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Specific Weight of Liquid given Head loss Due to Laminar Flow Formula

GoSpecific Weight of Liquid given its Absolute Pressure at Height Formula

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Specific Weight Liquid is defined as weight per unit volume. Check FAQs

γ liq = \frac{128 \cdot μ \cdot Q \cdot L pipe}{h f \cdot π \cdot {d pipe}^{4}}

γ_liq - Specific Weight Liquid?μ - Viscous Force?Q - Rate of Flow?L_pipe - Length of Pipe?h_f - Head Loss?d_pipe - Pipe Diameter?π - Archimedes' constant?

Specific Weight of Liquid given Head loss Due to Laminar Flow Example

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Here is how the Specific Weight of Liquid given Head loss Due to Laminar Flow equation looks like with Values.

Here is how the Specific Weight of Liquid given Head loss Due to Laminar Flow equation looks like with Units.

Here is how the Specific Weight of Liquid given Head loss Due to Laminar Flow equation looks like.

0.0792 = \frac{128 \cdot 100 \cdot 22.1 \cdot 0.1}{1200 \cdot 3.1416 \cdot {3.12}^{4}}

0.0792N/m³ = \frac{128 \cdot 100N \cdot 22.1m³/s \cdot 0.1m}{1200m \cdot 3.1416 \cdot {3.12m}^{4}}

0.0792 = \frac{128 \cdot 100 \cdot 22.1 \cdot 0.1}{1200 \cdot 3.1416 \cdot {3.12}^{4}}

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Specific Weight of Liquid given Head loss Due to Laminar Flow Solution

Follow our step by step solution on how to calculate Specific Weight of Liquid given Head loss Due to Laminar Flow?

FIRST Step Consider the formula

γ liq = \frac{128 \cdot μ \cdot Q \cdot L pipe}{h f \cdot π \cdot {d pipe}^{4}}

Next Step Substitute values of Variables

∴

γ liq = \frac{128 \cdot 100N \cdot 22.1m³/s \cdot 0.1m}{1200m \cdot π \cdot {3.12m}^{4}}

Next Step Substitute values of Constants

∴

γ liq = \frac{128 \cdot 100N \cdot 22.1m³/s \cdot 0.1m}{1200m \cdot 3.1416 \cdot {3.12m}^{4}}

Next Step Prepare to Evaluate

∴

γ liq = \frac{128 \cdot 100 \cdot 22.1 \cdot 0.1}{1200 \cdot 3.1416 \cdot {3.12}^{4}}

Next Step Evaluate

∴

γ liq = 0.0791867918631742N/m³

LAST Step Rounding Answer

∴

γ liq = 0.0792N/m³

Specific Weight of Liquid given Head loss Due to Laminar Flow Formula Elements

Variables

Constants

Specific Weight Liquid

Specific Weight Liquid is defined as weight per unit volume.

Symbol: γ_liq

Measurement: Specific WeightUnit: N/m³

Note: Value can be positive or negative.

Formulas to find Specific Weight Liquid

Viscous Force

The Viscous Force is the force between a body and a fluid (liquid or gas) moving past it, in a direction so as to oppose the flow of the fluid past the object.

Symbol: μ

Measurement: ForceUnit: N

Note: Value can be positive or negative.

Formulas to find Viscous Force

Rate of Flow

Rate of Flow is the rate at which a liquid or other substance flows through a particular channel, pipe, etc.

Symbol: Q

Measurement: Volumetric Flow RateUnit: m³/s

Note: Value can be positive or negative.

Formulas to find Rate of Flow

Length of Pipe

Length of Pipe describes the length of the pipe in which the liquid is flowing.

Symbol: L_pipe

Measurement: LengthUnit: m

Note: Value can be positive or negative.

Formulas to find Length of Pipe

Head Loss

Head loss is a measure of the reduction in the total head (sum of elevation head, velocity head and pressure head) of the fluid as it moves through a fluid system.

Symbol: h_f

Measurement: LengthUnit: m

Note: Value can be positive or negative.

Formulas to find Head Loss

Pipe Diameter

Pipe Diameter is the diameter of the pipe in which the liquid is flowing.

Symbol: d_pipe

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Pipe Diameter

Archimedes' constant

Archimedes' constant is a mathematical constant that represents the ratio of the circumference of a circle to its diameter.

Symbol: π

Value: 3.14159265358979323846264338327950288

Other Formulas to find Specific Weight Liquid

Go Specific Weight of Liquid given its Absolute Pressure at Height

γ liq = \frac{P abs - P atm}{h}

Other formulas in Specific Weight category

Go Specific Weight

γ Unit = \frac{W body}{V T}

Go Specific Weight of Fluid 1 given Differential Pressure between Two Points

γ 1 = \frac{Δp + γ 2 \cdot h 2}{h 1}

Go Specific Weight of Inclined Manometer Liquid

γ 1 = \frac{P a}{L m \cdot \sin (Θ)}

Go Specific Weight of Fluid 2 given Differential Pressure between Two Points

γ 2 = \frac{γ 1 \cdot h 1 - Δp}{h 2}

How to Evaluate Specific Weight of Liquid given Head loss Due to Laminar Flow?

Specific Weight of Liquid given Head loss Due to Laminar Flow evaluator uses Specific Weight Liquid = (128*Viscous Force*Rate of Flow*Length of Pipe)/(Head Loss*pi*Pipe Diameter^(4)) to evaluate the Specific Weight Liquid, The Specific Weight of Liquid given Head loss Due to Laminar Flow formula represents the force exerted by gravity on a unit volume of a fluid. For this reason, units are expressed as force per unit volume. Specific Weight Liquid is denoted by γ_liq symbol.

How to evaluate Specific Weight of Liquid given Head loss Due to Laminar Flow using this online evaluator? To use this online evaluator for Specific Weight of Liquid given Head loss Due to Laminar Flow, enter Viscous Force (μ), Rate of Flow (Q), Length of Pipe (L_pipe), Head Loss (h_f) & Pipe Diameter (d_pipe) and hit the calculate button.

FAQs on Specific Weight of Liquid given Head loss Due to Laminar Flow

What is the formula to find Specific Weight of Liquid given Head loss Due to Laminar Flow?

The formula of Specific Weight of Liquid given Head loss Due to Laminar Flow is expressed as Specific Weight Liquid = (128*Viscous Force*Rate of Flow*Length of Pipe)/(Head Loss*pi*Pipe Diameter^(4)). Here is an example- 0.079187 = (128*100*22.1*0.1)/(1200*pi*3.12^(4)).

How to calculate Specific Weight of Liquid given Head loss Due to Laminar Flow?

With Viscous Force (μ), Rate of Flow (Q), Length of Pipe (L_pipe), Head Loss (h_f) & Pipe Diameter (d_pipe) we can find Specific Weight of Liquid given Head loss Due to Laminar Flow using the formula - Specific Weight Liquid = (128*Viscous Force*Rate of Flow*Length of Pipe)/(Head Loss*pi*Pipe Diameter^(4)). This formula also uses Archimedes' constant .

What are the other ways to Calculate Specific Weight Liquid?

Here are the different ways to Calculate Specific Weight Liquid-

Specific Weight Liquid=(Absolute Pressure-Atmospheric Pressure)/Height

Can the Specific Weight of Liquid given Head loss Due to Laminar Flow be negative?

Yes, the Specific Weight of Liquid given Head loss Due to Laminar Flow, measured in Specific Weight can be negative.

Which unit is used to measure Specific Weight of Liquid given Head loss Due to Laminar Flow?

Specific Weight of Liquid given Head loss Due to Laminar Flow is usually measured using the Newton per Cubic Meter[N/m³] for Specific Weight. Newton per Cubic Centimeter[N/m³], Newton per Cubic Millimeter[N/m³], Kilonewton per Cubic Meter[N/m³] are the few other units in which Specific Weight of Liquid given Head loss Due to Laminar Flow can be measured.

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Specific Weight of Liquid given Head loss Due to Laminar Flow Formula

​GoSpecific Weight of Liquid given its Absolute Pressure at Height Formula

Specific Weight of Liquid given Head loss Due to Laminar Flow Example

Specific Weight of Liquid given Head loss Due to Laminar Flow Solution

Specific Weight of Liquid given Head loss Due to Laminar Flow Formula Elements

Other Formulas to find Specific Weight Liquid

Other formulas in Specific Weight category

How to Evaluate Specific Weight of Liquid given Head loss Due to Laminar Flow?

FAQs on Specific Weight of Liquid given Head loss Due to Laminar Flow

Variable Name

GoSpecific Weight of Liquid given its Absolute Pressure at Height Formula