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Reduced Volume of Real Gas given Clausius Parameter c, Reduced and Actual Parameters Formula

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Reduced Volume given RP AP of a fluid is computed from the ideal gas law as the ratio of its actual volume to critical volume. Check FAQs

V r_RP_AP = \frac{V real}{(\frac{3 \cdot [R] \cdot (\frac{T real}{T r})}{8 \cdot (\frac{P real}{P r})}) - c}

V_{r_RP_AP} - Reduced Volume given RP AP?V_real - Volume of Real Gas?T_real - Real Gas Temperature?T_r - Reduced Temperature?P_real - Real Gas Pressure?P_r - Reduced Pressure?c - Clausius Parameter c?[R] - Universal gas constant?

Reduced Volume of Real Gas given Clausius Parameter c, Reduced and Actual Parameters Example

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Here is how the Reduced Volume of Real Gas given Clausius Parameter c, Reduced and Actual Parameters equation looks like with Values.

Here is how the Reduced Volume of Real Gas given Clausius Parameter c, Reduced and Actual Parameters equation looks like with Units.

Here is how the Reduced Volume of Real Gas given Clausius Parameter c, Reduced and Actual Parameters equation looks like.

0.0297 = \frac{22}{(\frac{3 \cdot 8.3145 \cdot (\frac{300}{10})}{8 \cdot (\frac{101}{0.8})}) - 0.0002}

0.0297 = \frac{22L}{(\frac{3 \cdot 8.3145 \cdot (\frac{300K}{10})}{8 \cdot (\frac{101Pa}{0.8})}) - 0.0002}

0.0297 = \frac{22}{(\frac{3 \cdot 8.3145 \cdot (\frac{300}{10})}{8 \cdot (\frac{101}{0.8})}) - 0.0002}

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Reduced Volume of Real Gas given Clausius Parameter c, Reduced and Actual Parameters Solution

Follow our step by step solution on how to calculate Reduced Volume of Real Gas given Clausius Parameter c, Reduced and Actual Parameters?

FIRST Step Consider the formula

V r_RP_AP = \frac{V real}{(\frac{3 \cdot [R] \cdot (\frac{T real}{T r})}{8 \cdot (\frac{P real}{P r})}) - c}

Next Step Substitute values of Variables

∴

V r_RP_AP = \frac{22L}{(\frac{3 \cdot [R] \cdot (\frac{300K}{10})}{8 \cdot (\frac{101Pa}{0.8})}) - 0.0002}

Next Step Substitute values of Constants

∴

V r_RP_AP = \frac{22L}{(\frac{3 \cdot 8.3145 \cdot (\frac{300K}{10})}{8 \cdot (\frac{101Pa}{0.8})}) - 0.0002}

Next Step Convert Units

∴

V r_RP_AP = \frac{0.022m³}{(\frac{3 \cdot 8.3145 \cdot (\frac{300K}{10})}{8 \cdot (\frac{101Pa}{0.8})}) - 0.0002}

Next Step Prepare to Evaluate

∴

V r_RP_AP = \frac{0.022}{(\frac{3 \cdot 8.3145 \cdot (\frac{300}{10})}{8 \cdot (\frac{101}{0.8})}) - 0.0002}

Next Step Evaluate

∴

V r_RP_AP = 0.0297019259756425

LAST Step Rounding Answer

∴

V r_RP_AP = 0.0297

Reduced Volume of Real Gas given Clausius Parameter c, Reduced and Actual Parameters Formula Elements

Variables

Constants

Reduced Volume given RP AP

Reduced Volume given RP AP of a fluid is computed from the ideal gas law as the ratio of its actual volume to critical volume.

Symbol: V_{r_RP_AP}

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Formulas to find Reduced Volume given RP AP

Volume of Real Gas

Volume of Real Gas is the space occupied by that real gas at standard temperature and pressure.

Symbol: V_real

Measurement: VolumeUnit: L

Note: Value should be greater than 0.

Formulas to find Volume of Real Gas

Real Gas Temperature

Real Gas Temperature is the degree or intensity of heat present in a substance or object.

Symbol: T_real

Measurement: TemperatureUnit: K

Note: Value can be positive or negative.

Formulas to find Real Gas Temperature

Reduced Temperature

Reduced Temperature is the ratio of the actual temperature of the fluid to its critical temperature. It is dimensionless.

Symbol: T_r

Measurement: NAUnit: Unitless

Note: Value should be greater than 0.

Formulas to find Reduced Temperature

Real Gas Pressure

Real Gas Pressure is the force applied perpendicular to the surface of an object per unit area over which that force is distributed.

Symbol: P_real

Measurement: PressureUnit: Pa

Note: Value can be positive or negative.

Formulas to find Real Gas Pressure

Reduced Pressure

Reduced Pressure is the ratio of the actual pressure of the fluid to its critical pressure. It is dimensionless.

Symbol: P_r

Measurement: NAUnit: Unitless

Note: Value should be between 0 to 1.

Formulas to find Reduced Pressure

Clausius Parameter c

Clausius parameter c is an empirical parameter characteristic to equation obtained from Clausius model of real gas.

Symbol: c

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Formulas to find Clausius Parameter c

Universal gas constant

Universal gas constant is a fundamental physical constant that appears in the ideal gas law, relating the pressure, volume, and temperature of an ideal gas.

Symbol: [R]

Value: 8.31446261815324

Other formulas in Reduced Volume category

Go Actual Pressure of Real Gas given Clausius Parameter a, Reduced and Critical Parameters

Pa = (\frac{27 \cdot ({[R]}^{2}) \cdot ({T' c}^{3})}{64 \cdot a}) \cdot P r

Go Actual Pressure of Real Gas given Clausius Parameter b, Reduced and Actual Parameters

Pb = (\frac{[R] \cdot (\frac{T rg}{T r})}{4 \cdot ((\frac{V real}{V r}) - b')}) \cdot P r

How to Evaluate Reduced Volume of Real Gas given Clausius Parameter c, Reduced and Actual Parameters?

Reduced Volume of Real Gas given Clausius Parameter c, Reduced and Actual Parameters evaluator uses Reduced Volume given RP AP = Volume of Real Gas/(((3*[R]*(Real Gas Temperature/Reduced Temperature))/(8*(Real Gas Pressure/Reduced Pressure)))-Clausius Parameter c) to evaluate the Reduced Volume given RP AP, The Reduced Volume of real gas given Clausius parameter c, reduced and actual parameters formula is defined as the ratio of its actual volume to critical volume. Reduced Volume given RP AP is denoted by V_{r_RP_AP} symbol.

How to evaluate Reduced Volume of Real Gas given Clausius Parameter c, Reduced and Actual Parameters using this online evaluator? To use this online evaluator for Reduced Volume of Real Gas given Clausius Parameter c, Reduced and Actual Parameters, enter Volume of Real Gas (V_real), Real Gas Temperature (T_real), Reduced Temperature (T_r), Real Gas Pressure (P_real), Reduced Pressure (P_r) & Clausius Parameter c (c) and hit the calculate button.

FAQs on Reduced Volume of Real Gas given Clausius Parameter c, Reduced and Actual Parameters

What is the formula to find Reduced Volume of Real Gas given Clausius Parameter c, Reduced and Actual Parameters?

The formula of Reduced Volume of Real Gas given Clausius Parameter c, Reduced and Actual Parameters is expressed as Reduced Volume given RP AP = Volume of Real Gas/(((3*[R]*(Real Gas Temperature/Reduced Temperature))/(8*(Real Gas Pressure/Reduced Pressure)))-Clausius Parameter c). Here is an example- 0.004335 = 0.022/(((3*[R]*(300/10))/(8*(101/0.8)))-0.0002).

How to calculate Reduced Volume of Real Gas given Clausius Parameter c, Reduced and Actual Parameters?

With Volume of Real Gas (V_real), Real Gas Temperature (T_real), Reduced Temperature (T_r), Real Gas Pressure (P_real), Reduced Pressure (P_r) & Clausius Parameter c (c) we can find Reduced Volume of Real Gas given Clausius Parameter c, Reduced and Actual Parameters using the formula - Reduced Volume given RP AP = Volume of Real Gas/(((3*[R]*(Real Gas Temperature/Reduced Temperature))/(8*(Real Gas Pressure/Reduced Pressure)))-Clausius Parameter c). This formula also uses Universal gas constant .

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Reduced Volume of Real Gas given Clausius Parameter c, Reduced and Actual Parameters Formula

Reduced Volume of Real Gas given Clausius Parameter c, Reduced and Actual Parameters Example

Reduced Volume of Real Gas given Clausius Parameter c, Reduced and Actual Parameters Solution

Reduced Volume of Real Gas given Clausius Parameter c, Reduced and Actual Parameters Formula Elements

Other formulas in Reduced Volume category

How to Evaluate Reduced Volume of Real Gas given Clausius Parameter c, Reduced and Actual Parameters?

FAQs on Reduced Volume of Real Gas given Clausius Parameter c, Reduced and Actual Parameters

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