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Short Diagonal of Heptagon given Inradius Formula

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Short Diagonal of Heptagon is the length of the straight line joining two non-adjacent vertices across the two sides of the Heptagon. Check FAQs

d Short = 4 \cdot r i \cdot \tan (\frac{π}{7}) \cdot \cos (\frac{π}{7})

d_Short - Short Diagonal of Heptagon?r_i - Inradius of Heptagon?π - Archimedes' constant?

Short Diagonal of Heptagon given Inradius Example

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Here is how the Short Diagonal of Heptagon given Inradius equation looks like with Values.

Here is how the Short Diagonal of Heptagon given Inradius equation looks like with Units.

Here is how the Short Diagonal of Heptagon given Inradius equation looks like.

19.0909 = 4 \cdot 11 \cdot \tan (\frac{3.1416}{7}) \cdot \cos (\frac{3.1416}{7})

19.0909m = 4 \cdot 11m \cdot \tan (\frac{3.1416}{7}) \cdot \cos (\frac{3.1416}{7})

19.0909 = 4 \cdot 11 \cdot \tan (\frac{3.1416}{7}) \cdot \cos (\frac{3.1416}{7})

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Short Diagonal of Heptagon given Inradius Solution

Follow our step by step solution on how to calculate Short Diagonal of Heptagon given Inradius?

FIRST Step Consider the formula

d Short = 4 \cdot r i \cdot \tan (\frac{π}{7}) \cdot \cos (\frac{π}{7})

Next Step Substitute values of Variables

∴

d Short = 4 \cdot 11m \cdot \tan (\frac{π}{7}) \cdot \cos (\frac{π}{7})

Next Step Substitute values of Constants

∴

d Short = 4 \cdot 11m \cdot \tan (\frac{3.1416}{7}) \cdot \cos (\frac{3.1416}{7})

Next Step Prepare to Evaluate

∴

d Short = 4 \cdot 11 \cdot \tan (\frac{3.1416}{7}) \cdot \cos (\frac{3.1416}{7})

Next Step Evaluate

∴

d Short = 19.0908845211726m

LAST Step Rounding Answer

∴

d Short = 19.0909m

Short Diagonal of Heptagon given Inradius Formula Elements

Variables

Constants

Functions

Short Diagonal of Heptagon

Short Diagonal of Heptagon is the length of the straight line joining two non-adjacent vertices across the two sides of the Heptagon.

Symbol: d_Short

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Short Diagonal of Heptagon

Inradius of Heptagon

Inradius of Heptagon is defined as the radius of the circle which is inscribed inside the Heptagon.

Symbol: r_i

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Inradius of Heptagon

Archimedes' constant

Archimedes' constant is a mathematical constant that represents the ratio of the circumference of a circle to its diameter.

Symbol: π

Value: 3.14159265358979323846264338327950288

cos

Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle.

Syntax: cos(Angle)

tan

The tangent of an angle is a trigonometric ratio of the length of the side opposite an angle to the length of the side adjacent to an angle in a right triangle.

Syntax: tan(Angle)

Other Formulas to find Short Diagonal of Heptagon

Go Short Diagonal of Heptagon

d Short = 2 \cdot S \cdot \cos (\frac{π}{7})

Go Short Diagonal of Heptagon given Long Diagonal

d Short = 4 \cdot d Long \cdot \sin (\frac{(\frac{π}{2})}{7}) \cdot \cos (\frac{π}{7})

Go Short Diagonal of Heptagon given Height

d Short = 4 \cdot h \cdot \tan (\frac{(\frac{π}{2})}{7}) \cdot \cos (\frac{π}{7})

Go Short Diagonal of Heptagon given Perimeter

d Short = 2 \cdot (\frac{P}{7}) \cdot \cos (\frac{π}{7})

How to Evaluate Short Diagonal of Heptagon given Inradius?

Short Diagonal of Heptagon given Inradius evaluator uses Short Diagonal of Heptagon = 4*Inradius of Heptagon*tan(pi/7)*cos(pi/7) to evaluate the Short Diagonal of Heptagon, The Short Diagonal of Heptagon given Inradius formula is defined as a straight line joining two non-adjacent vertices of the Heptagon across the two sides, calculated using inradius. Short Diagonal of Heptagon is denoted by d_Short symbol.

How to evaluate Short Diagonal of Heptagon given Inradius using this online evaluator? To use this online evaluator for Short Diagonal of Heptagon given Inradius, enter Inradius of Heptagon (r_i) and hit the calculate button.

FAQs on Short Diagonal of Heptagon given Inradius

What is the formula to find Short Diagonal of Heptagon given Inradius?

The formula of Short Diagonal of Heptagon given Inradius is expressed as Short Diagonal of Heptagon = 4*Inradius of Heptagon*tan(pi/7)*cos(pi/7). Here is an example- 19.09088 = 4*11*tan(pi/7)*cos(pi/7).

How to calculate Short Diagonal of Heptagon given Inradius?

With Inradius of Heptagon (r_i) we can find Short Diagonal of Heptagon given Inradius using the formula - Short Diagonal of Heptagon = 4*Inradius of Heptagon*tan(pi/7)*cos(pi/7). This formula also uses Archimedes' constant and , Cosine (cos), Tangent (tan) function(s).

What are the other ways to Calculate Short Diagonal of Heptagon?

Here are the different ways to Calculate Short Diagonal of Heptagon-

Short Diagonal of Heptagon=2*Side of Heptagon*cos(pi/7)
Short Diagonal of Heptagon=4*Long Diagonal of Heptagon*sin(((pi/2))/7)*cos(pi/7)
Short Diagonal of Heptagon=4*Height of Heptagon*tan(((pi/2))/7)*cos(pi/7)

Can the Short Diagonal of Heptagon given Inradius be negative?

No, the Short Diagonal of Heptagon given Inradius, measured in Length cannot be negative.

Which unit is used to measure Short Diagonal of Heptagon given Inradius?

Short Diagonal of Heptagon given Inradius is usually measured using the Meter[m] for Length. Millimeter[m], Kilometer[m], Decimeter[m] are the few other units in which Short Diagonal of Heptagon given Inradius can be measured.

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