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Relative Lowering of Vapour Pressure given Molecular Mass and Molality Formula

GoRelative Lowering of Vapour Pressure Formula

GoRelative Lowering of Vapour Pressure given Number of Moles for Dilute Solution Formula

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The Relative Lowering of Vapour Pressure is the lowering of vapour pressure of pure solvent on addition of solute. Check FAQs

Δp = \frac{m \cdot M}{1000}

Δp - Relative Lowering of Vapour Pressure?m - Molality?M - Molecular Mass Solvent?

Relative Lowering of Vapour Pressure given Molecular Mass and Molality Example

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Here is how the Relative Lowering of Vapour Pressure given Molecular Mass and Molality equation looks like with Values.

Here is how the Relative Lowering of Vapour Pressure given Molecular Mass and Molality equation looks like with Units.

Here is how the Relative Lowering of Vapour Pressure given Molecular Mass and Molality equation looks like.

3.2E-5 = \frac{1.79 \cdot 18}{1000}

3.2E-5 = \frac{1.79mol/kg \cdot 18g}{1000}

3.2E-5 = \frac{1.79 \cdot 18}{1000}

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Relative Lowering of Vapour Pressure given Molecular Mass and Molality Solution

Follow our step by step solution on how to calculate Relative Lowering of Vapour Pressure given Molecular Mass and Molality?

FIRST Step Consider the formula

Δp = \frac{m \cdot M}{1000}

Next Step Substitute values of Variables

∴

Δp = \frac{1.79mol/kg \cdot 18g}{1000}

Next Step Convert Units

∴

Δp = \frac{1.79mol/kg \cdot 0.018kg}{1000}

Next Step Prepare to Evaluate

∴

Δp = \frac{1.79 \cdot 0.018}{1000}

Next Step Evaluate

∴

Δp = 3.222E-05

LAST Step Rounding Answer

∴

Δp = 3.2E-5

Relative Lowering of Vapour Pressure given Molecular Mass and Molality Formula Elements

Variables

Relative Lowering of Vapour Pressure

The Relative Lowering of Vapour Pressure is the lowering of vapour pressure of pure solvent on addition of solute.

Symbol: Δp

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Formulas to find Relative Lowering of Vapour Pressure

Molality

Molality is defined as the total number of moles of solute per kilograms of solvent present in the solution.

Symbol: m

Measurement: MolalityUnit: mol/kg

Note: Value can be positive or negative.

Formulas to find Molality

Molecular Mass Solvent

The Molecular Mass Solvent is sum of the atomic masses of all atoms in a molecule, based on a scale in which the atomic masses.

Symbol: M

Measurement: WeightUnit: g

Note: Value should be greater than 0.

Formulas to find Molecular Mass Solvent

Other Formulas to find Relative Lowering of Vapour Pressure

Go Relative Lowering of Vapour Pressure

Δp = \frac{p o - p}{p o}

Go Relative Lowering of Vapour Pressure given Number of Moles for Dilute Solution

Δp = \frac{n}{N}

Go Relative Lowering of Vapour Pressure given Number of Moles for Concentrated Solution

Δp = \frac{n}{n + N}

Go Relative Lowering of Vapour Pressure given Weight and Molecular Mass of Solute and Solvent

Δp = \frac{w \cdot M}{W \cdot M solute}

Other formulas in Relative Lowering of Vapour Pressure category

Go Mole Fraction of Solute given Vapour Pressure

x solute = \frac{p o - p}{p o}

Go Mole Fraction of Solvent given Vapour Pressure

x 2 = \frac{p}{p o}

Go Molecular Mass of Solvent given Relative Lowering of Vapour Pressure

M = \frac{(p o - p) \cdot 1000}{m \cdot p o}

Go Molality using Relative Lowering of Vapour Pressure

m = \frac{(p o - p) \cdot 1000}{M \cdot p o}

How to Evaluate Relative Lowering of Vapour Pressure given Molecular Mass and Molality?

Relative Lowering of Vapour Pressure given Molecular Mass and Molality evaluator uses Relative Lowering of Vapour Pressure = (Molality*Molecular Mass Solvent)/1000 to evaluate the Relative Lowering of Vapour Pressure, The Relative Lowering of Vapour Pressure given Molecular Mass and Molality is the relative measure of lowering of vapour pressure on addition of solute to solvent. Relative Lowering of Vapour Pressure is denoted by Δp symbol.

How to evaluate Relative Lowering of Vapour Pressure given Molecular Mass and Molality using this online evaluator? To use this online evaluator for Relative Lowering of Vapour Pressure given Molecular Mass and Molality, enter Molality (m) & Molecular Mass Solvent (M) and hit the calculate button.

FAQs on Relative Lowering of Vapour Pressure given Molecular Mass and Molality

What is the formula to find Relative Lowering of Vapour Pressure given Molecular Mass and Molality?

The formula of Relative Lowering of Vapour Pressure given Molecular Mass and Molality is expressed as Relative Lowering of Vapour Pressure = (Molality*Molecular Mass Solvent)/1000. Here is an example- 3.2E-5 = (1.79*0.018)/1000.

How to calculate Relative Lowering of Vapour Pressure given Molecular Mass and Molality?

With Molality (m) & Molecular Mass Solvent (M) we can find Relative Lowering of Vapour Pressure given Molecular Mass and Molality using the formula - Relative Lowering of Vapour Pressure = (Molality*Molecular Mass Solvent)/1000.

What are the other ways to Calculate Relative Lowering of Vapour Pressure?

Here are the different ways to Calculate Relative Lowering of Vapour Pressure-

Relative Lowering of Vapour Pressure=(Vapour Pressure of Pure Solvent-Vapour Pressure of Solvent in Solution)/Vapour Pressure of Pure Solvent
Relative Lowering of Vapour Pressure=Number of Moles of Solute/Number of Moles of Solvent
Relative Lowering of Vapour Pressure=Number of Moles of Solute/(Number of Moles of Solute+Number of Moles of Solvent)

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