Sum of Last N Terms of Arithmetic Progression Formula

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The Sum of Last N Terms of Progression is the summation of the terms starting from the end to the nth term of a given Progression. Check FAQs
Sn(End)=(n2)((2a)+(d((2nTotal)-n-1)))
Sn(End) - Sum of Last N Terms of Progression?n - Index N of Progression?a - First Term of Progression?d - Common Difference of Progression?nTotal - Number of Total Terms of Progression?

Sum of Last N Terms of Arithmetic Progression Example

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Here is how the Sum of Last N Terms of Arithmetic Progression equation looks like with Values.

Here is how the Sum of Last N Terms of Arithmetic Progression equation looks like with Units.

Here is how the Sum of Last N Terms of Arithmetic Progression equation looks like.

174Edit=(6Edit2)((23Edit)+(4Edit((210Edit)-6Edit-1)))
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Sum of Last N Terms of Arithmetic Progression Solution

Follow our step by step solution on how to calculate Sum of Last N Terms of Arithmetic Progression?

FIRST Step Consider the formula
Sn(End)=(n2)((2a)+(d((2nTotal)-n-1)))
Next Step Substitute values of Variables
Sn(End)=(62)((23)+(4((210)-6-1)))
Next Step Prepare to Evaluate
Sn(End)=(62)((23)+(4((210)-6-1)))
LAST Step Evaluate
Sn(End)=174

Sum of Last N Terms of Arithmetic Progression Formula Elements

Variables
Sum of Last N Terms of Progression
The Sum of Last N Terms of Progression is the summation of the terms starting from the end to the nth term of a given Progression.
Symbol: Sn(End)
Measurement: NAUnit: Unitless
Note: Value can be positive or negative.
Index N of Progression
The Index N of Progression is the value of n for the nth term or the position of the nth term in a Progression.
Symbol: n
Measurement: NAUnit: Unitless
Note: Value should be greater than 0.
First Term of Progression
The First Term of Progression is the term at which the given Progression starts.
Symbol: a
Measurement: NAUnit: Unitless
Note: Value can be positive or negative.
Common Difference of Progression
The Common Difference of Progression is the difference between two consecutive terms of a Progression, which is always a constant.
Symbol: d
Measurement: NAUnit: Unitless
Note: Value can be positive or negative.
Number of Total Terms of Progression
The Number of Total Terms of Progression is the total number of terms present in the given sequence of Progression.
Symbol: nTotal
Measurement: NAUnit: Unitless
Note: Value should be greater than 0.

Other formulas in Sum of Terms of Arithmetic Progression category

​Go Common Difference of Arithmetic Progression
d=Tn-Tn-1
​Go Sum of First N Terms of Arithmetic Progression
Sn=(n2)((2a)+((n-1)d))
​Go Nth Term of Arithmetic Progression
Tn=a+(n-1)d
​Go Sum of Total Terms of Arithmetic Progression given Last Term
STotal=(nTotal2)(a+l)

How to Evaluate Sum of Last N Terms of Arithmetic Progression?

Sum of Last N Terms of Arithmetic Progression evaluator uses Sum of Last N Terms of Progression = (Index N of Progression/2)*((2*First Term of Progression)+(Common Difference of Progression*((2*Number of Total Terms of Progression)-Index N of Progression-1))) to evaluate the Sum of Last N Terms of Progression, The Sum of Last N Terms of Arithmetic Progression formula is defined as the summation of the terms starting from the end to the nth term of given Arithmetic Progression. Sum of Last N Terms of Progression is denoted by Sn(End) symbol.

How to evaluate Sum of Last N Terms of Arithmetic Progression using this online evaluator? To use this online evaluator for Sum of Last N Terms of Arithmetic Progression, enter Index N of Progression (n), First Term of Progression (a), Common Difference of Progression (d) & Number of Total Terms of Progression (nTotal) and hit the calculate button.

FAQs on Sum of Last N Terms of Arithmetic Progression

What is the formula to find Sum of Last N Terms of Arithmetic Progression?
The formula of Sum of Last N Terms of Arithmetic Progression is expressed as Sum of Last N Terms of Progression = (Index N of Progression/2)*((2*First Term of Progression)+(Common Difference of Progression*((2*Number of Total Terms of Progression)-Index N of Progression-1))). Here is an example- 174 = (6/2)*((2*3)+(4*((2*10)-6-1))).
How to calculate Sum of Last N Terms of Arithmetic Progression?
With Index N of Progression (n), First Term of Progression (a), Common Difference of Progression (d) & Number of Total Terms of Progression (nTotal) we can find Sum of Last N Terms of Arithmetic Progression using the formula - Sum of Last N Terms of Progression = (Index N of Progression/2)*((2*First Term of Progression)+(Common Difference of Progression*((2*Number of Total Terms of Progression)-Index N of Progression-1))).
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