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Superelevation in railways Formula

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Superelevation is the elevation or banking of a road or railway curve to reduce the effect of centrifugal force on vehicles. Check FAQs

S = \frac{G \cdot (v^{2})}{[g] \cdot r}

S - Superelevation?G - Gauge of Track?v - Velocity?r - Radius of Circular Path?[g] - Gravitational acceleration on Earth?

Superelevation in railways Example

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Here is how the Superelevation in railways equation looks like with Values.

Here is how the Superelevation in railways equation looks like with Units.

Here is how the Superelevation in railways equation looks like.

0.7342 = \frac{0.2 \cdot (60^{2})}{9.8066 \cdot 100}

0.7342m = \frac{0.2m \cdot ({60m/s}^{2})}{9.8066m/s² \cdot 100m}

0.7342 = \frac{0.2 \cdot (60^{2})}{9.8066 \cdot 100}

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Superelevation in railways Solution

Follow our step by step solution on how to calculate Superelevation in railways?

FIRST Step Consider the formula

S = \frac{G \cdot (v^{2})}{[g] \cdot r}

Next Step Substitute values of Variables

∴

S = \frac{0.2m \cdot ({60m/s}^{2})}{[g] \cdot 100m}

Next Step Substitute values of Constants

∴

S = \frac{0.2m \cdot ({60m/s}^{2})}{9.8066m/s² \cdot 100m}

Next Step Prepare to Evaluate

∴

S = \frac{0.2 \cdot (60^{2})}{9.8066 \cdot 100}

Next Step Evaluate

∴

S = 0.734195673344108m

LAST Step Rounding Answer

∴

S = 0.7342m

Superelevation in railways Formula Elements

Variables

Constants

Superelevation

Superelevation is the elevation or banking of a road or railway curve to reduce the effect of centrifugal force on vehicles.

Symbol: S

Measurement: LengthUnit: m

Note: Value can be positive or negative.

Formulas to find Superelevation

Gauge of Track

Gauge of Track is the measure of the distance between the inner edges of the rail in a railway track, crucial in general dynamics principles.

Symbol: G

Measurement: LengthUnit: m

Note: Value can be positive or negative.

Formulas to find Gauge of Track

Velocity

Velocity is a vector quantity (it has both magnitude and direction) and is the rate of change of the position of an object with respect to time.

Symbol: v

Measurement: SpeedUnit: m/s

Note: Value can be positive or negative.

Formulas to find Velocity

Radius of Circular Path

Radius of Circular Path is the distance from the center of a circular path to any point on the circle in general dynamics principles.

Symbol: r

Measurement: LengthUnit: m

Note: Value can be positive or negative.

Formulas to find Radius of Circular Path

Gravitational acceleration on Earth

Gravitational acceleration on Earth means that the velocity of an object in free fall will increase by 9.8 m/s2 every second.

Symbol: [g]

Value: 9.80665 m/s²

Other formulas in Principal Parameters category

Go Force of attraction between two masses separated by distance

F g = \frac{[G.] \cdot m 1 \cdot m 2}{{d m}^{2}}

Go Angle of banking

θ b = a \tan (\frac{v^{2}}{[g] \cdot r})

Go Maximum velocity to avoid overturning of vehicle along level circular path

v = \sqrt{\frac{[g] \cdot r \cdot d w}{2 \cdot G}}

Go Maximum velocity to avoid skidding away of vehicle along level circular path

v = \sqrt{μ \cdot [g] \cdot r}

How to Evaluate Superelevation in railways?

Superelevation in railways evaluator uses Superelevation = (Gauge of Track*(Velocity^2))/([g]*Radius of Circular Path) to evaluate the Superelevation, Superelevation in railways formula is defined as a measure of the inward transverse inclination provided to the rails on a curve, which helps to balance the centrifugal force and gravity, thereby ensuring smooth and safe movement of trains at higher speeds. Superelevation is denoted by S symbol.

How to evaluate Superelevation in railways using this online evaluator? To use this online evaluator for Superelevation in railways, enter Gauge of Track (G), Velocity (v) & Radius of Circular Path (r) and hit the calculate button.

FAQs on Superelevation in railways

What is the formula to find Superelevation in railways?

The formula of Superelevation in railways is expressed as Superelevation = (Gauge of Track*(Velocity^2))/([g]*Radius of Circular Path). Here is an example- 0.734196 = (0.2*(60^2))/([g]*100).

How to calculate Superelevation in railways?

With Gauge of Track (G), Velocity (v) & Radius of Circular Path (r) we can find Superelevation in railways using the formula - Superelevation = (Gauge of Track*(Velocity^2))/([g]*Radius of Circular Path). This formula also uses Gravitational acceleration on Earth constant(s).

Can the Superelevation in railways be negative?

Yes, the Superelevation in railways, measured in Length can be negative.

Which unit is used to measure Superelevation in railways?

Superelevation in railways is usually measured using the Meter[m] for Length. Millimeter[m], Kilometer[m], Decimeter[m] are the few other units in which Superelevation in railways can be measured.

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Superelevation in railways Formula

Superelevation in railways Example

Superelevation in railways Solution

Superelevation in railways Formula Elements

Other formulas in Principal Parameters category

How to Evaluate Superelevation in railways?

FAQs on Superelevation in railways

Variable Name