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Reduced Temperature of Real Gas given Clausius Parameter and Actual Parameters Formula

GoReduced Temperature of Real Gas given Clausius Parameter a, Reduced and Actual Parameters Formula

GoReduced Temperature of Real Gas given Clausius Parameter c and Actual Parameters Formula

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Reduced Temperature is the ratio of the actual temperature of the fluid to its critical temperature. It is dimensionless. Check FAQs

T r = \frac{T rg}{{(\frac{a \cdot 64 \cdot P' c}{27 \cdot ({[R]}^{2})})}^{\frac{1}{3}}}

T_r - Reduced Temperature?T_rg - Temperature of Real Gas?a - Clausius Parameter a?P'_c - Critical Pressure of Real Gas?[R] - Universal gas constant?

Reduced Temperature of Real Gas given Clausius Parameter and Actual Parameters Example

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Here is how the Reduced Temperature of Real Gas given Clausius Parameter and Actual Parameters equation looks like with Values.

Here is how the Reduced Temperature of Real Gas given Clausius Parameter and Actual Parameters equation looks like with Units.

Here is how the Reduced Temperature of Real Gas given Clausius Parameter and Actual Parameters equation looks like.

11.9624 = \frac{300}{{(\frac{0.1 \cdot 64 \cdot 4.6E+6}{27 \cdot ({8.3145}^{2})})}^{\frac{1}{3}}}

11.9624 = \frac{300K}{{(\frac{0.1 \cdot 64 \cdot 4.6E+6Pa}{27 \cdot ({8.3145}^{2})})}^{\frac{1}{3}}}

11.9624 = \frac{300}{{(\frac{0.1 \cdot 64 \cdot 4.6E+6}{27 \cdot ({8.3145}^{2})})}^{\frac{1}{3}}}

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Reduced Temperature of Real Gas given Clausius Parameter and Actual Parameters Solution

Follow our step by step solution on how to calculate Reduced Temperature of Real Gas given Clausius Parameter and Actual Parameters?

FIRST Step Consider the formula

T r = \frac{T rg}{{(\frac{a \cdot 64 \cdot P' c}{27 \cdot ({[R]}^{2})})}^{\frac{1}{3}}}

Next Step Substitute values of Variables

∴

T r = \frac{300K}{{(\frac{0.1 \cdot 64 \cdot 4.6E+6Pa}{27 \cdot ({[R]}^{2})})}^{\frac{1}{3}}}

Next Step Substitute values of Constants

∴

T r = \frac{300K}{{(\frac{0.1 \cdot 64 \cdot 4.6E+6Pa}{27 \cdot ({8.3145}^{2})})}^{\frac{1}{3}}}

Next Step Prepare to Evaluate

∴

T r = \frac{300}{{(\frac{0.1 \cdot 64 \cdot 4.6E+6}{27 \cdot ({8.3145}^{2})})}^{\frac{1}{3}}}

Next Step Evaluate

∴

T r = 11.9624287552193

LAST Step Rounding Answer

∴

T r = 11.9624

Reduced Temperature of Real Gas given Clausius Parameter and Actual Parameters Formula Elements

Variables

Constants

Reduced Temperature

Reduced Temperature is the ratio of the actual temperature of the fluid to its critical temperature. It is dimensionless.

Symbol: T_r

Measurement: NAUnit: Unitless

Note: Value should be greater than 0.

Formulas to find Reduced Temperature

Temperature of Real Gas

Temperature of Real Gas is the degree or intensity of heat present in a substance or object.

Symbol: T_rg

Measurement: TemperatureUnit: K

Note: Value can be positive or negative.

Formulas to find Temperature of Real Gas

Clausius Parameter a

Clausius parameter a is an empirical parameter characteristic to equation obtained from Clausius model of real gas.

Symbol: a

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Formulas to find Clausius Parameter a

Critical Pressure of Real Gas

Critical Pressure of Real Gas is the minimum pressure required to liquify a substance at the critical temperature.

Symbol: P'_c

Measurement: PressureUnit: Pa

Note: Value should be greater than 0.

Formulas to find Critical Pressure of Real Gas

Universal gas constant

Universal gas constant is a fundamental physical constant that appears in the ideal gas law, relating the pressure, volume, and temperature of an ideal gas.

Symbol: [R]

Value: 8.31446261815324

Other Formulas to find Reduced Temperature

Go Reduced Temperature of Real Gas given Clausius Parameter a, Reduced and Actual Parameters

T r = \frac{T rg}{{(\frac{a \cdot 64 \cdot (\frac{p}{P r})}{27 \cdot ({[R]}^{2})})}^{\frac{1}{3}}}

Go Reduced Temperature of Real Gas given Clausius Parameter c and Actual Parameters

T r = \frac{T rg}{\frac{(c + V c) \cdot 8 \cdot P' c}{3 \cdot [R]}}

Go Reduced Temperature of Real Gas given Clausius Parameter c given Reduced and Actual Parameters

T r = \frac{T rg}{\frac{(c + (\frac{V real}{V r})) \cdot 8 \cdot (\frac{p}{P r})}{3 \cdot [R]}}

Go Reduced Temperature of Real Gas using Clausius Equation given Critical and Actual Parameters

T r = \frac{(p + (\frac{a}{({(V m + c)}^{2})})) \cdot (\frac{V m - b'}{[R]})}{T' c}

Other formulas in Reduced Temperature of Real Gas category

Go Reduced Temperature of Real Gas using Clausius Equation given Reduced and Actual Parameters

T r_RP_AP = \frac{(p + (\frac{a}{({(V m + c)}^{2})})) \cdot (\frac{V m - b'}{[R]})}{T rg}

How to Evaluate Reduced Temperature of Real Gas given Clausius Parameter and Actual Parameters?

Reduced Temperature of Real Gas given Clausius Parameter and Actual Parameters evaluator uses Reduced Temperature = Temperature of Real Gas/(((Clausius Parameter a*64*Critical Pressure of Real Gas)/(27*([R]^2)))^(1/3)) to evaluate the Reduced Temperature, The Reduced Temperature of real gas given Clausius parameter and actual parameters formula is defined as the ratio of the actual temperature of the fluid to its critical temperature. It is dimensionless. Reduced Temperature is denoted by T_r symbol.

How to evaluate Reduced Temperature of Real Gas given Clausius Parameter and Actual Parameters using this online evaluator? To use this online evaluator for Reduced Temperature of Real Gas given Clausius Parameter and Actual Parameters, enter Temperature of Real Gas (T_rg), Clausius Parameter a (a) & Critical Pressure of Real Gas (P'_c) and hit the calculate button.

FAQs on Reduced Temperature of Real Gas given Clausius Parameter and Actual Parameters

What is the formula to find Reduced Temperature of Real Gas given Clausius Parameter and Actual Parameters?

The formula of Reduced Temperature of Real Gas given Clausius Parameter and Actual Parameters is expressed as Reduced Temperature = Temperature of Real Gas/(((Clausius Parameter a*64*Critical Pressure of Real Gas)/(27*([R]^2)))^(1/3)). Here is an example- 3.389355 = 300/(((0.1*64*4600000)/(27*([R]^2)))^(1/3)).

How to calculate Reduced Temperature of Real Gas given Clausius Parameter and Actual Parameters?

With Temperature of Real Gas (T_rg), Clausius Parameter a (a) & Critical Pressure of Real Gas (P'_c) we can find Reduced Temperature of Real Gas given Clausius Parameter and Actual Parameters using the formula - Reduced Temperature = Temperature of Real Gas/(((Clausius Parameter a*64*Critical Pressure of Real Gas)/(27*([R]^2)))^(1/3)). This formula also uses Universal gas constant .

What are the other ways to Calculate Reduced Temperature?

Here are the different ways to Calculate Reduced Temperature-

Reduced Temperature=Temperature of Real Gas/(((Clausius Parameter a*64*(Pressure/Reduced Pressure))/(27*([R]^2)))^(1/3))
Reduced Temperature=Temperature of Real Gas/(((Clausius Parameter c+Critical Volume)*8*Critical Pressure of Real Gas)/(3*[R]))
Reduced Temperature=Temperature of Real Gas/(((Clausius Parameter c+(Volume of Real Gas/Reduced Volume))*8*(Pressure/Reduced Pressure))/(3*[R]))

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