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Specific Weight of Fluid 2 given Differential Pressure between Two Points Formula

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Specific weight 2 is the specific weight of 2nd fluid. Check FAQs

γ 2 = \frac{γ 1 \cdot h 1 - Δp}{h 2}

γ₂ - Specific Weight 2?γ₁ - Specific Weight 1?h₁ - Height of Column 1?Δp - Pressure Changes?h₂ - Height of Column 2?

Specific Weight of Fluid 2 given Differential Pressure between Two Points Example

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Here is how the Specific Weight of Fluid 2 given Differential Pressure between Two Points equation looks like with Values.

Here is how the Specific Weight of Fluid 2 given Differential Pressure between Two Points equation looks like with Units.

Here is how the Specific Weight of Fluid 2 given Differential Pressure between Two Points equation looks like.

245.0769 = \frac{1342 \cdot 0.012 - 3.36}{0.052}

245.0769N/m³ = \frac{1342N/m³ \cdot 0.012m - 3.36Pa}{0.052m}

245.0769 = \frac{1342 \cdot 0.012 - 3.36}{0.052}

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Specific Weight of Fluid 2 given Differential Pressure between Two Points Solution

Follow our step by step solution on how to calculate Specific Weight of Fluid 2 given Differential Pressure between Two Points?

FIRST Step Consider the formula

γ 2 = \frac{γ 1 \cdot h 1 - Δp}{h 2}

Next Step Substitute values of Variables

∴

γ 2 = \frac{1342N/m³ \cdot 0.012m - 3.36Pa}{0.052m}

Next Step Prepare to Evaluate

∴

γ 2 = \frac{1342 \cdot 0.012 - 3.36}{0.052}

Next Step Evaluate

∴

γ 2 = 245.076923076923N/m³

LAST Step Rounding Answer

∴

γ 2 = 245.0769N/m³

Specific Weight of Fluid 2 given Differential Pressure between Two Points Formula Elements

Variables

Specific Weight 2

Specific weight 2 is the specific weight of 2nd fluid.

Symbol: γ₂

Measurement: Specific WeightUnit: N/m³

Note: Value can be positive or negative.

Formulas to find Specific Weight 2

Specific Weight 1

Specific weight 1 is the specific weight of the fluid 1.

Symbol: γ₁

Measurement: Specific WeightUnit: N/m³

Note: Value can be positive or negative.

Formulas to find Specific Weight 1

Height of Column 1

Height of column 1 is the length of the column1 measured from bottom to Top.

Symbol: h₁

Measurement: LengthUnit: m

Note: Value can be positive or negative.

Formulas to find Height of Column 1

Pressure Changes

Pressure changes is the difference between the pressure inside the liquid droplet and atmospheric pressure.

Symbol: Δp

Measurement: PressureUnit: Pa

Note: Value can be positive or negative.

Formulas to find Pressure Changes

Height of Column 2

Height of column 2 is the length of the column2 measured from bottom to Top.

Symbol: h₂

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Height of Column 2

Other formulas in Specific Weight category

Go Specific Weight

γ Unit = \frac{W body}{V T}

Go Specific Weight of Fluid 1 given Differential Pressure between Two Points

γ 1 = \frac{Δp + γ 2 \cdot h 2}{h 1}

Go Specific Weight of Inclined Manometer Liquid

γ 1 = \frac{P a}{L m \cdot \sin (Θ)}

Go Specific Weight of Liquid given its Absolute Pressure at Height

γ liq = \frac{P abs - P atm}{h}

How to Evaluate Specific Weight of Fluid 2 given Differential Pressure between Two Points?

Specific Weight of Fluid 2 given Differential Pressure between Two Points evaluator uses Specific Weight 2 = (Specific Weight 1*Height of Column 1-Pressure Changes)/Height of Column 2 to evaluate the Specific Weight 2, The Specific Weight of Fluid 2 given Differential Pressure between Two Points formula is defined as the force exerted by gravity on a unit volume of a fluid. Specific Weight 2 is denoted by γ₂ symbol.

How to evaluate Specific Weight of Fluid 2 given Differential Pressure between Two Points using this online evaluator? To use this online evaluator for Specific Weight of Fluid 2 given Differential Pressure between Two Points, enter Specific Weight 1 (γ₁), Height of Column 1 (h₁), Pressure Changes (Δp) & Height of Column 2 (h₂) and hit the calculate button.

FAQs on Specific Weight of Fluid 2 given Differential Pressure between Two Points

What is the formula to find Specific Weight of Fluid 2 given Differential Pressure between Two Points?

The formula of Specific Weight of Fluid 2 given Differential Pressure between Two Points is expressed as Specific Weight 2 = (Specific Weight 1*Height of Column 1-Pressure Changes)/Height of Column 2. Here is an example- 245.0769 = (1342*0.012-3.36)/0.052.

How to calculate Specific Weight of Fluid 2 given Differential Pressure between Two Points?

With Specific Weight 1 (γ₁), Height of Column 1 (h₁), Pressure Changes (Δp) & Height of Column 2 (h₂) we can find Specific Weight of Fluid 2 given Differential Pressure between Two Points using the formula - Specific Weight 2 = (Specific Weight 1*Height of Column 1-Pressure Changes)/Height of Column 2.

Can the Specific Weight of Fluid 2 given Differential Pressure between Two Points be negative?

Yes, the Specific Weight of Fluid 2 given Differential Pressure between Two Points, measured in Specific Weight can be negative.

Which unit is used to measure Specific Weight of Fluid 2 given Differential Pressure between Two Points?

Specific Weight of Fluid 2 given Differential Pressure between Two Points is usually measured using the Newton per Cubic Meter[N/m³] for Specific Weight. Newton per Cubic Centimeter[N/m³], Newton per Cubic Millimeter[N/m³], Kilonewton per Cubic Meter[N/m³] are the few other units in which Specific Weight of Fluid 2 given Differential Pressure between Two Points can be measured.

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Specific Weight of Fluid 2 given Differential Pressure between Two Points Formula

Specific Weight of Fluid 2 given Differential Pressure between Two Points Example

Specific Weight of Fluid 2 given Differential Pressure between Two Points Solution

Specific Weight of Fluid 2 given Differential Pressure between Two Points Formula Elements

Other formulas in Specific Weight category

How to Evaluate Specific Weight of Fluid 2 given Differential Pressure between Two Points?

FAQs on Specific Weight of Fluid 2 given Differential Pressure between Two Points

Variable Name