FormulaDen.com

Physics Chemistry Math Chemical Engineering Civil Electrical Electronics Electronics and Instrumentation Materials Science Mechanical Production Engineering Financial Health

Spectral black body emissive power Planck's law Formula

Fx Copy

LaTeX Copy

The Spectral Blackbody Emissive Power is the amount of thermal radiation emitted by a perfect blackbody per unit wavelength at a given temperature. Check FAQs

E bλ = \frac{0.374177107 \cdot (10^{- 15})}{(λ^{5}) \cdot (e^{\frac{0.014387752}{λ \cdot T}} - 1)}

E_bλ - Spectral Blackbody Emissive Power?λ - Wavelength?T - Temperature?

Spectral black body emissive power Planck's law Example

With values

With units

Only example

Here is how the Spectral black body emissive power Planck's law equation looks like with Values.

Here is how the Spectral black body emissive power Planck's law equation looks like with Units.

Here is how the Spectral black body emissive power Planck's law equation looks like.

4.5E-18 = \frac{0.374177107 \cdot (10^{- 15})}{({26.8}^{5}) \cdot (e^{\frac{0.014387752}{26.8 \cdot 89.4033}} - 1)}

4.5E-18W/m³ = \frac{0.374177107 \cdot (10^{- 15})}{({26.8m}^{5}) \cdot (e^{\frac{0.014387752}{26.8m \cdot 89.4033K}} - 1)}

4.5E-18 = \frac{0.374177107 \cdot (10^{- 15})}{({26.8}^{5}) \cdot (e^{\frac{0.014387752}{26.8 \cdot 89.4033}} - 1)}

Tip: Use pencil ( Pencil

) icon above to edit Input Values and Units.

Calculate

Recalculate

Solution

Copy

Reset

You are here -

Home » Category

Physics » Category

Mechanical » Category

Heat and Mass Transfer » fx Spectral black body emissive power Planck's law

Spectral black body emissive power Planck's law Solution

Follow our step by step solution on how to calculate Spectral black body emissive power Planck's law?

FIRST Step Consider the formula

E bλ = \frac{0.374177107 \cdot (10^{- 15})}{(λ^{5}) \cdot (e^{\frac{0.014387752}{λ \cdot T}} - 1)}

Next Step Substitute values of Variables

∴

E bλ = \frac{0.374177107 \cdot (10^{- 15})}{({26.8m}^{5}) \cdot (e^{\frac{0.014387752}{26.8m \cdot 89.4033K}} - 1)}

Next Step Prepare to Evaluate

∴

E bλ = \frac{0.374177107 \cdot (10^{- 15})}{({26.8}^{5}) \cdot (e^{\frac{0.014387752}{26.8 \cdot 89.4033}} - 1)}

Next Step Evaluate

∴

E bλ = 4.5071015049576E-18W/m³

LAST Step Rounding Answer

∴

E bλ = 4.5E-18W/m³

Spectral black body emissive power Planck's law Formula Elements

Variables

Spectral Blackbody Emissive Power

The Spectral Blackbody Emissive Power is the amount of thermal radiation emitted by a perfect blackbody per unit wavelength at a given temperature.

Symbol: E_bλ

Measurement: Emissive Power per Unit WavelengthUnit: W/m³

Note: Value should be greater than 0.

Formulas to find Spectral Blackbody Emissive Power

Wavelength

The Wavelength is the distance between successive peaks of a wave, which influences the energy and characteristics of radiation emitted by heat sources.

Symbol: λ

Measurement: LengthUnit: m

Note: Value can be positive or negative.

Formulas to find Wavelength

Temperature

The Temperature is a measure of the thermal energy of a system, indicating how hot or cold it is, which affects heat emission due to radiation.

Symbol: T

Measurement: TemperatureUnit: K

Note: Value can be positive or negative.

Formulas to find Temperature

Other formulas in Heat Emission due to Radiation category

Go Black Bodies Heat Exchange by Radiation

q = ε \cdot [Stefan-BoltZ] \cdot A cs \cdot ({T 1}^{4} - {T 2}^{4})

Go Heat Exchange by Radiation due to Geometric Arrangement

q = ε \cdot A cs \cdot [Stefan-BoltZ] \cdot SF \cdot ({T 1}^{4} - {T 2}^{4})

Go Non Ideal Body Surface Emittance

e = ε \cdot [Stefan-BoltZ] \cdot {T w}^{4}

Go Radiation energy emitted by black body per unit time and surface area

G = [Stefan-BoltZ] \cdot T^{4}

How to Evaluate Spectral black body emissive power Planck's law?

Spectral black body emissive power Planck's law evaluator uses Spectral Blackbody Emissive Power = (0.374177107*(10^(-15)))/((Wavelength^5)*(e^(0.014387752/(Wavelength*Temperature))-1)) to evaluate the Spectral Blackbody Emissive Power, Spectral black body emissive power Planck's law formula is defined as a measure of the energy emitted by a blackbody at a given wavelength and temperature, describing the distribution of energy in the electromagnetic spectrum. Spectral Blackbody Emissive Power is denoted by E_bλ symbol.

How to evaluate Spectral black body emissive power Planck's law using this online evaluator? To use this online evaluator for Spectral black body emissive power Planck's law, enter Wavelength (λ) & Temperature (T) and hit the calculate button.

FAQs on Spectral black body emissive power Planck's law

What is the formula to find Spectral black body emissive power Planck's law?

The formula of Spectral black body emissive power Planck's law is expressed as Spectral Blackbody Emissive Power = (0.374177107*(10^(-15)))/((Wavelength^5)*(e^(0.014387752/(Wavelength*Temperature))-1)). Here is an example- 4.5E-18 = (0.374177107*(10^(-15)))/((26.8^5)*(e^(0.014387752/(26.8*89.4033))-1)).

How to calculate Spectral black body emissive power Planck's law?

With Wavelength (λ) & Temperature (T) we can find Spectral black body emissive power Planck's law using the formula - Spectral Blackbody Emissive Power = (0.374177107*(10^(-15)))/((Wavelength^5)*(e^(0.014387752/(Wavelength*Temperature))-1)).

Can the Spectral black body emissive power Planck's law be negative?

No, the Spectral black body emissive power Planck's law, measured in Emissive Power per Unit Wavelength cannot be negative.

Which unit is used to measure Spectral black body emissive power Planck's law?

Spectral black body emissive power Planck's law is usually measured using the Watt per Cubic Meter[W/m³] for Emissive Power per Unit Wavelength. Watt per Square Meter per Kilometer[W/m³], Kilowatt per Square Meter per Kilometer[W/m³] are the few other units in which Spectral black body emissive power Planck's law can be measured.

Let Others Know

✖

Facebook

Twitter

Copied!