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Time in Hours given Constant Depression Head and Area of Well Formula

GoTime in Hours given Clay Soil Formula

GoTime in Hours given Fine Sand Formula

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Time refers to the ongoing and continuous sequence of events that occur in succession, from the past through the present to the future. Check FAQs

t = \frac{2.303 \cdot A csw \cdot H' \cdot \log ((\frac{h d}{h w2}), 10)}{Q}

t - Time?A_csw - Cross-Sectional Area of Well?H' - Constant Depression Head?h_d - Depression Head?h_w2 - Depression Head in Well 2?Q - Discharge in Well?

Time in Hours given Constant Depression Head and Area of Well Example

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Here is how the Time in Hours given Constant Depression Head and Area of Well equation looks like with Values.

Here is how the Time in Hours given Constant Depression Head and Area of Well equation looks like with Units.

Here is how the Time in Hours given Constant Depression Head and Area of Well equation looks like.

2.664 = \frac{2.303 \cdot 13 \cdot 0.038 \cdot \log ((\frac{27}{10}), 10)}{0.99}

2.664h = \frac{2.303 \cdot 13m² \cdot 0.038 \cdot \log ((\frac{27m}{10m}), 10)}{0.99m³/s}

2.664 = \frac{2.303 \cdot 13 \cdot 0.038 \cdot \log ((\frac{27}{10}), 10)}{0.99}

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Time in Hours given Constant Depression Head and Area of Well Solution

Follow our step by step solution on how to calculate Time in Hours given Constant Depression Head and Area of Well?

FIRST Step Consider the formula

t = \frac{2.303 \cdot A csw \cdot H' \cdot \log ((\frac{h d}{h w2}), 10)}{Q}

Next Step Substitute values of Variables

∴

t = \frac{2.303 \cdot 13m² \cdot 0.038 \cdot \log ((\frac{27m}{10m}), 10)}{0.99m³/s}

Next Step Prepare to Evaluate

∴

t = \frac{2.303 \cdot 13 \cdot 0.038 \cdot \log ((\frac{27}{10}), 10)}{0.99}

Next Step Evaluate

∴

t = 9590.57250117253s

Next Step Convert to Output's Unit

∴

t = 2.66404791699237h

LAST Step Rounding Answer

∴

t = 2.664h

Time in Hours given Constant Depression Head and Area of Well Formula Elements

Variables

Functions

Time

Time refers to the ongoing and continuous sequence of events that occur in succession, from the past through the present to the future.

Symbol: t

Measurement: TimeUnit: h

Note: Value should be greater than 0.

Formulas to find Time

Cross-Sectional Area of Well

Cross-Sectional Area of Well is the the surface area of the interior opening of the well.

Symbol: A_csw

Measurement: AreaUnit: m²

Note: Value should be greater than 0.

Formulas to find Cross-Sectional Area of Well

Constant Depression Head

Constant Depression Head is the constant value of head in the well.

Symbol: H'

Measurement: NAUnit: Unitless

Note: Value should be greater than 0.

Formulas to find Constant Depression Head

Depression Head

Depression Head is the difference of level of waters table and the water level in the well when pumping stopped.

Symbol: h_d

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Depression Head

Depression Head in Well 2

Depression Head in Well 2 is depression head in the well at a time T after the pumping stopped.

Symbol: h_w2

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Depression Head in Well 2

Discharge in Well

Discharge in Well is the rate of flow of a liquid in well.

Symbol: Q

Measurement: Volumetric Flow RateUnit: m³/s

Note: Value can be positive or negative.

Formulas to find Discharge in Well

log

Logarithmic function is an inverse function to exponentiation.

Syntax: log(Base, Number)

Other Formulas to find Time

Go Time in Hours given Clay Soil

t = (\frac{1}{0.25}) \cdot \log ((\frac{h d}{h w2}), e)

Go Time in Hours given Fine Sand

t = (\frac{1}{0.5}) \cdot \log ((\frac{h d}{h w2}), e)

Go Time in Hours with Base 10 given Fine Sand

t = (\frac{2.303}{0.5}) \cdot \log ((\frac{h d}{h w2}), 10)

Go Time in Hours given Coarse Sand

t = \log ((\frac{h d}{h w2}), e)

How to Evaluate Time in Hours given Constant Depression Head and Area of Well?

Time in Hours given Constant Depression Head and Area of Well evaluator uses Time = (2.303*Cross-Sectional Area of Well*Constant Depression Head*log((Depression Head/Depression Head in Well 2),10))/Discharge in Well to evaluate the Time, The Time in Hours given Constant Depression Head and Area of Well formula is defined as the calculation of the value of time in hours when we have prior information of constant depression head and area of well. Time is denoted by t symbol.

How to evaluate Time in Hours given Constant Depression Head and Area of Well using this online evaluator? To use this online evaluator for Time in Hours given Constant Depression Head and Area of Well, enter Cross-Sectional Area of Well (A_csw), Constant Depression Head (H'), Depression Head (h_d), Depression Head in Well 2 (h_w2) & Discharge in Well (Q) and hit the calculate button.

FAQs on Time in Hours given Constant Depression Head and Area of Well

What is the formula to find Time in Hours given Constant Depression Head and Area of Well?

The formula of Time in Hours given Constant Depression Head and Area of Well is expressed as Time = (2.303*Cross-Sectional Area of Well*Constant Depression Head*log((Depression Head/Depression Head in Well 2),10))/Discharge in Well. Here is an example- 0.000725 = (2.303*13*0.038*log((27/10),10))/0.99.

How to calculate Time in Hours given Constant Depression Head and Area of Well?

With Cross-Sectional Area of Well (A_csw), Constant Depression Head (H'), Depression Head (h_d), Depression Head in Well 2 (h_w2) & Discharge in Well (Q) we can find Time in Hours given Constant Depression Head and Area of Well using the formula - Time = (2.303*Cross-Sectional Area of Well*Constant Depression Head*log((Depression Head/Depression Head in Well 2),10))/Discharge in Well. This formula also uses Logarithmic Inverse (log) function(s).

What are the other ways to Calculate Time?

Here are the different ways to Calculate Time-

Time=(1/0.25)*log((Depression Head/Depression Head in Well 2),e)
Time=(1/0.5)*log((Depression Head/Depression Head in Well 2),e)
Time=(2.303/0.5)*log((Depression Head/Depression Head in Well 2),10)

Can the Time in Hours given Constant Depression Head and Area of Well be negative?

No, the Time in Hours given Constant Depression Head and Area of Well, measured in Time cannot be negative.

Which unit is used to measure Time in Hours given Constant Depression Head and Area of Well?

Time in Hours given Constant Depression Head and Area of Well is usually measured using the Hour[h] for Time. Second[h], Millisecond[h], Microsecond[h] are the few other units in which Time in Hours given Constant Depression Head and Area of Well can be measured.

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Time in Hours given Constant Depression Head and Area of Well Formula

​GoTime in Hours given Clay Soil Formula

​GoTime in Hours given Fine Sand Formula

Time in Hours given Constant Depression Head and Area of Well Example

Time in Hours given Constant Depression Head and Area of Well Solution

Time in Hours given Constant Depression Head and Area of Well Formula Elements

Other Formulas to find Time

How to Evaluate Time in Hours given Constant Depression Head and Area of Well?

FAQs on Time in Hours given Constant Depression Head and Area of Well

Variable Name

GoTime in Hours given Clay Soil Formula

GoTime in Hours given Fine Sand Formula