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Resistivity using Volume of Conductor Material (1-Phase 2-Wire US) Formula

GoResistivity using Area of X-Section (1-Phase 2-Wire US) Formula

GoResistivity using Load Current (1-Phase 2-Wire US) Formula

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Resistivity is the measure of how strongly a material opposes the flow of current through them. Check FAQs

ρ = V \cdot P loss \cdot \frac{{(V m \cdot (\cos (Φ)))}^{2}}{8 \cdot {(P \cdot L)}^{2}}

ρ - Resistivity?V - Volume Of Conductor?P_loss - Line Losses?V_m - Maximum Voltage Underground AC?Φ - Phase Difference?P - Power Transmitted?L - Length of Underground AC Wire?

Resistivity using Volume of Conductor Material (1-Phase 2-Wire US) Example

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Here is how the Resistivity using Volume of Conductor Material (1-Phase 2-Wire US) equation looks like with Values.

Here is how the Resistivity using Volume of Conductor Material (1-Phase 2-Wire US) equation looks like with Units.

Here is how the Resistivity using Volume of Conductor Material (1-Phase 2-Wire US) equation looks like.

0.0153 = 60 \cdot 2.67 \cdot \frac{{(230 \cdot (\cos (30)))}^{2}}{8 \cdot {(300 \cdot 24)}^{2}}

0.0153Ω*m = 60m³ \cdot 2.67W \cdot \frac{{(230V \cdot (\cos (30°)))}^{2}}{8 \cdot {(300W \cdot 24m)}^{2}}

0.0153 = 60 \cdot 2.67 \cdot \frac{{(230 \cdot (\cos (30)))}^{2}}{8 \cdot {(300 \cdot 24)}^{2}}

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Resistivity using Volume of Conductor Material (1-Phase 2-Wire US) Solution

Follow our step by step solution on how to calculate Resistivity using Volume of Conductor Material (1-Phase 2-Wire US)?

FIRST Step Consider the formula

ρ = V \cdot P loss \cdot \frac{{(V m \cdot (\cos (Φ)))}^{2}}{8 \cdot {(P \cdot L)}^{2}}

Next Step Substitute values of Variables

∴

ρ = 60m³ \cdot 2.67W \cdot \frac{{(230V \cdot (\cos (30°)))}^{2}}{8 \cdot {(300W \cdot 24m)}^{2}}

Next Step Convert Units

∴

ρ = 60m³ \cdot 2.67W \cdot \frac{{(230V \cdot (\cos (0.5236rad)))}^{2}}{8 \cdot {(300W \cdot 24m)}^{2}}

Next Step Prepare to Evaluate

∴

ρ = 60 \cdot 2.67 \cdot \frac{{(230 \cdot (\cos (0.5236)))}^{2}}{8 \cdot {(300 \cdot 24)}^{2}}

Next Step Evaluate

∴

ρ = 0.0153258463541667Ω*m

LAST Step Rounding Answer

∴

ρ = 0.0153Ω*m

Resistivity using Volume of Conductor Material (1-Phase 2-Wire US) Formula Elements

Variables

Functions

Resistivity

Resistivity is the measure of how strongly a material opposes the flow of current through them.

Symbol: ρ

Measurement: Electric ResistivityUnit: Ω*m

Note: Value can be positive or negative.

Formulas to find Resistivity

Volume Of Conductor

Volume Of Conductor the 3-dimensional space enclosed by a conductor material.

Symbol: V

Measurement: VolumeUnit: m³

Note: Value should be greater than 0.

Formulas to find Volume Of Conductor

Line Losses

Line Losses is defined as the total losses occurring in an Underground AC line when in use.

Symbol: P_loss

Measurement: PowerUnit: W

Note: Value can be positive or negative.

Formulas to find Line Losses

Maximum Voltage Underground AC

Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.

Symbol: V_m

Measurement: Electric PotentialUnit: V

Note: Value can be positive or negative.

Formulas to find Maximum Voltage Underground AC

Phase Difference

Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.

Symbol: Φ

Measurement: AngleUnit: °

Note: Value should be greater than 0.

Formulas to find Phase Difference

Power Transmitted

Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.

Symbol: P

Measurement: PowerUnit: W

Note: Value can be positive or negative.

Formulas to find Power Transmitted

Length of Underground AC Wire

Length of Underground AC Wire is the total length of the wire from one end to other end.

Symbol: L

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Length of Underground AC Wire

cos

Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle.

Syntax: cos(Angle)

Other Formulas to find Resistivity

Go Resistivity using Area of X-Section (1-Phase 2-Wire US)

ρ = A \cdot ({V m}^{2}) \cdot P loss \cdot \frac{{(\cos (Φ))}^{2}}{(4) \cdot L \cdot (P^{2})}

Go Resistivity using Load Current (1-Phase 2-Wire US)

ρ = P loss \cdot \frac{A}{2 \cdot {(I)}^{2} \cdot L}

Other formulas in Resistance and Resistivity category

Go Resistance using Volume of Conductor Material (1-Phase 2-Wire US)

R = V \cdot \frac{ρ}{2 \cdot (A^{2})}

Go Resistance (1-Phase 2-Wire US)

R = ρ \cdot \frac{L}{A}

How to Evaluate Resistivity using Volume of Conductor Material (1-Phase 2-Wire US)?

Resistivity using Volume of Conductor Material (1-Phase 2-Wire US) evaluator uses Resistivity = Volume Of Conductor*Line Losses*(Maximum Voltage Underground AC*(cos(Phase Difference)))^2/(8*(Power Transmitted*Length of Underground AC Wire)^2) to evaluate the Resistivity, The Resistivity using Volume of Conductor Material (1-Phase 2-Wire US) formula is defined as a characteristic property of each material, resistivity is useful in comparing various materials on the basis of their ability to conduct electric currents. High resistivity designates poor conductors. Resistivity is denoted by ρ symbol.

How to evaluate Resistivity using Volume of Conductor Material (1-Phase 2-Wire US) using this online evaluator? To use this online evaluator for Resistivity using Volume of Conductor Material (1-Phase 2-Wire US), enter Volume Of Conductor (V), Line Losses (P_loss), Maximum Voltage Underground AC (V_m), Phase Difference (Φ), Power Transmitted (P) & Length of Underground AC Wire (L) and hit the calculate button.

FAQs on Resistivity using Volume of Conductor Material (1-Phase 2-Wire US)

What is the formula to find Resistivity using Volume of Conductor Material (1-Phase 2-Wire US)?

The formula of Resistivity using Volume of Conductor Material (1-Phase 2-Wire US) is expressed as Resistivity = Volume Of Conductor*Line Losses*(Maximum Voltage Underground AC*(cos(Phase Difference)))^2/(8*(Power Transmitted*Length of Underground AC Wire)^2). Here is an example- 0.015326 = 60*2.67*(230*(cos(0.5235987755982)))^2/(8*(300*24)^2).

How to calculate Resistivity using Volume of Conductor Material (1-Phase 2-Wire US)?

With Volume Of Conductor (V), Line Losses (P_loss), Maximum Voltage Underground AC (V_m), Phase Difference (Φ), Power Transmitted (P) & Length of Underground AC Wire (L) we can find Resistivity using Volume of Conductor Material (1-Phase 2-Wire US) using the formula - Resistivity = Volume Of Conductor*Line Losses*(Maximum Voltage Underground AC*(cos(Phase Difference)))^2/(8*(Power Transmitted*Length of Underground AC Wire)^2). This formula also uses Cosine function(s).

What are the other ways to Calculate Resistivity?

Here are the different ways to Calculate Resistivity-

Resistivity=Area of Underground AC Wire*(Maximum Voltage Underground AC^2)*Line Losses*((cos(Phase Difference))^2)/((4)*Length of Underground AC Wire*(Power Transmitted^2))
Resistivity=Line Losses*Area of Underground AC Wire/(2*(Current Underground AC)^2*Length of Underground AC Wire)
Resistivity=Line Losses*Area of Underground AC Wire*(Maximum Voltage Underground AC*cos(Phase Difference))^2/(4*(Power Transmitted)^2*Length of Underground AC Wire)

Can the Resistivity using Volume of Conductor Material (1-Phase 2-Wire US) be negative?

Yes, the Resistivity using Volume of Conductor Material (1-Phase 2-Wire US), measured in Electric Resistivity can be negative.

Which unit is used to measure Resistivity using Volume of Conductor Material (1-Phase 2-Wire US)?

Resistivity using Volume of Conductor Material (1-Phase 2-Wire US) is usually measured using the Ohm Meter[Ω*m] for Electric Resistivity. Ohm Centimeter[Ω*m], Ohm Inch[Ω*m], Microhm Centimeter[Ω*m] are the few other units in which Resistivity using Volume of Conductor Material (1-Phase 2-Wire US) can be measured.

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Resistivity using Volume of Conductor Material (1-Phase 2-Wire US) Formula

​GoResistivity using Area of X-Section (1-Phase 2-Wire US) Formula

​GoResistivity using Load Current (1-Phase 2-Wire US) Formula

Resistivity using Volume of Conductor Material (1-Phase 2-Wire US) Example

Resistivity using Volume of Conductor Material (1-Phase 2-Wire US) Solution

Resistivity using Volume of Conductor Material (1-Phase 2-Wire US) Formula Elements

Other Formulas to find Resistivity

Other formulas in Resistance and Resistivity category

How to Evaluate Resistivity using Volume of Conductor Material (1-Phase 2-Wire US)?

FAQs on Resistivity using Volume of Conductor Material (1-Phase 2-Wire US)

Variable Name

GoResistivity using Area of X-Section (1-Phase 2-Wire US) Formula

GoResistivity using Load Current (1-Phase 2-Wire US) Formula