Fx Copy
LaTeX Copy
The Relative Lowering of Vapour Pressure is the lowering of vapour pressure of pure solvent on addition of solute. Check FAQs
Δp=nN
Δp - Relative Lowering of Vapour Pressure?n - Number of Moles of Solute?N - Number of Moles of Solvent?

Relative Lowering of Vapour Pressure given Number of Moles for Dilute Solution Example

With values
With units
Only example

Here is how the Relative Lowering of Vapour Pressure given Number of Moles for Dilute Solution equation looks like with Values.

Here is how the Relative Lowering of Vapour Pressure given Number of Moles for Dilute Solution equation looks like with Units.

Here is how the Relative Lowering of Vapour Pressure given Number of Moles for Dilute Solution equation looks like.

0.052Edit=0.52Edit10Edit
You are here -
HomeIcon Home » Category Chemistry » Category Solution and Colligative properties » Category Relative Lowering of Vapour Pressure » fx Relative Lowering of Vapour Pressure given Number of Moles for Dilute Solution

Relative Lowering of Vapour Pressure given Number of Moles for Dilute Solution Solution

Follow our step by step solution on how to calculate Relative Lowering of Vapour Pressure given Number of Moles for Dilute Solution?

FIRST Step Consider the formula
Δp=nN
Next Step Substitute values of Variables
Δp=0.52mol10mol
Next Step Prepare to Evaluate
Δp=0.5210
LAST Step Evaluate
Δp=0.052

Relative Lowering of Vapour Pressure given Number of Moles for Dilute Solution Formula Elements

Variables
Relative Lowering of Vapour Pressure
The Relative Lowering of Vapour Pressure is the lowering of vapour pressure of pure solvent on addition of solute.
Symbol: Δp
Measurement: NAUnit: Unitless
Note: Value can be positive or negative.
Number of Moles of Solute
The number of Moles of Solute is the total number of representative particles present in the solute.
Symbol: n
Measurement: Amount of SubstanceUnit: mol
Note: Value can be positive or negative.
Number of Moles of Solvent
Number of Moles of Solvent is the total number of representative particles present in the solvent.
Symbol: N
Measurement: Amount of SubstanceUnit: mol
Note: Value can be positive or negative.

Other Formulas to find Relative Lowering of Vapour Pressure

​Go Ostwald-Walker Dynamic Method for Relative Lowering of Vapour Pressure
Δp=wBwA+wB
​Go Relative Lowering of Vapour Pressure
Δp=po-ppo
​Go Relative Lowering of Vapour Pressure given Number of Moles for Concentrated Solution
Δp=nn+N

Other formulas in Relative Lowering of Vapour Pressure category

​Go Osmotic Pressure for Non Electrolyte
π=c[R]T
​Go Osmotic Pressure given Concentration of Two Substances
π=(C1+C2)[R]T
​Go Osmotic Pressure given Density of Solution
π=ρsol[g]h
​Go Osmotic Pressure given Depression in Freezing Point
π=ΔHfusionΔTfTVm(Tfp2)

How to Evaluate Relative Lowering of Vapour Pressure given Number of Moles for Dilute Solution?

Relative Lowering of Vapour Pressure given Number of Moles for Dilute Solution evaluator uses Relative Lowering of Vapour Pressure = Number of Moles of Solute/Number of Moles of Solvent to evaluate the Relative Lowering of Vapour Pressure, The Relative Lowering of Vapour Pressure given Number of Moles for Dilute Solution is the ratio of no. of moles of solute to no. of moles of solvent. Relative Lowering of Vapour Pressure is denoted by Δp symbol.

How to evaluate Relative Lowering of Vapour Pressure given Number of Moles for Dilute Solution using this online evaluator? To use this online evaluator for Relative Lowering of Vapour Pressure given Number of Moles for Dilute Solution, enter Number of Moles of Solute (n) & Number of Moles of Solvent (N) and hit the calculate button.

FAQs on Relative Lowering of Vapour Pressure given Number of Moles for Dilute Solution

What is the formula to find Relative Lowering of Vapour Pressure given Number of Moles for Dilute Solution?
The formula of Relative Lowering of Vapour Pressure given Number of Moles for Dilute Solution is expressed as Relative Lowering of Vapour Pressure = Number of Moles of Solute/Number of Moles of Solvent. Here is an example- 0.1 = 0.52/10.
How to calculate Relative Lowering of Vapour Pressure given Number of Moles for Dilute Solution?
With Number of Moles of Solute (n) & Number of Moles of Solvent (N) we can find Relative Lowering of Vapour Pressure given Number of Moles for Dilute Solution using the formula - Relative Lowering of Vapour Pressure = Number of Moles of Solute/Number of Moles of Solvent.
What are the other ways to Calculate Relative Lowering of Vapour Pressure?
Here are the different ways to Calculate Relative Lowering of Vapour Pressure-
  • Relative Lowering of Vapour Pressure=Loss of Mass in Bulb Set B/(Loss of Mass in bulb set A+Loss of Mass in Bulb Set B)OpenImg
  • Relative Lowering of Vapour Pressure=(Vapour Pressure of Pure Solvent-Vapour Pressure of Solvent in Solution)/Vapour Pressure of Pure SolventOpenImg
  • Relative Lowering of Vapour Pressure=Number of Moles of Solute/(Number of Moles of Solute+Number of Moles of Solvent)OpenImg
Copied!