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Resistivity using Area of X-Section (1-Phase 2-Wire US) Formula

GoResistivity using Volume of Conductor Material (1-Phase 2-Wire US) Formula

GoResistivity using Load Current (1-Phase 2-Wire US) Formula

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Resistivity is the measure of how strongly a material opposes the flow of current through them. Check FAQs

ρ = A \cdot ({V m}^{2}) \cdot P loss \cdot \frac{{(\cos (Φ))}^{2}}{(4) \cdot L \cdot (P^{2})}

ρ - Resistivity?A - Area of Underground AC Wire?V_m - Maximum Voltage Underground AC?P_loss - Line Losses?Φ - Phase Difference?L - Length of Underground AC Wire?P - Power Transmitted?

Resistivity using Area of X-Section (1-Phase 2-Wire US) Example

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Here is how the Resistivity using Area of X-Section (1-Phase 2-Wire US) equation looks like with Values.

Here is how the Resistivity using Area of X-Section (1-Phase 2-Wire US) equation looks like with Units.

Here is how the Resistivity using Area of X-Section (1-Phase 2-Wire US) equation looks like.

0.0157 = 1.28 \cdot (230^{2}) \cdot 2.67 \cdot \frac{{(\cos (30))}^{2}}{(4) \cdot 24 \cdot (300^{2})}

0.0157Ω*m = 1.28m² \cdot ({230V}^{2}) \cdot 2.67W \cdot \frac{{(\cos (30°))}^{2}}{(4) \cdot 24m \cdot ({300W}^{2})}

0.0157 = 1.28 \cdot (230^{2}) \cdot 2.67 \cdot \frac{{(\cos (30))}^{2}}{(4) \cdot 24 \cdot (300^{2})}

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Resistivity using Area of X-Section (1-Phase 2-Wire US) Solution

Follow our step by step solution on how to calculate Resistivity using Area of X-Section (1-Phase 2-Wire US)?

FIRST Step Consider the formula

ρ = A \cdot ({V m}^{2}) \cdot P loss \cdot \frac{{(\cos (Φ))}^{2}}{(4) \cdot L \cdot (P^{2})}

Next Step Substitute values of Variables

∴

ρ = 1.28m² \cdot ({230V}^{2}) \cdot 2.67W \cdot \frac{{(\cos (30°))}^{2}}{(4) \cdot 24m \cdot ({300W}^{2})}

Next Step Convert Units

∴

ρ = 1.28m² \cdot ({230V}^{2}) \cdot 2.67W \cdot \frac{{(\cos (0.5236rad))}^{2}}{(4) \cdot 24m \cdot ({300W}^{2})}

Next Step Prepare to Evaluate

∴

ρ = 1.28 \cdot (230^{2}) \cdot 2.67 \cdot \frac{{(\cos (0.5236))}^{2}}{(4) \cdot 24 \cdot (300^{2})}

Next Step Evaluate

∴

ρ = 0.0156936666666667Ω*m

LAST Step Rounding Answer

∴

ρ = 0.0157Ω*m

Resistivity using Area of X-Section (1-Phase 2-Wire US) Formula Elements

Variables

Functions

Resistivity

Resistivity is the measure of how strongly a material opposes the flow of current through them.

Symbol: ρ

Measurement: Electric ResistivityUnit: Ω*m

Note: Value can be positive or negative.

Formulas to find Resistivity

Area of Underground AC Wire

Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.

Symbol: A

Measurement: AreaUnit: m²

Note: Value can be positive or negative.

Formulas to find Area of Underground AC Wire

Maximum Voltage Underground AC

Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.

Symbol: V_m

Measurement: Electric PotentialUnit: V

Note: Value can be positive or negative.

Formulas to find Maximum Voltage Underground AC

Line Losses

Line Losses is defined as the total losses occurring in an Underground AC line when in use.

Symbol: P_loss

Measurement: PowerUnit: W

Note: Value can be positive or negative.

Formulas to find Line Losses

Phase Difference

Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.

Symbol: Φ

Measurement: AngleUnit: °

Note: Value should be greater than 0.

Formulas to find Phase Difference

Length of Underground AC Wire

Length of Underground AC Wire is the total length of the wire from one end to other end.

Symbol: L

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Length of Underground AC Wire

Power Transmitted

Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.

Symbol: P

Measurement: PowerUnit: W

Note: Value can be positive or negative.

Formulas to find Power Transmitted

cos

Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle.

Syntax: cos(Angle)

Other Formulas to find Resistivity

Go Resistivity using Volume of Conductor Material (1-Phase 2-Wire US)

ρ = V \cdot P loss \cdot \frac{{(V m \cdot (\cos (Φ)))}^{2}}{8 \cdot {(P \cdot L)}^{2}}

Go Resistivity using Load Current (1-Phase 2-Wire US)

ρ = P loss \cdot \frac{A}{2 \cdot {(I)}^{2} \cdot L}

Other formulas in Resistance and Resistivity category

Go Resistance using Volume of Conductor Material (1-Phase 2-Wire US)

R = V \cdot \frac{ρ}{2 \cdot (A^{2})}

Go Resistance (1-Phase 2-Wire US)

R = ρ \cdot \frac{L}{A}

How to Evaluate Resistivity using Area of X-Section (1-Phase 2-Wire US)?

Resistivity using Area of X-Section (1-Phase 2-Wire US) evaluator uses Resistivity = Area of Underground AC Wire*(Maximum Voltage Underground AC^2)*Line Losses*((cos(Phase Difference))^2)/((4)*Length of Underground AC Wire*(Power Transmitted^2)) to evaluate the Resistivity, The Resistivity using Area of X-Section (1-Phase 2-Wire US) formula is defined as a characteristic property of each material, resistivity is useful in comparing various materials on the basis of their ability to conduct electric currents. High resistivity designates poor conductors. Resistivity is denoted by ρ symbol.

How to evaluate Resistivity using Area of X-Section (1-Phase 2-Wire US) using this online evaluator? To use this online evaluator for Resistivity using Area of X-Section (1-Phase 2-Wire US), enter Area of Underground AC Wire (A), Maximum Voltage Underground AC (V_m), Line Losses (P_loss), Phase Difference (Φ), Length of Underground AC Wire (L) & Power Transmitted (P) and hit the calculate button.

FAQs on Resistivity using Area of X-Section (1-Phase 2-Wire US)

What is the formula to find Resistivity using Area of X-Section (1-Phase 2-Wire US)?

The formula of Resistivity using Area of X-Section (1-Phase 2-Wire US) is expressed as Resistivity = Area of Underground AC Wire*(Maximum Voltage Underground AC^2)*Line Losses*((cos(Phase Difference))^2)/((4)*Length of Underground AC Wire*(Power Transmitted^2)). Here is an example- 0.015694 = 1.28*(230^2)*2.67*((cos(0.5235987755982))^2)/((4)*24*(300^2)).

How to calculate Resistivity using Area of X-Section (1-Phase 2-Wire US)?

With Area of Underground AC Wire (A), Maximum Voltage Underground AC (V_m), Line Losses (P_loss), Phase Difference (Φ), Length of Underground AC Wire (L) & Power Transmitted (P) we can find Resistivity using Area of X-Section (1-Phase 2-Wire US) using the formula - Resistivity = Area of Underground AC Wire*(Maximum Voltage Underground AC^2)*Line Losses*((cos(Phase Difference))^2)/((4)*Length of Underground AC Wire*(Power Transmitted^2)). This formula also uses Cosine function(s).

What are the other ways to Calculate Resistivity?

Here are the different ways to Calculate Resistivity-

Resistivity=Volume Of Conductor*Line Losses*(Maximum Voltage Underground AC*(cos(Phase Difference)))^2/(8*(Power Transmitted*Length of Underground AC Wire)^2)
Resistivity=Line Losses*Area of Underground AC Wire/(2*(Current Underground AC)^2*Length of Underground AC Wire)
Resistivity=Line Losses*Area of Underground AC Wire*(Maximum Voltage Underground AC*cos(Phase Difference))^2/(4*(Power Transmitted)^2*Length of Underground AC Wire)

Can the Resistivity using Area of X-Section (1-Phase 2-Wire US) be negative?

Yes, the Resistivity using Area of X-Section (1-Phase 2-Wire US), measured in Electric Resistivity can be negative.

Which unit is used to measure Resistivity using Area of X-Section (1-Phase 2-Wire US)?

Resistivity using Area of X-Section (1-Phase 2-Wire US) is usually measured using the Ohm Meter[Ω*m] for Electric Resistivity. Ohm Centimeter[Ω*m], Ohm Inch[Ω*m], Microhm Centimeter[Ω*m] are the few other units in which Resistivity using Area of X-Section (1-Phase 2-Wire US) can be measured.

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Resistivity using Area of X-Section (1-Phase 2-Wire US) Formula

​GoResistivity using Volume of Conductor Material (1-Phase 2-Wire US) Formula

​GoResistivity using Load Current (1-Phase 2-Wire US) Formula

Resistivity using Area of X-Section (1-Phase 2-Wire US) Example

Resistivity using Area of X-Section (1-Phase 2-Wire US) Solution

Resistivity using Area of X-Section (1-Phase 2-Wire US) Formula Elements

Other Formulas to find Resistivity

Other formulas in Resistance and Resistivity category

How to Evaluate Resistivity using Area of X-Section (1-Phase 2-Wire US)?

FAQs on Resistivity using Area of X-Section (1-Phase 2-Wire US)

Variable Name

GoResistivity using Volume of Conductor Material (1-Phase 2-Wire US) Formula

GoResistivity using Load Current (1-Phase 2-Wire US) Formula