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Time refers to the ongoing and continuous sequence of events that occur in succession, from the past through the present to the future. Check FAQs
t=(2.303Ka)log((hdhw2),10)
t - Time?Ka - Specific Capacity?hd - Depression Head?hw2 - Depression Head in Well 2?

Time in Hours given Specific Capacity of Open Well with Base 10 Example

With values
With units
Only example

Here is how the Time in Hours given Specific Capacity of Open Well with Base 10 equation looks like with Values.

Here is how the Time in Hours given Specific Capacity of Open Well with Base 10 equation looks like with Units.

Here is how the Time in Hours given Specific Capacity of Open Well with Base 10 equation looks like.

2.6694Edit=(2.3032Edit)log((27Edit10Edit),10)
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Time in Hours given Specific Capacity of Open Well with Base 10 Solution

Follow our step by step solution on how to calculate Time in Hours given Specific Capacity of Open Well with Base 10?

FIRST Step Consider the formula
t=(2.303Ka)log((hdhw2),10)
Next Step Substitute values of Variables
t=(2.3032m/h)log((27m10m),10)
Next Step Convert Units
t=(2.3030.0006m/s)log((27m10m),10)
Next Step Prepare to Evaluate
t=(2.3030.0006)log((2710),10)
Next Step Evaluate
t=9609.98661554736s
Next Step Convert to Output's Unit
t=2.66944072654093h
LAST Step Rounding Answer
t=2.6694h

Time in Hours given Specific Capacity of Open Well with Base 10 Formula Elements

Variables
Functions
Time
Time refers to the ongoing and continuous sequence of events that occur in succession, from the past through the present to the future.
Symbol: t
Measurement: TimeUnit: h
Note: Value should be greater than 0.
Specific Capacity
Specific Capacity is capacity of an open well.
Symbol: Ka
Measurement: SpeedUnit: m/h
Note: Value should be greater than 0.
Depression Head
Depression Head is the difference of level of waters table and the water level in the well when pumping stopped.
Symbol: hd
Measurement: LengthUnit: m
Note: Value should be greater than 0.
Depression Head in Well 2
Depression Head in Well 2 is depression head in the well at a time T after the pumping stopped.
Symbol: hw2
Measurement: LengthUnit: m
Note: Value should be greater than 0.
log
Logarithmic function is an inverse function to exponentiation.
Syntax: log(Base, Number)

Other Formulas to find Time

​Go Time in Hours given Specific Capacity of Open Well
t=(1Ka)log((hdhw2),e)

Other formulas in Discharge from Well category

​Go Discharge from Well given Specific Capacity
Q=SsiAcswH'
​Go Discharge from Well given Specific Capacity for Clay Soil
Q=0.25AcswH''
​Go Discharge from Well given Specific Capacity for Fine Sand
Q=0.5AcswHf
​Go Discharge from Well given Specific Capacity for Coarse Sand
Q=1AcswHc

How to Evaluate Time in Hours given Specific Capacity of Open Well with Base 10?

Time in Hours given Specific Capacity of Open Well with Base 10 evaluator uses Time = (2.303/Specific Capacity)*log((Depression Head/Depression Head in Well 2),10) to evaluate the Time, The Time in Hours given Specific Capacity of Open Well with Base 10 formula is defined as the calculation of value of time in hours when we have prior information of other parameters used. Time is denoted by t symbol.

How to evaluate Time in Hours given Specific Capacity of Open Well with Base 10 using this online evaluator? To use this online evaluator for Time in Hours given Specific Capacity of Open Well with Base 10, enter Specific Capacity (Ka), Depression Head (hd) & Depression Head in Well 2 (hw2) and hit the calculate button.

FAQs on Time in Hours given Specific Capacity of Open Well with Base 10

What is the formula to find Time in Hours given Specific Capacity of Open Well with Base 10?
The formula of Time in Hours given Specific Capacity of Open Well with Base 10 is expressed as Time = (2.303/Specific Capacity)*log((Depression Head/Depression Head in Well 2),10). Here is an example- 0.000742 = (2.303/0.000555555555555556)*log((27/10),10).
How to calculate Time in Hours given Specific Capacity of Open Well with Base 10?
With Specific Capacity (Ka), Depression Head (hd) & Depression Head in Well 2 (hw2) we can find Time in Hours given Specific Capacity of Open Well with Base 10 using the formula - Time = (2.303/Specific Capacity)*log((Depression Head/Depression Head in Well 2),10). This formula also uses Logarithmic Inverse (log) function(s).
What are the other ways to Calculate Time?
Here are the different ways to Calculate Time-
  • Time=(1/Specific Capacity)*log((Depression Head/Depression Head in Well 2),e)OpenImg
Can the Time in Hours given Specific Capacity of Open Well with Base 10 be negative?
No, the Time in Hours given Specific Capacity of Open Well with Base 10, measured in Time cannot be negative.
Which unit is used to measure Time in Hours given Specific Capacity of Open Well with Base 10?
Time in Hours given Specific Capacity of Open Well with Base 10 is usually measured using the Hour[h] for Time. Second[h], Millisecond[h], Microsecond[h] are the few other units in which Time in Hours given Specific Capacity of Open Well with Base 10 can be measured.
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