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Reduced Pressure using Modified Berthelot Equation given Actual Parameters Formula

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Reduced Pressure is the ratio of the actual pressure of the fluid to its critical pressure. It is dimensionless. Check FAQs

P r = \frac{128}{9} \cdot T r \cdot (\frac{(\frac{P rg \cdot V' m}{[R] \cdot T rg}) - 1}{1 - (\frac{6}{{T r}^{2}})})

P_r - Reduced Pressure?T_r - Reduced Temperature?P_rg - Pressure of Gas?V'_m - Molar Volume of Real Gas?T_rg - Temperature of Real Gas?[R] - Universal gas constant?

Reduced Pressure using Modified Berthelot Equation given Actual Parameters Example

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Here is how the Reduced Pressure using Modified Berthelot Equation given Actual Parameters equation looks like with Values.

Here is how the Reduced Pressure using Modified Berthelot Equation given Actual Parameters equation looks like with Units.

Here is how the Reduced Pressure using Modified Berthelot Equation given Actual Parameters equation looks like.

0.2189 = \frac{128}{9} \cdot 0.461 \cdot (\frac{(\frac{10132 \cdot 0.0224}{8.3145 \cdot 300}) - 1}{1 - (\frac{6}{{0.461}^{2}})})

0.2189 = \frac{128}{9} \cdot 0.461 \cdot (\frac{(\frac{10132Pa \cdot 0.0224m³}{8.3145 \cdot 300K}) - 1}{1 - (\frac{6}{{0.461}^{2}})})

0.2189 = \frac{128}{9} \cdot 0.461 \cdot (\frac{(\frac{10132 \cdot 0.0224}{8.3145 \cdot 300}) - 1}{1 - (\frac{6}{{0.461}^{2}})})

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Reduced Pressure using Modified Berthelot Equation given Actual Parameters Solution

Follow our step by step solution on how to calculate Reduced Pressure using Modified Berthelot Equation given Actual Parameters?

FIRST Step Consider the formula

P r = \frac{128}{9} \cdot T r \cdot (\frac{(\frac{P rg \cdot V' m}{[R] \cdot T rg}) - 1}{1 - (\frac{6}{{T r}^{2}})})

Next Step Substitute values of Variables

∴

P r = \frac{128}{9} \cdot 0.461 \cdot (\frac{(\frac{10132Pa \cdot 0.0224m³}{[R] \cdot 300K}) - 1}{1 - (\frac{6}{{0.461}^{2}})})

Next Step Substitute values of Constants

∴

P r = \frac{128}{9} \cdot 0.461 \cdot (\frac{(\frac{10132Pa \cdot 0.0224m³}{8.3145 \cdot 300K}) - 1}{1 - (\frac{6}{{0.461}^{2}})})

Next Step Prepare to Evaluate

∴

P r = \frac{128}{9} \cdot 0.461 \cdot (\frac{(\frac{10132 \cdot 0.0224}{8.3145 \cdot 300}) - 1}{1 - (\frac{6}{{0.461}^{2}})})

Next Step Evaluate

∴

P r = 0.218851768400877

LAST Step Rounding Answer

∴

P r = 0.2189

Reduced Pressure using Modified Berthelot Equation given Actual Parameters Formula Elements

Variables

Constants

Reduced Pressure

Reduced Pressure is the ratio of the actual pressure of the fluid to its critical pressure. It is dimensionless.

Symbol: P_r

Measurement: NAUnit: Unitless

Note: Value should be between 0 to 1.

Formulas to find Reduced Pressure

Reduced Temperature

Reduced Temperature is the ratio of the actual temperature of the fluid to its critical temperature. It is dimensionless.

Symbol: T_r

Measurement: NAUnit: Unitless

Note: Value should be greater than 0.

Formulas to find Reduced Temperature

Pressure of Gas

Pressure of Gas is the force applied perpendicular to the surface of an object per unit area over which that force is distributed.

Symbol: P_rg

Measurement: PressureUnit: Pa

Note: Value can be positive or negative.

Formulas to find Pressure of Gas

Molar Volume of Real Gas

Molar Volume of Real Gas or Molar gas volume is one mole of any gas at a specific temperature and pressure has a fixed volume.

Symbol: V'_m

Measurement: VolumeUnit: m³

Note: Value can be positive or negative.

Formulas to find Molar Volume of Real Gas

Temperature of Real Gas

Temperature of Real Gas is the degree or intensity of heat present in a substance or object.

Symbol: T_rg

Measurement: TemperatureUnit: K

Note: Value can be positive or negative.

Formulas to find Temperature of Real Gas

Universal gas constant

Universal gas constant is a fundamental physical constant that appears in the ideal gas law, relating the pressure, volume, and temperature of an ideal gas.

Symbol: [R]

Value: 8.31446261815324

Other formulas in Berthelot and Modified Berthelot Model of Real Gas category

Go Pressure of Real Gas using Berthelot Equation

p = (\frac{[R] \cdot T}{V m - b}) - (\frac{a}{T \cdot ({V m}^{2})})

Go Temperature of Real Gas using Berthelot Equation

T = \frac{p + (\frac{a}{V m})}{\frac{[R]}{V m - b}}

Go Molar Volume of Real Gas using Berthelot Equation

V m = \frac{(\frac{1}{p}) + (\frac{b}{[R] \cdot T})}{(\frac{1}{[R] \cdot T}) - (\frac{T}{a})}

Go Berthelot Parameter of Real Gas

a = ((\frac{[R] \cdot T}{V m - b}) - p) \cdot (T \cdot ({V m}^{2}))

How to Evaluate Reduced Pressure using Modified Berthelot Equation given Actual Parameters?

Reduced Pressure using Modified Berthelot Equation given Actual Parameters evaluator uses Reduced Pressure = 128/9*Reduced Temperature*((((Pressure of Gas*Molar Volume of Real Gas)/([R]*Temperature of Real Gas))-1)/(1-(6/(Reduced Temperature^2)))) to evaluate the Reduced Pressure, The Reduced Pressure using Modified Berthelot equation given actual parameters formula is defined as the ratio of the actual pressure of the fluid to its critical pressure. It is dimensionless. Reduced Pressure is denoted by P_r symbol.

How to evaluate Reduced Pressure using Modified Berthelot Equation given Actual Parameters using this online evaluator? To use this online evaluator for Reduced Pressure using Modified Berthelot Equation given Actual Parameters, enter Reduced Temperature (T_r), Pressure of Gas (P_rg), Molar Volume of Real Gas (V'_m) & Temperature of Real Gas (T_rg) and hit the calculate button.

FAQs on Reduced Pressure using Modified Berthelot Equation given Actual Parameters

What is the formula to find Reduced Pressure using Modified Berthelot Equation given Actual Parameters?

The formula of Reduced Pressure using Modified Berthelot Equation given Actual Parameters is expressed as Reduced Pressure = 128/9*Reduced Temperature*((((Pressure of Gas*Molar Volume of Real Gas)/([R]*Temperature of Real Gas))-1)/(1-(6/(Reduced Temperature^2)))). Here is an example- 0.163442 = 128/9*0.461*((((10132*0.0224)/([R]*300))-1)/(1-(6/(0.461^2)))).

How to calculate Reduced Pressure using Modified Berthelot Equation given Actual Parameters?

With Reduced Temperature (T_r), Pressure of Gas (P_rg), Molar Volume of Real Gas (V'_m) & Temperature of Real Gas (T_rg) we can find Reduced Pressure using Modified Berthelot Equation given Actual Parameters using the formula - Reduced Pressure = 128/9*Reduced Temperature*((((Pressure of Gas*Molar Volume of Real Gas)/([R]*Temperature of Real Gas))-1)/(1-(6/(Reduced Temperature^2)))). This formula also uses Universal gas constant .

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Reduced Pressure using Modified Berthelot Equation given Actual Parameters Formula

Reduced Pressure using Modified Berthelot Equation given Actual Parameters Example

Reduced Pressure using Modified Berthelot Equation given Actual Parameters Solution

Reduced Pressure using Modified Berthelot Equation given Actual Parameters Formula Elements

Other formulas in Berthelot and Modified Berthelot Model of Real Gas category

How to Evaluate Reduced Pressure using Modified Berthelot Equation given Actual Parameters?

FAQs on Reduced Pressure using Modified Berthelot Equation given Actual Parameters

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