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Resultant Vertical Shear Force on Section N+1 Formula

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Vertical Shear Force at other Section means shear force at section N+1. Check FAQs

X (n+1) = W + X n - (F n \cdot \cos (\frac{θ \cdot π}{180})) + (S \cdot \sin (\frac{θ \cdot π}{180}))

X_(n+1) - Vertical Shear Force at other Section?W - Weight of Slice?X_n - Vertical Shear Force?F_n - Total Normal Force in Soil Mechanics?θ - Angle of Base?S - Shear Force on Slice in Soil Mechanics?π - Archimedes' constant?

Resultant Vertical Shear Force on Section N+1 Example

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Here is how the Resultant Vertical Shear Force on Section N+1 equation looks like with Values.

Here is how the Resultant Vertical Shear Force on Section N+1 equation looks like with Units.

Here is how the Resultant Vertical Shear Force on Section N+1 equation looks like.

10.9529 = 20 + 2.89 - (12.09 \cdot \cos (\frac{45 \cdot 3.1416}{180})) + (11.07 \cdot \sin (\frac{45 \cdot 3.1416}{180}))

10.9529N = 20N + 2.89N - (12.09N \cdot \cos (\frac{45° \cdot 3.1416}{180})) + (11.07N \cdot \sin (\frac{45° \cdot 3.1416}{180}))

10.9529 = 20 + 2.89 - (12.09 \cdot \cos (\frac{45 \cdot 3.1416}{180})) + (11.07 \cdot \sin (\frac{45 \cdot 3.1416}{180}))

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Resultant Vertical Shear Force on Section N+1 Solution

Follow our step by step solution on how to calculate Resultant Vertical Shear Force on Section N+1?

FIRST Step Consider the formula

X (n+1) = W + X n - (F n \cdot \cos (\frac{θ \cdot π}{180})) + (S \cdot \sin (\frac{θ \cdot π}{180}))

Next Step Substitute values of Variables

∴

X (n+1) = 20N + 2.89N - (12.09N \cdot \cos (\frac{45° \cdot π}{180})) + (11.07N \cdot \sin (\frac{45° \cdot π}{180}))

Next Step Substitute values of Constants

∴

X (n+1) = 20N + 2.89N - (12.09N \cdot \cos (\frac{45° \cdot 3.1416}{180})) + (11.07N \cdot \sin (\frac{45° \cdot 3.1416}{180}))

Next Step Convert Units

∴

X (n+1) = 20N + 2.89N - (12.09N \cdot \cos (\frac{0.7854rad \cdot 3.1416}{180})) + (11.07N \cdot \sin (\frac{0.7854rad \cdot 3.1416}{180}))

Next Step Prepare to Evaluate

∴

X (n+1) = 20 + 2.89 - (12.09 \cdot \cos (\frac{0.7854 \cdot 3.1416}{180})) + (11.07 \cdot \sin (\frac{0.7854 \cdot 3.1416}{180}))

Next Step Evaluate

∴

X (n+1) = 10.9528762733733N

LAST Step Rounding Answer

∴

X (n+1) = 10.9529N

Resultant Vertical Shear Force on Section N+1 Formula Elements

Variables

Constants

Functions

Vertical Shear Force at other Section

Vertical Shear Force at other Section means shear force at section N+1.

Symbol: X_(n+1)

Measurement: ForceUnit: N

Note: Value can be positive or negative.

Formulas to find Vertical Shear Force at other Section

Weight of Slice

Weight of Slice taken in Bishop's method.

Symbol: W

Measurement: ForceUnit: N