FormulaDen.com

Physics Chemistry Math Chemical Engineering Civil Electrical Electronics Electronics and Instrumentation Materials Science Mechanical Production Engineering Financial Health

Tension in String if only One Body is Freely Suspended Formula

Fx Copy

LaTeX Copy

Tension in freely Suspended String is the force exerted by the string on the hanging object, opposing its weight, and keeping it in equilibrium. Check FAQs

T fs = \frac{m 1 \cdot m 2}{m 1 + m 2} \cdot [g]

T_fs - Tension in Freely Suspended String?m₁ - Mass of Left Body?m₂ - Mass of Right Body?[g] - Gravitational acceleration on Earth?

Tension in String if only One Body is Freely Suspended Example

With values

With units

Only example

Here is how the Tension in String if only One Body is Freely Suspended equation looks like with Values.

Here is how the Tension in String if only One Body is Freely Suspended equation looks like with Units.

Here is how the Tension in String if only One Body is Freely Suspended equation looks like.

90.4278 = \frac{29 \cdot 13.52}{29 + 13.52} \cdot 9.8066

90.4278N = \frac{29kg \cdot 13.52kg}{29kg + 13.52kg} \cdot 9.8066m/s²

90.4278 = \frac{29 \cdot 13.52}{29 + 13.52} \cdot 9.8066

Tip: Use pencil ( Pencil

) icon above to edit Input Values and Units.

Calculate

Recalculate

Solution

Copy

Reset

You are here -

Home » Category

Physics » Category

Mechanical » Category

Mechanics » fx Tension in String if only One Body is Freely Suspended

Tension in String if only One Body is Freely Suspended Solution

Follow our step by step solution on how to calculate Tension in String if only One Body is Freely Suspended?

FIRST Step Consider the formula

T fs = \frac{m 1 \cdot m 2}{m 1 + m 2} \cdot [g]

Next Step Substitute values of Variables

∴

T fs = \frac{29kg \cdot 13.52kg}{29kg + 13.52kg} \cdot [g]

Next Step Substitute values of Constants

∴

T fs = \frac{29kg \cdot 13.52kg}{29kg + 13.52kg} \cdot 9.8066m/s²

Next Step Prepare to Evaluate

∴

T fs = \frac{29 \cdot 13.52}{29 + 13.52} \cdot 9.8066

Next Step Evaluate

∴

T fs = 90.4278300094073N

LAST Step Rounding Answer

∴

T fs = 90.4278N

Tension in String if only One Body is Freely Suspended Formula Elements

Variables

Constants

Tension in Freely Suspended String

Tension in freely Suspended String is the force exerted by the string on the hanging object, opposing its weight, and keeping it in equilibrium.

Symbol: T_fs

Measurement: ForceUnit: N

Note: Value can be positive or negative.

Formulas to find Tension in Freely Suspended String

Mass of Left Body

Mass of Left Body is the amount of matter in an object hanging from a string, which affects the motion of the system.

Symbol: m₁

Measurement: WeightUnit: kg

Note: Value should be greater than 0.

Formulas to find Mass of Left Body

Mass of Right Body

Mass of Right Body is the amount of matter in an object hanging from a string, which affects its motion and oscillations.

Symbol: m₂

Measurement: WeightUnit: kg

Note: Value should be greater than 0.

Formulas to find Mass of Right Body

Gravitational acceleration on Earth

Gravitational acceleration on Earth means that the velocity of an object in free fall will increase by 9.8 m/s2 every second.

Symbol: [g]

Value: 9.80665 m/s²

Other formulas in Body Lying on Smooth Horizontal Plane category

Go Acceleration in System

a b = \frac{m 1}{m 1 + m 2} \cdot [g]

How to Evaluate Tension in String if only One Body is Freely Suspended?

Tension in String if only One Body is Freely Suspended evaluator uses Tension in Freely Suspended String = (Mass of Left Body*Mass of Right Body)/(Mass of Left Body+Mass of Right Body)*[g] to evaluate the Tension in Freely Suspended String, Tension in String if only One Body is Freely Suspended formula is defined as a measure of the force exerted by a string on an object when one body is freely suspended, providing a way to quantify the string's force in relation to the masses of the objects involved. Tension in Freely Suspended String is denoted by T_fs symbol.

How to evaluate Tension in String if only One Body is Freely Suspended using this online evaluator? To use this online evaluator for Tension in String if only One Body is Freely Suspended, enter Mass of Left Body (m₁) & Mass of Right Body (m₂) and hit the calculate button.

FAQs on Tension in String if only One Body is Freely Suspended

What is the formula to find Tension in String if only One Body is Freely Suspended?

The formula of Tension in String if only One Body is Freely Suspended is expressed as Tension in Freely Suspended String = (Mass of Left Body*Mass of Right Body)/(Mass of Left Body+Mass of Right Body)*[g]. Here is an example- 90.42783 = (29*13.52)/(29+13.52)*[g].

How to calculate Tension in String if only One Body is Freely Suspended?

With Mass of Left Body (m₁) & Mass of Right Body (m₂) we can find Tension in String if only One Body is Freely Suspended using the formula - Tension in Freely Suspended String = (Mass of Left Body*Mass of Right Body)/(Mass of Left Body+Mass of Right Body)*[g]. This formula also uses Gravitational acceleration on Earth constant(s).

Can the Tension in String if only One Body is Freely Suspended be negative?

Yes, the Tension in String if only One Body is Freely Suspended, measured in Force can be negative.

Which unit is used to measure Tension in String if only One Body is Freely Suspended?

Tension in String if only One Body is Freely Suspended is usually measured using the Newton[N] for Force. Exanewton[N], Meganewton[N], Kilonewton[N] are the few other units in which Tension in String if only One Body is Freely Suspended can be measured.

Let Others Know

✖

Facebook

Twitter

Copied!

: Value
: Unit