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Time refers to the ongoing and continuous sequence of events that occur in succession, from the past through the present to the future. Check FAQs
t=(10.5)log((hdhw2),e)
t - Time?hd - Depression Head?hw2 - Depression Head in Well 2?

Time in Hours given Fine Sand Example

With values
With units
Only example

Here is how the Time in Hours given Fine Sand equation looks like with Values.

Here is how the Time in Hours given Fine Sand equation looks like with Units.

Here is how the Time in Hours given Fine Sand equation looks like.

2.0136Edit=(10.5)log((27Edit10Edit),e)
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Time in Hours given Fine Sand Solution

Follow our step by step solution on how to calculate Time in Hours given Fine Sand?

FIRST Step Consider the formula
t=(10.5)log((hdhw2),e)
Next Step Substitute values of Variables
t=(10.5)log((27m10m),e)
Next Step Prepare to Evaluate
t=(10.5)log((2710),e)
Next Step Evaluate
t=7248.91733963757s
Next Step Convert to Output's Unit
t=2.01358814989932h
LAST Step Rounding Answer
t=2.0136h

Time in Hours given Fine Sand Formula Elements

Variables
Functions
Time
Time refers to the ongoing and continuous sequence of events that occur in succession, from the past through the present to the future.
Symbol: t
Measurement: TimeUnit: h
Note: Value should be greater than 0.
Depression Head
Depression Head is the difference of level of waters table and the water level in the well when pumping stopped.
Symbol: hd
Measurement: LengthUnit: m
Note: Value should be greater than 0.
Depression Head in Well 2
Depression Head in Well 2 is depression head in the well at a time T after the pumping stopped.
Symbol: hw2
Measurement: LengthUnit: m
Note: Value should be greater than 0.
log
Logarithmic function is an inverse function to exponentiation.
Syntax: log(Base, Number)

Other Formulas to find Time

​Go Time in Hours given Clay Soil
t=(10.25)log((hdhw2),e)
​Go Time in Hours with Base 10 given Fine Sand
t=(2.3030.5)log((hdhw2),10)
​Go Time in Hours given Coarse Sand
t=log((hdhw2),e)
​Go Time in Hours with Base 10 given Coarse Sand
t=(2.3031)log((hdhw2),10)

How to Evaluate Time in Hours given Fine Sand?

Time in Hours given Fine Sand evaluator uses Time = (1/0.5)*log((Depression Head/Depression Head in Well 2),e) to evaluate the Time, The Time in Hours given Fine Sand formula is defined as the calculation of the value of time in hours when we have prior information of soil available. Time is denoted by t symbol.

How to evaluate Time in Hours given Fine Sand using this online evaluator? To use this online evaluator for Time in Hours given Fine Sand, enter Depression Head (hd) & Depression Head in Well 2 (hw2) and hit the calculate button.

FAQs on Time in Hours given Fine Sand

What is the formula to find Time in Hours given Fine Sand?
The formula of Time in Hours given Fine Sand is expressed as Time = (1/0.5)*log((Depression Head/Depression Head in Well 2),e). Here is an example- 0.000559 = (1/0.5)*log((27/10),e).
How to calculate Time in Hours given Fine Sand?
With Depression Head (hd) & Depression Head in Well 2 (hw2) we can find Time in Hours given Fine Sand using the formula - Time = (1/0.5)*log((Depression Head/Depression Head in Well 2),e). This formula also uses Logarithmic Inverse (log) function(s).
What are the other ways to Calculate Time?
Here are the different ways to Calculate Time-
  • Time=(1/0.25)*log((Depression Head/Depression Head in Well 2),e)OpenImg
  • Time=(2.303/0.5)*log((Depression Head/Depression Head in Well 2),10)OpenImg
  • Time=log((Depression Head/Depression Head in Well 2),e)OpenImg
Can the Time in Hours given Fine Sand be negative?
No, the Time in Hours given Fine Sand, measured in Time cannot be negative.
Which unit is used to measure Time in Hours given Fine Sand?
Time in Hours given Fine Sand is usually measured using the Hour[h] for Time. Second[h], Millisecond[h], Microsecond[h] are the few other units in which Time in Hours given Fine Sand can be measured.
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