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Reduced Volume of Real Gas given Clausius Parameter b, Reduced and Actual Parameters Formula

GoReduced Volume of Real Gas given Clausius Parameter b and Actual Parameters Formula

GoReduced Volume of Real Gas given Clausius Parameter c and Actual Parameters Formula

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Reduced Volume of a fluid is computed from the ideal gas law as the ratio of its actual volume to critical volume. Check FAQs

V r = \frac{V real}{b' + (\frac{[R] \cdot (\frac{T rg}{T r})}{4 \cdot (\frac{p}{P r})})}

V_r - Reduced Volume?V_real - Volume of Real Gas?b' - Clausius Parameter b for Real Gas?T_rg - Temperature of Real Gas?T_r - Reduced Temperature?p - Pressure?P_r - Reduced Pressure?[R] - Universal gas constant?

Reduced Volume of Real Gas given Clausius Parameter b, Reduced and Actual Parameters Example

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Here is how the Reduced Volume of Real Gas given Clausius Parameter b, Reduced and Actual Parameters equation looks like with Values.

Here is how the Reduced Volume of Real Gas given Clausius Parameter b, Reduced and Actual Parameters equation looks like with Units.

Here is how the Reduced Volume of Real Gas given Clausius Parameter b, Reduced and Actual Parameters equation looks like.

339.5666 = \frac{22}{0.0024 + (\frac{8.3145 \cdot (\frac{300}{10})}{4 \cdot (\frac{800}{0.8})})}

339.5666L = \frac{22L}{0.0024 + (\frac{8.3145 \cdot (\frac{300K}{10})}{4 \cdot (\frac{800Pa}{0.8})})}

339.5666 = \frac{22}{0.0024 + (\frac{8.3145 \cdot (\frac{300}{10})}{4 \cdot (\frac{800}{0.8})})}

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Reduced Volume of Real Gas given Clausius Parameter b, Reduced and Actual Parameters Solution

Follow our step by step solution on how to calculate Reduced Volume of Real Gas given Clausius Parameter b, Reduced and Actual Parameters?

FIRST Step Consider the formula

V r = \frac{V real}{b' + (\frac{[R] \cdot (\frac{T rg}{T r})}{4 \cdot (\frac{p}{P r})})}

Next Step Substitute values of Variables

∴

V r = \frac{22L}{0.0024 + (\frac{[R] \cdot (\frac{300K}{10})}{4 \cdot (\frac{800Pa}{0.8})})}

Next Step Substitute values of Constants

∴

V r = \frac{22L}{0.0024 + (\frac{8.3145 \cdot (\frac{300K}{10})}{4 \cdot (\frac{800Pa}{0.8})})}

Next Step Convert Units

∴

V r = \frac{0.022m³}{0.0024 + (\frac{8.3145 \cdot (\frac{300K}{10})}{4 \cdot (\frac{800Pa}{0.8})})}

Next Step Prepare to Evaluate

∴

V r = \frac{0.022}{0.0024 + (\frac{8.3145 \cdot (\frac{300}{10})}{4 \cdot (\frac{800}{0.8})})}

Next Step Evaluate

∴

V r = 0.339566594543004m³

Next Step Convert to Output's Unit

∴

V r = 339.566594543004L

LAST Step Rounding Answer

∴

V r = 339.5666L

Reduced Volume of Real Gas given Clausius Parameter b, Reduced and Actual Parameters Formula Elements

Variables

Constants

Reduced Volume

Reduced Volume of a fluid is computed from the ideal gas law as the ratio of its actual volume to critical volume.

Symbol: V_r

Measurement: VolumeUnit: L

Note: Value can be positive or negative.

Formulas to find Reduced Volume

Volume of Real Gas

Volume of Real Gas is the space occupied by that real gas at standard temperature and pressure.

Symbol: V_real

Measurement: VolumeUnit: L

Note: Value should be greater than 0.

Formulas to find Volume of Real Gas

Clausius Parameter b for Real Gas

Clausius Parameter b for Real Gas is an empirical parameter characteristic to equation obtained from Clausius model of real gas.

Symbol: b'

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Formulas to find Clausius Parameter b for Real Gas

Temperature of Real Gas

Temperature of Real Gas is the degree or intensity of heat present in a substance or object.

Symbol: T_rg

Measurement: TemperatureUnit: K

Note: Value can be positive or negative.

Formulas to find Temperature of Real Gas

Reduced Temperature

Reduced Temperature is the ratio of the actual temperature of the fluid to its critical temperature. It is dimensionless.

Symbol: T_r

Measurement: NAUnit: Unitless

Note: Value should be greater than 0.

Formulas to find Reduced Temperature

Pressure

Pressure is the force applied perpendicular to the surface of an object per unit area over which that force is distributed.

Symbol: p

Measurement: PressureUnit: Pa

Note: Value can be positive or negative.

Formulas to find Pressure

Reduced Pressure

Reduced Pressure is the ratio of the actual pressure of the fluid to its critical pressure. It is dimensionless.

Symbol: P_r

Measurement: NAUnit: Unitless

Note: Value should be between 0 to 1.

Formulas to find Reduced Pressure

Universal gas constant

Universal gas constant is a fundamental physical constant that appears in the ideal gas law, relating the pressure, volume, and temperature of an ideal gas.

Symbol: [R]

Value: 8.31446261815324

Other Formulas to find Reduced Volume

Go Reduced Volume of Real Gas given Clausius Parameter b and Actual Parameters

V r = \frac{V real}{b' + (\frac{[R] \cdot T' c}{4 \cdot P' c})}

Go Reduced Volume of Real Gas given Clausius Parameter c and Actual Parameters

V r = \frac{V real}{(\frac{3 \cdot [R] \cdot T c}{8 \cdot P' c}) - c}

Other formulas in Reduced Volume category

Go Reduced Volume of Real Gas given Clausius Parameter c, Reduced and Actual Parameters

V r_RP_AP = \frac{V real}{(\frac{3 \cdot [R] \cdot (\frac{T real}{T r})}{8 \cdot (\frac{P real}{P r})}) - c}

Go Reduced Molar Volume of Real Gas using Clausius Equation given Critical and Actual Parameters

V' m,r = \frac{(\frac{[R] \cdot T rg}{p + (\frac{a}{T rg})}) + b'}{V m,c}

How to Evaluate Reduced Volume of Real Gas given Clausius Parameter b, Reduced and Actual Parameters?

Reduced Volume of Real Gas given Clausius Parameter b, Reduced and Actual Parameters evaluator uses Reduced Volume = Volume of Real Gas/(Clausius Parameter b for Real Gas+(([R]*(Temperature of Real Gas/Reduced Temperature))/(4*(Pressure/Reduced Pressure)))) to evaluate the Reduced Volume, The Reduced Volume of real gas given Clausius parameter b, reduced and actual parameters formula is defined as the ratio of its actual volume to critical volume. Reduced Volume is denoted by V_r symbol.

How to evaluate Reduced Volume of Real Gas given Clausius Parameter b, Reduced and Actual Parameters using this online evaluator? To use this online evaluator for Reduced Volume of Real Gas given Clausius Parameter b, Reduced and Actual Parameters, enter Volume of Real Gas (V_real), Clausius Parameter b for Real Gas (b'), Temperature of Real Gas (T_rg), Reduced Temperature (T_r), Pressure (p) & Reduced Pressure (P_r) and hit the calculate button.

FAQs on Reduced Volume of Real Gas given Clausius Parameter b, Reduced and Actual Parameters

What is the formula to find Reduced Volume of Real Gas given Clausius Parameter b, Reduced and Actual Parameters?

The formula of Reduced Volume of Real Gas given Clausius Parameter b, Reduced and Actual Parameters is expressed as Reduced Volume = Volume of Real Gas/(Clausius Parameter b for Real Gas+(([R]*(Temperature of Real Gas/Reduced Temperature))/(4*(Pressure/Reduced Pressure)))). Here is an example- 1.1E+6 = 0.022/(0.00243+(([R]*(300/10))/(4*(800/0.8)))).

How to calculate Reduced Volume of Real Gas given Clausius Parameter b, Reduced and Actual Parameters?

With Volume of Real Gas (V_real), Clausius Parameter b for Real Gas (b'), Temperature of Real Gas (T_rg), Reduced Temperature (T_r), Pressure (p) & Reduced Pressure (P_r) we can find Reduced Volume of Real Gas given Clausius Parameter b, Reduced and Actual Parameters using the formula - Reduced Volume = Volume of Real Gas/(Clausius Parameter b for Real Gas+(([R]*(Temperature of Real Gas/Reduced Temperature))/(4*(Pressure/Reduced Pressure)))). This formula also uses Universal gas constant .

What are the other ways to Calculate Reduced Volume?

Here are the different ways to Calculate Reduced Volume-

Reduced Volume=Volume of Real Gas/(Clausius Parameter b for Real Gas+(([R]*Critical Temperature For Clausius Model)/(4*Critical Pressure of Real Gas)))
Reduced Volume=Volume of Real Gas/(((3*[R]*Critical Temperature)/(8*Critical Pressure of Real Gas))-Clausius Parameter c)
Reduced Volume=Volume of Real Gas/Critical Volume

Can the Reduced Volume of Real Gas given Clausius Parameter b, Reduced and Actual Parameters be negative?

Yes, the Reduced Volume of Real Gas given Clausius Parameter b, Reduced and Actual Parameters, measured in Volume can be negative.

Which unit is used to measure Reduced Volume of Real Gas given Clausius Parameter b, Reduced and Actual Parameters?

Reduced Volume of Real Gas given Clausius Parameter b, Reduced and Actual Parameters is usually measured using the Liter[L] for Volume. Cubic Meter[L], Cubic Centimeter[L], Cubic Millimeter[L] are the few other units in which Reduced Volume of Real Gas given Clausius Parameter b, Reduced and Actual Parameters can be measured.

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Reduced Volume of Real Gas given Clausius Parameter b, Reduced and Actual Parameters Formula

​GoReduced Volume of Real Gas given Clausius Parameter b and Actual Parameters Formula

​GoReduced Volume of Real Gas given Clausius Parameter c and Actual Parameters Formula

Reduced Volume of Real Gas given Clausius Parameter b, Reduced and Actual Parameters Example

Reduced Volume of Real Gas given Clausius Parameter b, Reduced and Actual Parameters Solution

Reduced Volume of Real Gas given Clausius Parameter b, Reduced and Actual Parameters Formula Elements

Other Formulas to find Reduced Volume

Other formulas in Reduced Volume category

How to Evaluate Reduced Volume of Real Gas given Clausius Parameter b, Reduced and Actual Parameters?

FAQs on Reduced Volume of Real Gas given Clausius Parameter b, Reduced and Actual Parameters

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GoReduced Volume of Real Gas given Clausius Parameter b and Actual Parameters Formula

GoReduced Volume of Real Gas given Clausius Parameter c and Actual Parameters Formula