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Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters Formula

GoTemperature of Real Gas using Clausius Equation Formula

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Temperature given CE is the degree or intensity of heat present in a substance or object. Check FAQs

T CE = ((P r \cdot P' c) + (\frac{a}{({((V' m,r \cdot V m,c) + c)}^{2})})) \cdot (\frac{(V' m,r \cdot V m,c) - b'}{[R]})

T_CE - Temperature given CE?P_r - Reduced Pressure?P'_c - Critical Pressure of Real Gas?a - Clausius Parameter a?V'_m,r - Reduced Molar Volume for Real Gas?V_m,c - Critical Molar Volume?c - Clausius Parameter c?b' - Clausius Parameter b for Real Gas?[R] - Universal gas constant?

Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters Example

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Here is how the Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters equation looks like with Values.

Here is how the Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters equation looks like with Units.

Here is how the Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters equation looks like.

4.6E+7 = ((0.8 \cdot 4.6E+6) + (\frac{0.1}{({((8.96 \cdot 11.5) + 0.0002)}^{2})})) \cdot (\frac{(8.96 \cdot 11.5) - 0.0024}{8.3145})

4.6E+7K = ((0.8 \cdot 4.6E+6Pa) + (\frac{0.1}{({((8.96 \cdot 11.5m³/mol) + 0.0002)}^{2})})) \cdot (\frac{(8.96 \cdot 11.5m³/mol) - 0.0024}{8.3145})

4.6E+7 = ((0.8 \cdot 4.6E+6) + (\frac{0.1}{({((8.96 \cdot 11.5) + 0.0002)}^{2})})) \cdot (\frac{(8.96 \cdot 11.5) - 0.0024}{8.3145})

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Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters Solution

Follow our step by step solution on how to calculate Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters?

FIRST Step Consider the formula

T CE = ((P r \cdot P' c) + (\frac{a}{({((V' m,r \cdot V m,c) + c)}^{2})})) \cdot (\frac{(V' m,r \cdot V m,c) - b'}{[R]})

Next Step Substitute values of Variables

∴

T CE = ((0.8 \cdot 4.6E+6Pa) + (\frac{0.1}{({((8.96 \cdot 11.5m³/mol) + 0.0002)}^{2})})) \cdot (\frac{(8.96 \cdot 11.5m³/mol) - 0.0024}{[R]})

Next Step Substitute values of Constants

∴

T CE = ((0.8 \cdot 4.6E+6Pa) + (\frac{0.1}{({((8.96 \cdot 11.5m³/mol) + 0.0002)}^{2})})) \cdot (\frac{(8.96 \cdot 11.5m³/mol) - 0.0024}{8.3145})

Next Step Prepare to Evaluate

∴

T CE = ((0.8 \cdot 4.6E+6) + (\frac{0.1}{({((8.96 \cdot 11.5) + 0.0002)}^{2})})) \cdot (\frac{(8.96 \cdot 11.5) - 0.0024}{8.3145})

Next Step Evaluate

∴

T CE = 45604662.0226662K

LAST Step Rounding Answer

∴

T CE = 4.6E+7K

Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters Formula Elements

Variables

Constants

Temperature given CE

Temperature given CE is the degree or intensity of heat present in a substance or object.

Symbol: T_CE

Measurement: TemperatureUnit: K

Note: Value can be positive or negative.

Formulas to find Temperature given CE

Reduced Pressure

Reduced Pressure is the ratio of the actual pressure of the fluid to its critical pressure. It is dimensionless.

Symbol: P_r

Measurement: NAUnit: Unitless

Note: Value should be between 0 to 1.

Formulas to find Reduced Pressure

Critical Pressure of Real Gas

Critical Pressure of Real Gas is the minimum pressure required to liquify a substance at the critical temperature.

Symbol: P'_c

Measurement: PressureUnit: Pa

Note: Value should be greater than 0.

Formulas to find Critical Pressure of Real Gas

Clausius Parameter a

Clausius parameter a is an empirical parameter characteristic to equation obtained from Clausius model of real gas.

Symbol: a

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Formulas to find Clausius Parameter a

Reduced Molar Volume for Real Gas

Reduced Molar Volume for Real Gas of a fluid is computed from the ideal gas law at the substance's critical pressure and temperature per mole.

Symbol: V'_m,r

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Formulas to find Reduced Molar Volume for Real Gas

Critical Molar Volume

Critical Molar Volume is the volume occupied by gas at critical temperature and pressure per mole.

Symbol: V_m,c

Measurement: Molar Magnetic SusceptibilityUnit: m³/mol

Note: Value can be positive or negative.

Formulas to find Critical Molar Volume

Clausius Parameter c

Clausius parameter c is an empirical parameter characteristic to equation obtained from Clausius model of real gas.

Symbol: c

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Formulas to find Clausius Parameter c

Clausius Parameter b for Real Gas

Clausius Parameter b for Real Gas is an empirical parameter characteristic to equation obtained from Clausius model of real gas.

Symbol: b'

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Formulas to find Clausius Parameter b for Real Gas

Universal gas constant

Universal gas constant is a fundamental physical constant that appears in the ideal gas law, relating the pressure, volume, and temperature of an ideal gas.

Symbol: [R]

Value: 8.31446261815324

Other Formulas to find Temperature given CE

Go Temperature of Real Gas using Clausius Equation

T CE = (p + (\frac{a}{({(V m + c)}^{2})})) \cdot (\frac{V m - b'}{[R]})

Other formulas in Pressure and Temperature of Real Gas category

Go Actual Pressure of Real Gas given Clausius Parameter a, Reduced and Critical Parameters

Pa = (\frac{27 \cdot ({[R]}^{2}) \cdot ({T' c}^{3})}{64 \cdot a}) \cdot P r

Go Actual Pressure of Real Gas given Clausius Parameter b, Reduced and Actual Parameters

Pb = (\frac{[R] \cdot (\frac{T rg}{T r})}{4 \cdot ((\frac{V real}{V r}) - b')}) \cdot P r

How to Evaluate Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters?

Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters evaluator uses Temperature given CE = ((Reduced Pressure*Critical Pressure of Real Gas)+(Clausius Parameter a/((((Reduced Molar Volume for Real Gas*Critical Molar Volume)+Clausius Parameter c)^2))))*(((Reduced Molar Volume for Real Gas*Critical Molar Volume)-Clausius Parameter b for Real Gas)/[R]) to evaluate the Temperature given CE, The Temperature of real gas using Clausius equation given reduced and critical parameters formula is defined as the degree or intensity of heat present in a substance or object. Temperature given CE is denoted by T_CE symbol.

How to evaluate Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters using this online evaluator? To use this online evaluator for Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters, enter Reduced Pressure (P_r), Critical Pressure of Real Gas (P'_c), Clausius Parameter a (a), Reduced Molar Volume for Real Gas (V'_m,r), Critical Molar Volume (V_m,c), Clausius Parameter c (c) & Clausius Parameter b for Real Gas (b') and hit the calculate button.

FAQs on Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters

What is the formula to find Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters?

The formula of Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters is expressed as Temperature given CE = ((Reduced Pressure*Critical Pressure of Real Gas)+(Clausius Parameter a/((((Reduced Molar Volume for Real Gas*Critical Molar Volume)+Clausius Parameter c)^2))))*(((Reduced Molar Volume for Real Gas*Critical Molar Volume)-Clausius Parameter b for Real Gas)/[R]). Here is an example- 5.7E+7 = ((0.8*4600000)+(0.1/((((8.96*11.5)+0.0002)^2))))*(((8.96*11.5)-0.00243)/[R]).

How to calculate Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters?

With Reduced Pressure (P_r), Critical Pressure of Real Gas (P'_c), Clausius Parameter a (a), Reduced Molar Volume for Real Gas (V'_m,r), Critical Molar Volume (V_m,c), Clausius Parameter c (c) & Clausius Parameter b for Real Gas (b') we can find Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters using the formula - Temperature given CE = ((Reduced Pressure*Critical Pressure of Real Gas)+(Clausius Parameter a/((((Reduced Molar Volume for Real Gas*Critical Molar Volume)+Clausius Parameter c)^2))))*(((Reduced Molar Volume for Real Gas*Critical Molar Volume)-Clausius Parameter b for Real Gas)/[R]). This formula also uses Universal gas constant .

What are the other ways to Calculate Temperature given CE?

Here are the different ways to Calculate Temperature given CE-

Temperature given CE=(Pressure+(Clausius Parameter a/(((Molar Volume+Clausius Parameter c)^2))))*((Molar Volume-Clausius Parameter b for Real Gas)/[R])

Can the Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters be negative?

Yes, the Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters, measured in Temperature can be negative.

Which unit is used to measure Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters?

Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters is usually measured using the Kelvin[K] for Temperature. Celsius[K], Fahrenheit[K], Rankine[K] are the few other units in which Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters can be measured.

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Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters Formula

​GoTemperature of Real Gas using Clausius Equation Formula

Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters Example

Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters Solution

Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters Formula Elements

Other Formulas to find Temperature given CE

Other formulas in Pressure and Temperature of Real Gas category

How to Evaluate Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters?

FAQs on Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters

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GoTemperature of Real Gas using Clausius Equation Formula