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The Specific weight of liquid is also known as the unit weight, is the weight per unit volume of the liquid. For Example - Specific weight of water on Earth at 4°C is 9.807 kN/m3 or 62.43 lbf/ft3. Check FAQs
y=PQ⋅(Hent-hf)
y - Specific weight of liquid?P - Power?Q - Rate of Flow?Hent - Total Head at Entrance?hf - Head Loss?

Specific Weight of Liquid given Hydraulic Transmission Power Example

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Here is how the Specific Weight of Liquid given Hydraulic Transmission Power equation looks like with Values.

Here is how the Specific Weight of Liquid given Hydraulic Transmission Power equation looks like with Units.

Here is how the Specific Weight of Liquid given Hydraulic Transmission Power equation looks like.

-0.0064Edit=170Edit22.1Edit⋅(1.6Edit-1200Edit)
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Specific Weight of Liquid given Hydraulic Transmission Power Solution

Follow our step by step solution on how to calculate Specific Weight of Liquid given Hydraulic Transmission Power?

FIRST Step Consider the formula
y=PQ⋅(Hent-hf)
Next Step Substitute values of Variables
∴ y=170W22.1m³/s⋅(1.6m-1200m)
Next Step Prepare to Evaluate
∴ y=17022.1⋅(1.6-1200)
Next Step Evaluate
∴y=-0.00641881483002978N/m³
LAST Step Rounding Answer
∴y=-0.0064N/m³

Specific Weight of Liquid given Hydraulic Transmission Power Formula Elements

Variables
Specific weight of liquid
The Specific weight of liquid is also known as the unit weight, is the weight per unit volume of the liquid. For Example - Specific weight of water on Earth at 4°C is 9.807 kN/m3 or 62.43 lbf/ft3.
Symbol: y
Measurement: Specific WeightUnit: N/m³
Note: Value can be positive or negative.
Formulas to find Specific weight of liquidOpen Variable
Power
Power is the amount of energy liberated per second in a device.
Symbol: P
Measurement: PowerUnit: W
Note: Value should be greater than 0.
Formulas to find PowerOpen Variable
Rate of Flow
Rate of Flow is the rate at which a liquid or other substance flows through a particular channel, pipe, etc.
Symbol: Q
Measurement: Volumetric Flow RateUnit: m³/s
Note: Value can be positive or negative.
Formulas to find Rate of FlowOpen Variable
Total Head at Entrance
Total Head at Entrance is the measure of fluid's potential at the entrance.
Symbol: Hent
Measurement: LengthUnit: m
Note: Value should be greater than 0.
Formulas to find Total Head at EntranceOpen Variable
Head Loss
Head loss is a measure of the reduction in the total head (sum of elevation head, velocity head and pressure head) of the fluid as it moves through a fluid system.
Symbol: hf
Measurement: LengthUnit: m
Note: Value can be positive or negative.
Formulas to find Head LossOpen Variable

Other Formulas to find Specific weight of liquid

​Go Specific Weight of Liquid given Buoyancy Force
y=FbVO

Other formulas in Specific Weight category

​Go Specific Weight
γUnit=WbodyVT
​Go Specific Weight of Fluid 1 given Differential Pressure between Two Points
γ1=Δp+γ2⋅h2h1
​Go Specific Weight of Inclined Manometer Liquid
γ1=PaLm⋅sin(Θ)
​Go Specific Weight of Fluid 2 given Differential Pressure between Two Points
γ2=γ1⋅h1-Δph2

How to Evaluate Specific Weight of Liquid given Hydraulic Transmission Power?

Specific Weight of Liquid given Hydraulic Transmission Power evaluator uses Specific weight of liquid = Power/(Rate of Flow*(Total Head at Entrance-Head Loss)) to evaluate the Specific weight of liquid, The Specific Weight of Liquid given Hydraulic Transmission Power formula is defined as the weight per unit volume of a material. A commonly used value is the specific weight of water on Earth at 4°C. Specific weight of liquid is denoted by y symbol.

How to evaluate Specific Weight of Liquid given Hydraulic Transmission Power using this online evaluator? To use this online evaluator for Specific Weight of Liquid given Hydraulic Transmission Power, enter Power (P), Rate of Flow (Q), Total Head at Entrance (Hent) & Head Loss (hf) and hit the calculate button.

FAQs on Specific Weight of Liquid given Hydraulic Transmission Power

What is the formula to find Specific Weight of Liquid given Hydraulic Transmission Power?
The formula of Specific Weight of Liquid given Hydraulic Transmission Power is expressed as Specific weight of liquid = Power/(Rate of Flow*(Total Head at Entrance-Head Loss)). Here is an example- -0.006419 = 170/(22.1*(1.6-1200)).
How to calculate Specific Weight of Liquid given Hydraulic Transmission Power?
With Power (P), Rate of Flow (Q), Total Head at Entrance (Hent) & Head Loss (hf) we can find Specific Weight of Liquid given Hydraulic Transmission Power using the formula - Specific weight of liquid = Power/(Rate of Flow*(Total Head at Entrance-Head Loss)).
What are the other ways to Calculate Specific weight of liquid?
Here are the different ways to Calculate Specific weight of liquid-
  • Specific weight of liquid=Buoyancy Force/Volume of ObjectOpenImg
Can the Specific Weight of Liquid given Hydraulic Transmission Power be negative?
Yes, the Specific Weight of Liquid given Hydraulic Transmission Power, measured in Specific Weight can be negative.
Which unit is used to measure Specific Weight of Liquid given Hydraulic Transmission Power?
Specific Weight of Liquid given Hydraulic Transmission Power is usually measured using the Newton per Cubic Meter[N/m³] for Specific Weight. Newton per Cubic Centimeter[N/m³], Newton per Cubic Millimeter[N/m³], Kilonewton per Cubic Meter[N/m³] are the few other units in which Specific Weight of Liquid given Hydraulic Transmission Power can be measured.
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