on Earth

Gravitational acceleration on Earth means that the velocity of an object in free fall will increase by 9.8 m/s2 every second.

Symbol: [g]

Value: 9.80665 m/s²

Archimedes' constant

Archimedes' constant is a mathematical constant that represents the ratio of the circumference of a circle to its diameter.

Symbol: π

Value: 3.14159265358979323846264338327950288

Other formulas in Time Period of Transverse Oscillation of a Floating Body category

Go Radius of Gyration of Body given Time Period

k G = \sqrt{({(\frac{T}{2 \cdot π})}^{2}) \cdot ([g] \cdot GM)}

How to Evaluate Time Period of One Complete Oscillations?

Time Period of One Complete Oscillations evaluator uses Time Period of Rolling = 2*pi*(Radius of Gyration of Body^2/([g]*Metacentric Height))^(1/2) to evaluate the Time Period of Rolling, The Time Period of One Complete Oscillations pitching. The oscillatory motion of an object about its longitudinal axis is designated as rolling. Time Period of Rolling is denoted by T symbol.

How to evaluate Time Period of One Complete Oscillations using this online evaluator? To use this online evaluator for Time Period of One Complete Oscillations, enter Radius of Gyration of Body (k_G) & Metacentric Height (GM) and hit the calculate button.

FAQs on Time Period of One Complete Oscillations

What is the formula to find Time Period of One Complete Oscillations?

The formula of Time Period of One Complete Oscillations is expressed as Time Period of Rolling = 2*pi*(Radius of Gyration of Body^2/([g]*Metacentric Height))^(1/2). Here is an example- 5.439553 = 2*pi*(0.105^2/([g]*0.0015))^(1/2).

How to calculate Time Period of One Complete Oscillations?

With Radius of Gyration of Body (k_G) & Metacentric Height (GM) we can find Time Period of One Complete Oscillations using the formula - Time Period of Rolling = 2*pi*(Radius of Gyration of Body^2/([g]*Metacentric Height))^(1/2). This formula also uses Gravitational acceleration on Earth, Archimedes' constant .

Can the Time Period of One Complete Oscillations be negative?

Yes, the Time Period of One Complete Oscillations, measured in Time can be negative.

Which unit is used to measure Time Period of One Complete Oscillations?

Time Period of One Complete Oscillations is usually measured using the Second[s] for Time. Millisecond[s], Microsecond[s], Nanosecond[s] are the few other units in which Time Period of One Complete Oscillations can be measured.

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Time Period of One Complete Oscillations Formula

Time Period of One Complete Oscillations Example

Time Period of One Complete Oscillations Solution

Time Period of One Complete Oscillations Formula Elements

Other formulas in Time Period of Transverse Oscillation of a Floating Body category

How to Evaluate Time Period of One Complete Oscillations?

FAQs on Time Period of One Complete Oscillations

Variable Name