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Strain in x direction in biaxial system Formula

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Strain in X direction is the change in dimensions experienced by the member in x direction. Check FAQs

ε x = (\frac{σ x}{E}) - ((𝛎) \cdot (\frac{σ y}{E}))

ε_x - Strain in X direction?σ_x - Normal Stress in x Direction?E - Young's Modulus Bar?𝛎 - Poisson's Ratio?σ_y - Normal Stress in y Direction?

Strain in x direction in biaxial system Example

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Here is how the Strain in x direction in biaxial system equation looks like with Values.

Here is how the Strain in x direction in biaxial system equation looks like with Units.

Here is how the Strain in x direction in biaxial system equation looks like.

0.3217 = (\frac{0.011}{0.023}) - ((0.3) \cdot (\frac{0.012}{0.023}))

0.3217 = (\frac{0.011MPa}{0.023MPa}) - ((0.3) \cdot (\frac{0.012MPa}{0.023MPa}))

0.3217 = (\frac{0.011}{0.023}) - ((0.3) \cdot (\frac{0.012}{0.023}))

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Strain in x direction in biaxial system Solution

Follow our step by step solution on how to calculate Strain in x direction in biaxial system?

FIRST Step Consider the formula

ε x = (\frac{σ x}{E}) - ((𝛎) \cdot (\frac{σ y}{E}))

Next Step Substitute values of Variables

∴

ε x = (\frac{0.011MPa}{0.023MPa}) - ((0.3) \cdot (\frac{0.012MPa}{0.023MPa}))

Next Step Convert Units

∴

ε x = (\frac{11000Pa}{23000Pa}) - ((0.3) \cdot (\frac{12000Pa}{23000Pa}))

Next Step Prepare to Evaluate

∴

ε x = (\frac{11000}{23000}) - ((0.3) \cdot (\frac{12000}{23000}))

Next Step Evaluate

∴

ε x = 0.321739130434783

LAST Step Rounding Answer

∴

ε x = 0.3217

Strain in x direction in biaxial system Formula Elements

Variables

Strain in X direction

Strain in X direction is the change in dimensions experienced by the member in x direction.

Symbol: ε_x

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Formulas to find Strain in X direction

Normal Stress in x Direction

Normal Stress in x Direction is the stress experienced by a body under the influence of a force.

Symbol: σ_x

Measurement: StressUnit: MPa

Note: Value can be positive or negative.

Formulas to find Normal Stress in x Direction

Young's Modulus Bar

Young's Modulus Bar is a mechanical property of linear elastic solid substances. It describes the relationship between longitudinal stress and longitudinal strain.

Symbol: E

Measurement: PressureUnit: MPa

Note: Value should be greater than 0.

Formulas to find Young's Modulus Bar

Poisson's Ratio

Poisson's Ratio is defined as the ratio of the lateral and axial strain. For many metals and alloys, values of Poisson’s ratio range between 0.1 and 0.5.

Symbol: 𝛎

Measurement: NAUnit: Unitless

Note: Value should be between -1 to 0.5.

Formulas to find Poisson's Ratio

Normal Stress in y Direction

Normal Stress in y Direction is the stress experienced by the body under the influence of an external force.

Symbol: σ_y

Measurement: StressUnit: MPa

Note: Value should be between -1E+15 to 1E+15.

Formulas to find Normal Stress in y Direction

Other formulas in Biaxial Stress Deformation System category

Go Strain in Y direction in biaxial system

ε y = (\frac{σ y}{E}) - ((𝛎) \cdot (\frac{σ x}{E}))

How to Evaluate Strain in x direction in biaxial system?

Strain in x direction in biaxial system evaluator uses Strain in X direction = (Normal Stress in x Direction/Young's Modulus Bar)-((Poisson's Ratio)*(Normal Stress in y Direction/Young's Modulus Bar)) to evaluate the Strain in X direction, The Strain in x direction in biaxial system is defined as the change in dimensions of the member along the X axis in a biaxial system. Strain in X direction is denoted by ε_x symbol.

How to evaluate Strain in x direction in biaxial system using this online evaluator? To use this online evaluator for Strain in x direction in biaxial system, enter Normal Stress in x Direction (σ_x), Young's Modulus Bar (E), Poisson's Ratio (𝛎) & Normal Stress in y Direction (σ_y) and hit the calculate button.

FAQs on Strain in x direction in biaxial system

What is the formula to find Strain in x direction in biaxial system?

The formula of Strain in x direction in biaxial system is expressed as Strain in X direction = (Normal Stress in x Direction/Young's Modulus Bar)-((Poisson's Ratio)*(Normal Stress in y Direction/Young's Modulus Bar)). Here is an example- 0.321739 = (11000/23000)-((0.3)*(12000/23000)).

How to calculate Strain in x direction in biaxial system?

With Normal Stress in x Direction (σ_x), Young's Modulus Bar (E), Poisson's Ratio (𝛎) & Normal Stress in y Direction (σ_y) we can find Strain in x direction in biaxial system using the formula - Strain in X direction = (Normal Stress in x Direction/Young's Modulus Bar)-((Poisson's Ratio)*(Normal Stress in y Direction/Young's Modulus Bar)).

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