FormulaDen.com

Physics Chemistry Math Chemical Engineering Civil Electrical Electronics Electronics and Instrumentation Materials Science Mechanical Production Engineering Financial Health

Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed) Formula

GoResistivity using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) Formula

Fx Copy

LaTeX Copy

Resistivity is the measure of how strongly a material opposes the flow of current through them. Check FAQs

ρ = P loss \cdot \frac{A}{2 \cdot L \cdot (I^{2})}

ρ - Resistivity?P_loss - Line Losses?A - Area of Underground AC Wire?L - Length of Underground AC Wire?I - Current Underground AC?

Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed) Example

With values

With units

Only example

Here is how the Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed) equation looks like with Values.

Here is how the Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed) equation looks like with Units.

Here is how the Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed) equation looks like.

0.0009 = 2.67 \cdot \frac{1.28}{2 \cdot 24 \cdot (9^{2})}

0.0009Ω*m = 2.67W \cdot \frac{1.28m²}{2 \cdot 24m \cdot ({9A}^{2})}

0.0009 = 2.67 \cdot \frac{1.28}{2 \cdot 24 \cdot (9^{2})}

Tip: Use pencil ( Pencil

) icon above to edit Input Values and Units.

Calculate

Recalculate

Solution

Copy

Reset

You are here -

Home » Category

Engineering » Category

Electrical » Category

Power System » fx Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed)

Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed) Solution

Follow our step by step solution on how to calculate Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed)?

FIRST Step Consider the formula

ρ = P loss \cdot \frac{A}{2 \cdot L \cdot (I^{2})}

Next Step Substitute values of Variables

∴

ρ = 2.67W \cdot \frac{1.28m²}{2 \cdot 24m \cdot ({9A}^{2})}

Next Step Prepare to Evaluate

∴

ρ = 2.67 \cdot \frac{1.28}{2 \cdot 24 \cdot (9^{2})}

Next Step Evaluate

∴

ρ = 0.000879012345679012Ω*m

LAST Step Rounding Answer

∴

ρ = 0.0009Ω*m

Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed) Formula Elements

Variables

Resistivity

Resistivity is the measure of how strongly a material opposes the flow of current through them.

Symbol: ρ

Measurement: Electric ResistivityUnit: Ω*m

Note: Value can be positive or negative.

Formulas to find Resistivity

Line Losses

Line Losses is defined as the total losses occurring in an Underground AC line when in use.

Symbol: P_loss

Measurement: PowerUnit: W

Note: Value can be positive or negative.

Formulas to find Line Losses

Area of Underground AC Wire

Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.

Symbol: A

Measurement: AreaUnit: m²

Note: Value can be positive or negative.

Formulas to find Area of Underground AC Wire

Length of Underground AC Wire

Length of Underground AC Wire is the total length of the wire from one end to other end.

Symbol: L

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Length of Underground AC Wire

Current Underground AC

Current Underground AC is defined as the current flowing through the overhead ac supply wire.

Symbol: I

Measurement: Electric CurrentUnit: A

Note: Value can be positive or negative.

Formulas to find Current Underground AC

Other Formulas to find Resistivity

Go Resistivity using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)

ρ = A \cdot P loss \cdot \frac{{(V m \cdot \cos (Φ))}^{2}}{4 \cdot (P^{2}) \cdot L}

Other formulas in Resistance and Resistivity category

Go Resistance using Line Losses (1-Phase 2-Wire Mid-Point Earthed)

R = \frac{P loss}{2 \cdot (I^{2})}

How to Evaluate Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed)?

Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed) evaluator uses Resistivity = Line Losses*Area of Underground AC Wire/(2*Length of Underground AC Wire*(Current Underground AC^2)) to evaluate the Resistivity, The Resistivity using Line Losses (1-phase 2-wire Mid-point Earthed) formula is defined as a characteristic property of each material, resistivity is useful in comparing various materials on the basis of their ability to conduct electric currents. High resistivity designates poor conductors. Resistivity is denoted by ρ symbol.

How to evaluate Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed) using this online evaluator? To use this online evaluator for Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed), enter Line Losses (P_loss), Area of Underground AC Wire (A), Length of Underground AC Wire (L) & Current Underground AC (I) and hit the calculate button.

FAQs on Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed)

What is the formula to find Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed)?

The formula of Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed) is expressed as Resistivity = Line Losses*Area of Underground AC Wire/(2*Length of Underground AC Wire*(Current Underground AC^2)). Here is an example- 0.000879 = 2.67*1.28/(2*24*(9^2)).

How to calculate Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed)?

With Line Losses (P_loss), Area of Underground AC Wire (A), Length of Underground AC Wire (L) & Current Underground AC (I) we can find Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed) using the formula - Resistivity = Line Losses*Area of Underground AC Wire/(2*Length of Underground AC Wire*(Current Underground AC^2)).

What are the other ways to Calculate Resistivity?

Here are the different ways to Calculate Resistivity-

Resistivity=Area of Underground AC Wire*Line Losses*((Maximum Voltage Underground AC*cos(Phase Difference))^2)/(4*(Power Transmitted^2)*Length of Underground AC Wire)

Can the Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed) be negative?

Yes, the Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed), measured in Electric Resistivity can be negative.

Which unit is used to measure Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed)?

Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed) is usually measured using the Ohm Meter[Ω*m] for Electric Resistivity. Ohm Centimeter[Ω*m], Ohm Inch[Ω*m], Microhm Centimeter[Ω*m] are the few other units in which Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed) can be measured.

Let Others Know

✖

Facebook

Twitter

Copied!

: Value
: Unit

Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed) Formula

​GoResistivity using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) Formula

Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed) Example

Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed) Solution

Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed) Formula Elements

Other Formulas to find Resistivity

Other formulas in Resistance and Resistivity category

How to Evaluate Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed)?

FAQs on Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed)

Variable Name

GoResistivity using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) Formula