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RMS Load Current of Single Phase Half Wave Diode Rectifier with RE Load Formula

GoRMS Load Current of Single Phase Half Wave Diode Rectifier with Resistive Load Formula

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RMS Load Current SP is the root mean square value of the average output voltage of the converter. Check FAQs

I Lrms = \sqrt{\frac{({V s}^{2} + {E L}^{2}) \cdot (π - (2 \cdot θ r)) + {V s}^{2} \cdot \sin (2 \cdot θ d) - 4 \cdot V (max) \cdot E L \cdot \cos (θ d)}{2 \cdot π \cdot r^{2}}}

I_Lrms - RMS Load Current SP?V_s - Source Voltage?E_L - Load EMF?θ_r - Diode Turn On Angle Radians?θ_d - Diode Turn On Angle Degrees?V_(max) - Peak Input Voltage SP?r - Resistance SP?π - Archimedes' constant?

RMS Load Current of Single Phase Half Wave Diode Rectifier with RE Load Example

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Here is how the RMS Load Current of Single Phase Half Wave Diode Rectifier with RE Load equation looks like with Values.

Here is how the RMS Load Current of Single Phase Half Wave Diode Rectifier with RE Load equation looks like with Units.

Here is how the RMS Load Current of Single Phase Half Wave Diode Rectifier with RE Load equation looks like.

6.6237 = \sqrt{\frac{(440^{2} + 333^{2}) \cdot (3.1416 - (2 \cdot 0.01)) + 440^{2} \cdot \sin (2 \cdot 84.26) - 4 \cdot 221 \cdot 333 \cdot \cos (84.26)}{2 \cdot 3.1416 \cdot 59^{2}}}

6.6237A = \sqrt{\frac{({440V}^{2} + {333V}^{2}) \cdot (3.1416 - (2 \cdot 0.01rad)) + {440V}^{2} \cdot \sin (2 \cdot 84.26°) - 4 \cdot 221V \cdot 333V \cdot \cos (84.26°)}{2 \cdot 3.1416 \cdot {59Ω}^{2}}}

6.6237 = \sqrt{\frac{(440^{2} + 333^{2}) \cdot (3.1416 - (2 \cdot 0.01)) + 440^{2} \cdot \sin (2 \cdot 84.26) - 4 \cdot 221 \cdot 333 \cdot \cos (84.26)}{2 \cdot 3.1416 \cdot 59^{2}}}

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RMS Load Current of Single Phase Half Wave Diode Rectifier with RE Load Solution

Follow our step by step solution on how to calculate RMS Load Current of Single Phase Half Wave Diode Rectifier with RE Load?

FIRST Step Consider the formula

I Lrms = \sqrt{\frac{({V s}^{2} + {E L}^{2}) \cdot (π - (2 \cdot θ r)) + {V s}^{2} \cdot \sin (2 \cdot θ d) - 4 \cdot V (max) \cdot E L \cdot \cos (θ d)}{2 \cdot π \cdot r^{2}}}

Next Step Substitute values of Variables

∴

I Lrms = \sqrt{\frac{({440V}^{2} + {333V}^{2}) \cdot (π - (2 \cdot 0.01rad)) + {440V}^{2} \cdot \sin (2 \cdot 84.26°) - 4 \cdot 221V \cdot 333V \cdot \cos (84.26°)}{2 \cdot π \cdot {59Ω}^{2}}}

Next Step Substitute values of Constants

∴

I Lrms = \sqrt{\frac{({440V}^{2} + {333V}^{2}) \cdot (3.1416 - (2 \cdot 0.01rad)) + {440V}^{2} \cdot \sin (2 \cdot 84.26°) - 4 \cdot 221V \cdot 333V \cdot \cos (84.26°)}{2 \cdot 3.1416 \cdot {59Ω}^{2}}}

Next Step Convert Units

∴

I Lrms = \sqrt{\frac{({440V}^{2} + {333V}^{2}) \cdot (3.1416 - (2 \cdot 0.01rad)) + {440V}^{2} \cdot \sin (2 \cdot 1.4706rad) - 4 \cdot 221V \cdot 333V \cdot \cos (1.4706rad)}{2 \cdot 3.1416 \cdot {59Ω}^{2}}}

Next Step Prepare to Evaluate

∴

I Lrms = \sqrt{\frac{(440^{2} + 333^{2}) \cdot (3.1416 - (2 \cdot 0.01)) + 440^{2} \cdot \sin (2 \cdot 1.4706) - 4 \cdot 221 \cdot 333 \cdot \cos (1.4706)}{2 \cdot 3.1416 \cdot 59^{2}}}

Next Step Evaluate

∴

I Lrms = 6.62367144623848A

LAST Step Rounding Answer

∴

I Lrms = 6.6237A

RMS Load Current of Single Phase Half Wave Diode Rectifier with RE Load Formula Elements

Variables

Constants

Functions

RMS Load Current SP

RMS Load Current SP is the root mean square value of the average output voltage of the converter.

Symbol: I_Lrms

Measurement: Electric CurrentUnit: A

Note: Value should be greater than 0.

Formulas to find RMS Load Current SP

Source Voltage

Source Voltage is defined as the voltage or potential difference of the source which is supplying voltage to the rectifier.

Symbol: V_s

Measurement: Electric PotentialUnit: V

Note: Value should be greater than 0.

Formulas to find Source Voltage

Load EMF

Load EMF is the emf at the load of a rectifier based circuit.

Symbol: E_L

Measurement: Electric PotentialUnit: V

Note: Value should be greater than 0.

Formulas to find Load EMF

Diode Turn On Angle Radians

Diode turn on angle radians is the angle beyond which the diode of a rectifier with emf at the load starts conducting.

Symbol: θ_r

Measurement: AngleUnit: rad

Note: Value should be greater than 0.

Formulas to find Diode Turn On Angle Radians

Diode Turn On Angle Degrees

Diode turn on angle degrees is the angle beyond which the diode of a rectifier with emf at the load starts conducting.

Symbol: θ_d

Measurement: AngleUnit: °

Note: Value should be greater than 0.

Formulas to find Diode Turn On Angle Degrees

Peak Input Voltage SP

Peak Input Voltage SP is the peak of the alternating voltage provided at the input of any electrical circuit.

Symbol: V_(max)

Measurement: Electric PotentialUnit: V

Note: Value should be greater than 0.

Formulas to find Peak Input Voltage SP

Resistance SP

Resistance SP is a measure of the opposition to current flow in an electrical circuit. Its S.I unit is ohm.

Symbol: r

Measurement: Electric ResistanceUnit: Ω

Note: Value should be greater than 0.

Formulas to find Resistance SP

Archimedes' constant

Archimedes' constant is a mathematical constant that represents the ratio of the circumference of a circle to its diameter.

Symbol: π

Value: 3.14159265358979323846264338327950288

sin

Sine is a trigonometric function that describes the ratio of the length of the opposite side of a right triangle to the length of the hypotenuse.

Syntax: sin(Angle)

cos

Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle.

Syntax: cos(Angle)

sqrt

A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number.

Syntax: sqrt(Number)

Other Formulas to find RMS Load Current SP

Go RMS Load Current of Single Phase Half Wave Diode Rectifier with Resistive Load

I Lrms = \frac{V (max)}{2 \cdot r}

Other formulas in Half Wave category

Go Average Output Voltage of Single Phase Half Wave Diode Rectifier with Resistive Load

V dc(h) = \frac{V (max)}{π}

Go RMS Output Voltage of Single Phase Half Wave Diode Rectifier with Resistive Load

V rms(h) = \frac{V (max)}{2}

How to Evaluate RMS Load Current of Single Phase Half Wave Diode Rectifier with RE Load?

RMS Load Current of Single Phase Half Wave Diode Rectifier with RE Load evaluator uses RMS Load Current SP = sqrt(((Source Voltage^2+Load EMF^2)*(pi-(2*Diode Turn On Angle Radians))+Source Voltage^2*sin(2*Diode Turn On Angle Degrees)-4*Peak Input Voltage SP*Load EMF*cos(Diode Turn On Angle Degrees))/(2*pi*Resistance SP^2)) to evaluate the RMS Load Current SP, The RMS load current of single phase half wave diode rectifier with RE load formula is defined as the RMS value of the output current over a complete input cycle when the load is RE in nature. RMS Load Current SP is denoted by I_Lrms symbol.

How to evaluate RMS Load Current of Single Phase Half Wave Diode Rectifier with RE Load using this online evaluator? To use this online evaluator for RMS Load Current of Single Phase Half Wave Diode Rectifier with RE Load, enter Source Voltage (V_s), Load EMF (E_L), Diode Turn On Angle Radians (θ_r), Diode Turn On Angle Degrees (θ_d), Peak Input Voltage SP (V_(max)) & Resistance SP (r) and hit the calculate button.

FAQs on RMS Load Current of Single Phase Half Wave Diode Rectifier with RE Load

What is the formula to find RMS Load Current of Single Phase Half Wave Diode Rectifier with RE Load?

The formula of RMS Load Current of Single Phase Half Wave Diode Rectifier with RE Load is expressed as RMS Load Current SP = sqrt(((Source Voltage^2+Load EMF^2)*(pi-(2*Diode Turn On Angle Radians))+Source Voltage^2*sin(2*Diode Turn On Angle Degrees)-4*Peak Input Voltage SP*Load EMF*cos(Diode Turn On Angle Degrees))/(2*pi*Resistance SP^2)). Here is an example- 6.623671 = sqrt(((440^2+333^2)*(pi-(2*0.01))+440^2*sin(2*1.47061442773015)-4*221*333*cos(1.47061442773015))/(2*pi*59^2)).

How to calculate RMS Load Current of Single Phase Half Wave Diode Rectifier with RE Load?

With Source Voltage (V_s), Load EMF (E_L), Diode Turn On Angle Radians (θ_r), Diode Turn On Angle Degrees (θ_d), Peak Input Voltage SP (V_(max)) & Resistance SP (r) we can find RMS Load Current of Single Phase Half Wave Diode Rectifier with RE Load using the formula - RMS Load Current SP = sqrt(((Source Voltage^2+Load EMF^2)*(pi-(2*Diode Turn On Angle Radians))+Source Voltage^2*sin(2*Diode Turn On Angle Degrees)-4*Peak Input Voltage SP*Load EMF*cos(Diode Turn On Angle Degrees))/(2*pi*Resistance SP^2)). This formula also uses Archimedes' constant and , Sine (sin), Cosine (cos), Square Root (sqrt) function(s).

What are the other ways to Calculate RMS Load Current SP?

Here are the different ways to Calculate RMS Load Current SP-

RMS Load Current SP=Peak Input Voltage SP/(2*Resistance SP)

Can the RMS Load Current of Single Phase Half Wave Diode Rectifier with RE Load be negative?

No, the RMS Load Current of Single Phase Half Wave Diode Rectifier with RE Load, measured in Electric Current cannot be negative.

Which unit is used to measure RMS Load Current of Single Phase Half Wave Diode Rectifier with RE Load?

RMS Load Current of Single Phase Half Wave Diode Rectifier with RE Load is usually measured using the Ampere[A] for Electric Current. Milliampere[A], Microampere[A], Centiampere[A] are the few other units in which RMS Load Current of Single Phase Half Wave Diode Rectifier with RE Load can be measured.

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RMS Load Current of Single Phase Half Wave Diode Rectifier with RE Load Formula

​GoRMS Load Current of Single Phase Half Wave Diode Rectifier with Resistive Load Formula

RMS Load Current of Single Phase Half Wave Diode Rectifier with RE Load Example

RMS Load Current of Single Phase Half Wave Diode Rectifier with RE Load Solution

RMS Load Current of Single Phase Half Wave Diode Rectifier with RE Load Formula Elements

Other Formulas to find RMS Load Current SP

Other formulas in Half Wave category

How to Evaluate RMS Load Current of Single Phase Half Wave Diode Rectifier with RE Load?

FAQs on RMS Load Current of Single Phase Half Wave Diode Rectifier with RE Load

Variable Name

GoRMS Load Current of Single Phase Half Wave Diode Rectifier with Resistive Load Formula