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Reduced Molar Volume of Real Gas using Clausius Equation given Reduced and Critical Parameters Formula

GoReduced Molar Volume of Real Gas using Clausius Equation given Critical and Actual Parameters Formula

GoReduced Molar Volume of Real Gas using Clausius Equation given Reduced and Actual Parameters Formula

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Reduced Molar Volume for Real Gas of a fluid is computed from the ideal gas law at the substance's critical pressure and temperature per mole. Check FAQs

V' m,r = \frac{(\frac{[R] \cdot (T r \cdot T' c)}{(P r \cdot P' c) + (\frac{a}{T r \cdot T' c})}) + b'}{V m,c}

V'_m,r - Reduced Molar Volume for Real Gas?T_r - Reduced Temperature?T'_c - Critical Temperature For Clausius Model?P_r - Reduced Pressure?P'_c - Critical Pressure of Real Gas?a - Clausius Parameter a?b' - Clausius Parameter b for Real Gas?V_m,c - Critical Molar Volume?[R] - Universal gas constant?

Reduced Molar Volume of Real Gas using Clausius Equation given Reduced and Critical Parameters Example

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Here is how the Reduced Molar Volume of Real Gas using Clausius Equation given Reduced and Critical Parameters equation looks like with Values.

Here is how the Reduced Molar Volume of Real Gas using Clausius Equation given Reduced and Critical Parameters equation looks like with Units.

Here is how the Reduced Molar Volume of Real Gas using Clausius Equation given Reduced and Critical Parameters equation looks like.

0.0005 = \frac{(\frac{8.3145 \cdot (10 \cdot 154.4)}{(0.8 \cdot 4.6E+6) + (\frac{0.1}{10 \cdot 154.4})}) + 0.0024}{11.5}

0.0005 = \frac{(\frac{8.3145 \cdot (10 \cdot 154.4K)}{(0.8 \cdot 4.6E+6Pa) + (\frac{0.1}{10 \cdot 154.4K})}) + 0.0024}{11.5m³/mol}

0.0005 = \frac{(\frac{8.3145 \cdot (10 \cdot 154.4)}{(0.8 \cdot 4.6E+6) + (\frac{0.1}{10 \cdot 154.4})}) + 0.0024}{11.5}

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Reduced Molar Volume of Real Gas using Clausius Equation given Reduced and Critical Parameters Solution

Follow our step by step solution on how to calculate Reduced Molar Volume of Real Gas using Clausius Equation given Reduced and Critical Parameters?

FIRST Step Consider the formula

V' m,r = \frac{(\frac{[R] \cdot (T r \cdot T' c)}{(P r \cdot P' c) + (\frac{a}{T r \cdot T' c})}) + b'}{V m,c}

Next Step Substitute values of Variables

∴

V' m,r = \frac{(\frac{[R] \cdot (10 \cdot 154.4K)}{(0.8 \cdot 4.6E+6Pa) + (\frac{0.1}{10 \cdot 154.4K})}) + 0.0024}{11.5m³/mol}

Next Step Substitute values of Constants

∴

V' m,r = \frac{(\frac{8.3145 \cdot (10 \cdot 154.4K)}{(0.8 \cdot 4.6E+6Pa) + (\frac{0.1}{10 \cdot 154.4K})}) + 0.0024}{11.5m³/mol}

Next Step Prepare to Evaluate

∴

V' m,r = \frac{(\frac{8.3145 \cdot (10 \cdot 154.4)}{(0.8 \cdot 4.6E+6) + (\frac{0.1}{10 \cdot 154.4})}) + 0.0024}{11.5}

Next Step Evaluate

∴

V' m,r = 0.000514648636157908

LAST Step Rounding Answer

∴

V' m,r = 0.0005

Reduced Molar Volume of Real Gas using Clausius Equation given Reduced and Critical Parameters Formula Elements

Variables

Constants

Reduced Molar Volume for Real Gas

Reduced Molar Volume for Real Gas of a fluid is computed from the ideal gas law at the substance's critical pressure and temperature per mole.

Symbol: V'_m,r

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Formulas to find Reduced Molar Volume for Real Gas

Reduced Temperature

Reduced Temperature is the ratio of the actual temperature of the fluid to its critical temperature. It is dimensionless.

Symbol: T_r

Measurement: NAUnit: Unitless

Note: Value should be greater than 0.

Formulas to find Reduced Temperature

Critical Temperature For Clausius Model

Critical Temperature For Clausius Model is the highest temperature at which the substance can exist as a liquid. At this phase boundaries vanish, the substance can exist both as a liquid and vapor.

Symbol: T'_c

Measurement: TemperatureUnit: K

Note: Value should be greater than 0.

Formulas to find Critical Temperature For Clausius Model

Reduced Pressure

Reduced Pressure is the ratio of the actual pressure of the fluid to its critical pressure. It is dimensionless.

Symbol: P_r

Measurement: NAUnit: Unitless

Note: Value should be between 0 to 1.

Formulas to find Reduced Pressure

Critical Pressure of Real Gas

Critical Pressure of Real Gas is the minimum pressure required to liquify a substance at the critical temperature.

Symbol: P'_c

Measurement: PressureUnit: Pa

Note: Value should be greater than 0.

Formulas to find Critical Pressure of Real Gas

Clausius Parameter a

Clausius parameter a is an empirical parameter characteristic to equation obtained from Clausius model of real gas.

Symbol: a

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Formulas to find Clausius Parameter a

Clausius Parameter b for Real Gas

Clausius Parameter b for Real Gas is an empirical parameter characteristic to equation obtained from Clausius model of real gas.

Symbol: b'

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Formulas to find Clausius Parameter b for Real Gas

Critical Molar Volume

Critical Molar Volume is the volume occupied by gas at critical temperature and pressure per mole.

Symbol: V_m,c

Measurement: Molar Magnetic SusceptibilityUnit: m³/mol

Note: Value can be positive or negative.

Formulas to find Critical Molar Volume

Universal gas constant

Universal gas constant is a fundamental physical constant that appears in the ideal gas law, relating the pressure, volume, and temperature of an ideal gas.

Symbol: [R]

Value: 8.31446261815324

Other Formulas to find Reduced Molar Volume for Real Gas

Go Reduced Molar Volume of Real Gas using Clausius Equation given Critical and Actual Parameters

V' m,r = \frac{(\frac{[R] \cdot T rg}{p + (\frac{a}{T rg})}) + b'}{V m,c}

Go Reduced Molar Volume of Real Gas using Clausius Equation given Reduced and Actual Parameters

V' m,r = \frac{(\frac{[R] \cdot T rg}{p + (\frac{a}{T rg})}) + b'}{V m}

Other formulas in Reduced Volume category

Go Reduced Volume of Real Gas given Clausius Parameter b and Actual Parameters

V r = \frac{V real}{b' + (\frac{[R] \cdot T' c}{4 \cdot P' c})}

Go Reduced Volume of Real Gas given Clausius Parameter b, Reduced and Actual Parameters

V r = \frac{V real}{b' + (\frac{[R] \cdot (\frac{T rg}{T r})}{4 \cdot (\frac{p}{P r})})}

How to Evaluate Reduced Molar Volume of Real Gas using Clausius Equation given Reduced and Critical Parameters?

Reduced Molar Volume of Real Gas using Clausius Equation given Reduced and Critical Parameters evaluator uses Reduced Molar Volume for Real Gas = ((([R]*(Reduced Temperature*Critical Temperature For Clausius Model))/((Reduced Pressure*Critical Pressure of Real Gas)+(Clausius Parameter a/(Reduced Temperature*Critical Temperature For Clausius Model))))+Clausius Parameter b for Real Gas)/Critical Molar Volume to evaluate the Reduced Molar Volume for Real Gas, The Reduced Molar Volume of real gas using Clausius equation given reduced and critical parameters formula of a fluid is computed from the ideal gas law as the ratio of its actual volume to critical volume per mole. Reduced Molar Volume for Real Gas is denoted by V'_m,r symbol.

How to evaluate Reduced Molar Volume of Real Gas using Clausius Equation given Reduced and Critical Parameters using this online evaluator? To use this online evaluator for Reduced Molar Volume of Real Gas using Clausius Equation given Reduced and Critical Parameters, enter Reduced Temperature (T_r), Critical Temperature For Clausius Model (T'_c), Reduced Pressure (P_r), Critical Pressure of Real Gas (P'_c), Clausius Parameter a (a), Clausius Parameter b for Real Gas (b') & Critical Molar Volume (V_m,c) and hit the calculate button.

FAQs on Reduced Molar Volume of Real Gas using Clausius Equation given Reduced and Critical Parameters

What is the formula to find Reduced Molar Volume of Real Gas using Clausius Equation given Reduced and Critical Parameters?

The formula of Reduced Molar Volume of Real Gas using Clausius Equation given Reduced and Critical Parameters is expressed as Reduced Molar Volume for Real Gas = ((([R]*(Reduced Temperature*Critical Temperature For Clausius Model))/((Reduced Pressure*Critical Pressure of Real Gas)+(Clausius Parameter a/(Reduced Temperature*Critical Temperature For Clausius Model))))+Clausius Parameter b for Real Gas)/Critical Molar Volume. Here is an example- 0.000515 = ((([R]*(10*154.4))/((0.8*4600000)+(0.1/(10*154.4))))+0.00243)/11.5.

How to calculate Reduced Molar Volume of Real Gas using Clausius Equation given Reduced and Critical Parameters?

With Reduced Temperature (T_r), Critical Temperature For Clausius Model (T'_c), Reduced Pressure (P_r), Critical Pressure of Real Gas (P'_c), Clausius Parameter a (a), Clausius Parameter b for Real Gas (b') & Critical Molar Volume (V_m,c) we can find Reduced Molar Volume of Real Gas using Clausius Equation given Reduced and Critical Parameters using the formula - Reduced Molar Volume for Real Gas = ((([R]*(Reduced Temperature*Critical Temperature For Clausius Model))/((Reduced Pressure*Critical Pressure of Real Gas)+(Clausius Parameter a/(Reduced Temperature*Critical Temperature For Clausius Model))))+Clausius Parameter b for Real Gas)/Critical Molar Volume. This formula also uses Universal gas constant .

What are the other ways to Calculate Reduced Molar Volume for Real Gas?

Here are the different ways to Calculate Reduced Molar Volume for Real Gas-

Reduced Molar Volume for Real Gas=((([R]*Temperature of Real Gas)/(Pressure+(Clausius Parameter a/Temperature of Real Gas)))+Clausius Parameter b for Real Gas)/Critical Molar Volume
Reduced Molar Volume for Real Gas=((([R]*Temperature of Real Gas)/(Pressure+(Clausius Parameter a/Temperature of Real Gas)))+Clausius Parameter b for Real Gas)/Molar Volume

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Reduced Molar Volume of Real Gas using Clausius Equation given Reduced and Critical Parameters Formula

​GoReduced Molar Volume of Real Gas using Clausius Equation given Critical and Actual Parameters Formula

​GoReduced Molar Volume of Real Gas using Clausius Equation given Reduced and Actual Parameters Formula

Reduced Molar Volume of Real Gas using Clausius Equation given Reduced and Critical Parameters Example

Reduced Molar Volume of Real Gas using Clausius Equation given Reduced and Critical Parameters Solution

Reduced Molar Volume of Real Gas using Clausius Equation given Reduced and Critical Parameters Formula Elements

Other Formulas to find Reduced Molar Volume for Real Gas

Other formulas in Reduced Volume category

How to Evaluate Reduced Molar Volume of Real Gas using Clausius Equation given Reduced and Critical Parameters?

FAQs on Reduced Molar Volume of Real Gas using Clausius Equation given Reduced and Critical Parameters

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GoReduced Molar Volume of Real Gas using Clausius Equation given Critical and Actual Parameters Formula

GoReduced Molar Volume of Real Gas using Clausius Equation given Reduced and Actual Parameters Formula