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Relative Lowering of Vapour Pressure given Osmotic Pressure Formula

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The Relative Lowering of Vapour Pressure is the lowering of vapour pressure of pure solvent on addition of solute. Check FAQs

Δp = \frac{π \cdot V m}{[R] \cdot T}

Δp - Relative Lowering of Vapour Pressure?π - Osmotic Pressure?V_m - Molar Volume?T - Temperature?[R] - Universal gas constant?

Relative Lowering of Vapour Pressure given Osmotic Pressure Example

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Here is how the Relative Lowering of Vapour Pressure given Osmotic Pressure equation looks like with Values.

Here is how the Relative Lowering of Vapour Pressure given Osmotic Pressure equation looks like with Units.

Here is how the Relative Lowering of Vapour Pressure given Osmotic Pressure equation looks like.

0.0521 = \frac{2.5 \cdot 51.6}{8.3145 \cdot 298}

0.0521 = \frac{2.5Pa \cdot 51.6m³/mol}{8.3145 \cdot 298K}

0.0521 = \frac{2.5 \cdot 51.6}{8.3145 \cdot 298}

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Relative Lowering of Vapour Pressure given Osmotic Pressure Solution

Follow our step by step solution on how to calculate Relative Lowering of Vapour Pressure given Osmotic Pressure?

FIRST Step Consider the formula

Δp = \frac{π \cdot V m}{[R] \cdot T}

Next Step Substitute values of Variables

∴

Δp = \frac{2.5Pa \cdot 51.6m³/mol}{[R] \cdot 298K}

Next Step Substitute values of Constants

∴

Δp = \frac{2.5Pa \cdot 51.6m³/mol}{8.3145 \cdot 298K}

Next Step Prepare to Evaluate

∴

Δp = \frac{2.5 \cdot 51.6}{8.3145 \cdot 298}

Next Step Evaluate

∴

Δp = 0.0520642073842673

LAST Step Rounding Answer

∴

Δp = 0.0521

Relative Lowering of Vapour Pressure given Osmotic Pressure Formula Elements

Variables

Constants

Relative Lowering of Vapour Pressure

The Relative Lowering of Vapour Pressure is the lowering of vapour pressure of pure solvent on addition of solute.

Symbol: Δp

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Formulas to find Relative Lowering of Vapour Pressure

Osmotic Pressure

The Osmotic Pressure is the minimum pressure which needs to be applied to a solution to prevent the inward flow of its pure solvent across a semipermeable membrane.

Symbol: π

Measurement: PressureUnit: Pa

Note: Value should be greater than 0.

Formulas to find Osmotic Pressure

Molar Volume

Molar Volume is the volume occupied by one mole of a substance which can be a chemical element or a chemical compound at Standard Temperature and Pressure.

Symbol: V_m

Measurement: Molar Magnetic SusceptibilityUnit: m³/mol

Note: Value can be positive or negative.

Formulas to find Molar Volume

Temperature

Temperature is the degree or intensity of heat present in a substance or object.

Symbol: T

Measurement: TemperatureUnit: K

Note: Value can be positive or negative.

Formulas to find Temperature

Universal gas constant

Universal gas constant is a fundamental physical constant that appears in the ideal gas law, relating the pressure, volume, and temperature of an ideal gas.

Symbol: [R]

Value: 8.31446261815324

Other formulas in Osmotic Pressure category

Go Density of Solution given Osmotic Pressure

ρ sol = \frac{π}{[g] \cdot h}

Go Equilibrium Height given Osmotic Pressure

h = \frac{π}{[g] \cdot ρ sol}

Go Osmotic Pressure given Volume and Osmotic Pressure of Two Substances

π = \frac{(π 1 \cdot V 1) + (π 2 \cdot V 2)}{[R] \cdot T}

Go Moles of Solute given Osmotic Pressure

n = \frac{π \cdot V}{[R] \cdot T}

How to Evaluate Relative Lowering of Vapour Pressure given Osmotic Pressure?

Relative Lowering of Vapour Pressure given Osmotic Pressure evaluator uses Relative Lowering of Vapour Pressure = (Osmotic Pressure*Molar Volume)/([R]*Temperature) to evaluate the Relative Lowering of Vapour Pressure, The Relative Lowering of Vapour Pressure given Osmotic Pressure is the relative measure of lowering of vapour pressure on addition of solute to solvent. Relative Lowering of Vapour Pressure is denoted by Δp symbol.

How to evaluate Relative Lowering of Vapour Pressure given Osmotic Pressure using this online evaluator? To use this online evaluator for Relative Lowering of Vapour Pressure given Osmotic Pressure, enter Osmotic Pressure (π), Molar Volume (V_m) & Temperature (T) and hit the calculate button.

FAQs on Relative Lowering of Vapour Pressure given Osmotic Pressure

What is the formula to find Relative Lowering of Vapour Pressure given Osmotic Pressure?

The formula of Relative Lowering of Vapour Pressure given Osmotic Pressure is expressed as Relative Lowering of Vapour Pressure = (Osmotic Pressure*Molar Volume)/([R]*Temperature). Here is an example- 0.052064 = (2.5*51.6)/([R]*298).

How to calculate Relative Lowering of Vapour Pressure given Osmotic Pressure?

With Osmotic Pressure (π), Molar Volume (V_m) & Temperature (T) we can find Relative Lowering of Vapour Pressure given Osmotic Pressure using the formula - Relative Lowering of Vapour Pressure = (Osmotic Pressure*Molar Volume)/([R]*Temperature). This formula also uses Universal gas constant .

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Relative Lowering of Vapour Pressure given Osmotic Pressure Formula

Relative Lowering of Vapour Pressure given Osmotic Pressure Example

Relative Lowering of Vapour Pressure given Osmotic Pressure Solution

Relative Lowering of Vapour Pressure given Osmotic Pressure Formula Elements

Other formulas in Osmotic Pressure category

How to Evaluate Relative Lowering of Vapour Pressure given Osmotic Pressure?

FAQs on Relative Lowering of Vapour Pressure given Osmotic Pressure

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