FormulaDen.com

Physics Chemistry Math Chemical Engineering Civil Electrical Electronics Electronics and Instrumentation Materials Science Mechanical Production Engineering Financial Health

Thermal conductivity for pipe with eccentric lagging Formula

Fx Copy

LaTeX Copy

Eccentric Lagging Thermal Conductivity is expressed as amount of heat flows per unit time through a unit area with a temperature gradient of one degree per unit distance. Check FAQs

k e = \frac{Q e \cdot (\ln (\frac{\sqrt{({(r 2 + r 1)}^{2}) - e^{2}} + \sqrt{({(r 2 - r 1)}^{2}) - e^{2}}}{\sqrt{({(r 2 + r 1)}^{2}) - e^{2}} - \sqrt{({(r 2 - r 1)}^{2}) - e^{2}}}))}{2 \cdot π \cdot L e \cdot (T ie - T oe)}

k_e - Eccentric Lagging Thermal Conductivity?Q_e - Eccentric Lagging Heat Flow Rate?r₂ - Radius 2?r₁ - Radius 1?e - Distance Between Centers of Eccentric Circles?L_e - Eccentric Lagging Length?T_ie - Eccentric Lagging Inner Surface Temperature?T_oe - Eccentric Lagging Outer Surface Temperature?π - Archimedes' constant?

Thermal conductivity for pipe with eccentric lagging Example

With values

With units

Only example

Here is how the Thermal conductivity for pipe with eccentric lagging equation looks like with Values.

Here is how the Thermal conductivity for pipe with eccentric lagging equation looks like with Units.

Here is how the Thermal conductivity for pipe with eccentric lagging equation looks like.

15 = \frac{3021.485 \cdot (\ln (\frac{\sqrt{({(12.1 + 4)}^{2}) - {1.4}^{2}} + \sqrt{({(12.1 - 4)}^{2}) - {1.4}^{2}}}{\sqrt{({(12.1 + 4)}^{2}) - {1.4}^{2}} - \sqrt{({(12.1 - 4)}^{2}) - {1.4}^{2}}}))}{2 \cdot 3.1416 \cdot 7 \cdot (25 - 20)}

15W/(m*K) = \frac{3021.485W \cdot (\ln (\frac{\sqrt{({(12.1m + 4m)}^{2}) - {1.4m}^{2}} + \sqrt{({(12.1m - 4m)}^{2}) - {1.4m}^{2}}}{\sqrt{({(12.1m + 4m)}^{2}) - {1.4m}^{2}} - \sqrt{({(12.1m - 4m)}^{2}) - {1.4m}^{2}}}))}{2 \cdot 3.1416 \cdot 7m \cdot (25K - 20K)}

15 = \frac{3021.485 \cdot (\ln (\frac{\sqrt{({(12.1 + 4)}^{2}) - {1.4}^{2}} + \sqrt{({(12.1 - 4)}^{2}) - {1.4}^{2}}}{\sqrt{({(12.1 + 4)}^{2}) - {1.4}^{2}} - \sqrt{({(12.1 - 4)}^{2}) - {1.4}^{2}}}))}{2 \cdot 3.1416 \cdot 7 \cdot (25 - 20)}

Tip: Use pencil ( Pencil

) icon above to edit Input Values and Units.

Calculate

Recalculate

Solution

Copy

Reset

You are here -

Home » Category

Physics » Category

Mechanical » Category

Heat and Mass Transfer » fx Thermal conductivity for pipe with eccentric lagging

Thermal conductivity for pipe with eccentric lagging Solution

Follow our step by step solution on how to calculate Thermal conductivity for pipe with eccentric lagging?

FIRST Step Consider the formula

k e = \frac{Q e \cdot (\ln (\frac{\sqrt{({(r 2 + r 1)}^{2}) - e^{2}} + \sqrt{({(r 2 - r 1)}^{2}) - e^{2}}}{\sqrt{({(r 2 + r 1)}^{2}) - e^{2}} - \sqrt{({(r 2 - r 1)}^{2}) - e^{2}}}))}{2 \cdot π \cdot L e \cdot (T ie - T oe)}

Next Step Substitute values of Variables

∴

k e = \frac{3021.485W \cdot (\ln (\frac{\sqrt{({(12.1m + 4m)}^{2}) - {1.4m}^{2}} + \sqrt{({(12.1m - 4m)}^{2}) - {1.4m}^{2}}}{\sqrt{({(12.1m + 4m)}^{2}) - {1.4m}^{2}} - \sqrt{({(12.1m - 4m)}^{2}) - {1.4m}^{2}}}))}{2 \cdot π \cdot 7m \cdot (25K - 20K)}

Next Step Substitute values of Constants

∴

k e = \frac{3021.485W \cdot (\ln (\frac{\sqrt{({(12.1m + 4m)}^{2}) - {1.4m}^{2}} + \sqrt{({(12.1m - 4m)}^{2}) - {1.4m}^{2}}}{\sqrt{({(12.1m + 4m)}^{2}) - {1.4m}^{2}} - \sqrt{({(12.1m - 4m)}^{2}) - {1.4m}^{2}}}))}{2 \cdot 3.1416 \cdot 7m \cdot (25K - 20K)}

Next Step Prepare to Evaluate

∴

k e = \frac{3021.485 \cdot (\ln (\frac{\sqrt{({(12.1 + 4)}^{2}) - {1.4}^{2}} + \sqrt{({(12.1 - 4)}^{2}) - {1.4}^{2}}}{\sqrt{({(12.1 + 4)}^{2}) - {1.4}^{2}} - \sqrt{({(12.1 - 4)}^{2}) - {1.4}^{2}}}))}{2 \cdot 3.1416 \cdot 7 \cdot (25 - 20)}

Next Step Evaluate

∴

k e = 15.0000006425146W/(m*K)

LAST Step Rounding Answer

∴

k e = 15W/(m*K)

Thermal conductivity for pipe with eccentric lagging Formula Elements

Variables

Constants

Functions

Eccentric Lagging Thermal Conductivity

Eccentric Lagging Thermal Conductivity is expressed as amount of heat flows per unit time through a unit area with a temperature gradient of one degree per unit distance.

Symbol: k_e

Measurement: Thermal ConductivityUnit: W/(m*K)

Note: Value should be greater than 0.

Formulas to find Eccentric Lagging Thermal Conductivity

Eccentric Lagging Heat Flow Rate

Eccentric lagging Heat Flow Rate is the amount of heat that is transferred per unit of time in some material. Heat is the flow of thermal energy driven by thermal non-equilibrium.

Symbol: Q_e

Measurement: PowerUnit: W

Note: Value can be positive or negative.

Formulas to find Eccentric Lagging Heat Flow Rate

Radius 2

Radius 2 is the radius of the second concentric circle or circle.

Symbol: r₂

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Radius 2

Radius 1

Radius 1 is the distance from the center of the concentric circles to any point on the first/smallest concentric circle or the radius of the first circle.

Symbol: r₁

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Radius 1

Distance Between Centers of Eccentric Circles

Distance Between Centers of Eccentric Circles is the distance between the centres of two circles that are eccentric to each other.

Symbol: e

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Distance Between Centers of Eccentric Circles

Eccentric Lagging Length

Eccentric Lagging Length is the measurement or extent of something from end to end.

Symbol: L_e

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Eccentric Lagging Length

Eccentric Lagging Inner Surface Temperature

Eccentric Lagging Inner Surface Temperature is the temperature at the inner surface of the wall either plane wall or cylindrical wall or spherical wall, etc.

Symbol: T_ie

Measurement: TemperatureUnit: K

Note: Value can be positive or negative.

Formulas to find Eccentric Lagging Inner Surface Temperature

Eccentric Lagging Outer Surface Temperature

Eccentric Lagging Outer surface temperature is the temperature at the outer surface of the wall (either plane wall or cylindrical wall or spherical wall, etc).

Symbol: T_oe

Measurement: TemperatureUnit: K

Note: Value can be positive or negative.

Formulas to find Eccentric Lagging Outer Surface Temperature

Archimedes' constant

Archimedes' constant is a mathematical constant that represents the ratio of the circumference of a circle to its diameter.

Symbol: π

Value: 3.14159265358979323846264338327950288

The natural logarithm, also known as the logarithm to the base e, is the inverse function of the natural exponential function.

Syntax: ln(Number)

sqrt

A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number.

Syntax: sqrt(Number)

Other formulas in Other shapes category

Go Thermal Resistance for Pipe in Square Section

R th = (\frac{1}{2 \cdot π \cdot L}) \cdot ((\frac{1}{h i \cdot R}) + ((\frac{L}{k}) \cdot \ln (\frac{1.08 \cdot a}{2 \cdot R})) + (\frac{π}{2 \cdot h o \cdot a}))

Go Thermal resistance of pipe with eccentric lagging

r th = (\frac{1}{2 \cdot π \cdot k e \cdot L e}) \cdot (\ln (\frac{\sqrt{({(r 2 + r 1)}^{2}) - e^{2}} + \sqrt{({(r 2 - r 1)}^{2}) - e^{2}}}{\sqrt{({(r 2 + r 1)}^{2}) - e^{2}} - \sqrt{({(r 2 - r 1)}^{2}) - e^{2}}}))

How to Evaluate Thermal conductivity for pipe with eccentric lagging?

Thermal conductivity for pipe with eccentric lagging evaluator uses Eccentric Lagging Thermal Conductivity = (Eccentric Lagging Heat Flow Rate*(ln((sqrt(((Radius 2+Radius 1)^2)-Distance Between Centers of Eccentric Circles^2)+sqrt(((Radius 2-Radius 1)^2)-Distance Between Centers of Eccentric Circles^2))/(sqrt(((Radius 2+Radius 1)^2)-Distance Between Centers of Eccentric Circles^2)-sqrt(((Radius 2-Radius 1)^2)-Distance Between Centers of Eccentric Circles^2)))))/(2*pi*Eccentric Lagging Length*(Eccentric Lagging Inner Surface Temperature-Eccentric Lagging Outer Surface Temperature)) to evaluate the Eccentric Lagging Thermal Conductivity, The Thermal conductivity for pipe with eccentric lagging formula is defined as the thermal conductivity of the material of the pipe with eccentric lagging required to maintain the given temperature difference across its inner and outer surfaces. Eccentric Lagging Thermal Conductivity is denoted by k_e symbol.

How to evaluate Thermal conductivity for pipe with eccentric lagging using this online evaluator? To use this online evaluator for Thermal conductivity for pipe with eccentric lagging, enter Eccentric Lagging Heat Flow Rate (Q_e), Radius 2 (r₂), Radius 1 (r₁), Distance Between Centers of Eccentric Circles (e), Eccentric Lagging Length (L_e), Eccentric Lagging Inner Surface Temperature (T_ie) & Eccentric Lagging Outer Surface Temperature (T_oe) and hit the calculate button.

FAQs on Thermal conductivity for pipe with eccentric lagging

What is the formula to find Thermal conductivity for pipe with eccentric lagging?

The formula of Thermal conductivity for pipe with eccentric lagging is expressed as Eccentric Lagging Thermal Conductivity = (Eccentric Lagging Heat Flow Rate*(ln((sqrt(((Radius 2+Radius 1)^2)-Distance Between Centers of Eccentric Circles^2)+sqrt(((Radius 2-Radius 1)^2)-Distance Between Centers of Eccentric Circles^2))/(sqrt(((Radius 2+Radius 1)^2)-Distance Between Centers of Eccentric Circles^2)-sqrt(((Radius 2-Radius 1)^2)-Distance Between Centers of Eccentric Circles^2)))))/(2*pi*Eccentric Lagging Length*(Eccentric Lagging Inner Surface Temperature-Eccentric Lagging Outer Surface Temperature)). Here is an example- 0.496445 = (3021.485*(ln((sqrt(((12.1+4)^2)-1.4^2)+sqrt(((12.1-4)^2)-1.4^2))/(sqrt(((12.1+4)^2)-1.4^2)-sqrt(((12.1-4)^2)-1.4^2)))))/(2*pi*7*(25-20)).

How to calculate Thermal conductivity for pipe with eccentric lagging?

With Eccentric Lagging Heat Flow Rate (Q_e), Radius 2 (r₂), Radius 1 (r₁), Distance Between Centers of Eccentric Circles (e), Eccentric Lagging Length (L_e), Eccentric Lagging Inner Surface Temperature (T_ie) & Eccentric Lagging Outer Surface Temperature (T_oe) we can find Thermal conductivity for pipe with eccentric lagging using the formula - Eccentric Lagging Thermal Conductivity = (Eccentric Lagging Heat Flow Rate*(ln((sqrt(((Radius 2+Radius 1)^2)-Distance Between Centers of Eccentric Circles^2)+sqrt(((Radius 2-Radius 1)^2)-Distance Between Centers of Eccentric Circles^2))/(sqrt(((Radius 2+Radius 1)^2)-Distance Between Centers of Eccentric Circles^2)-sqrt(((Radius 2-Radius 1)^2)-Distance Between Centers of Eccentric Circles^2)))))/(2*pi*Eccentric Lagging Length*(Eccentric Lagging Inner Surface Temperature-Eccentric Lagging Outer Surface Temperature)). This formula also uses Archimedes' constant and , Natural Logarithm (ln), Square Root (sqrt) function(s).

Can the Thermal conductivity for pipe with eccentric lagging be negative?

No, the Thermal conductivity for pipe with eccentric lagging, measured in Thermal Conductivity cannot be negative.

Which unit is used to measure Thermal conductivity for pipe with eccentric lagging?

Thermal conductivity for pipe with eccentric lagging is usually measured using the Watt per Meter per K[W/(m*K)] for Thermal Conductivity. Kilowatt per Meter per K[W/(m*K)], Calorie (IT) per Second per Centimeter per °C[W/(m*K)], Kilocalorie (th) per Hour per Meter per °C[W/(m*K)] are the few other units in which Thermal conductivity for pipe with eccentric lagging can be measured.

Let Others Know

✖

Facebook

Twitter

Copied!

: Value
: Unit

Thermal conductivity for pipe with eccentric lagging Formula

Thermal conductivity for pipe with eccentric lagging Example

Thermal conductivity for pipe with eccentric lagging Solution

Thermal conductivity for pipe with eccentric lagging Formula Elements

Other formulas in Other shapes category

How to Evaluate Thermal conductivity for pipe with eccentric lagging?

FAQs on Thermal conductivity for pipe with eccentric lagging

Variable Name