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Ratio of Partial Pressure of 2 Immiscible Liquids given Number of Moles Formula

GoRatio of Partial Vapour Pressures of 2 Immiscible Liquids given Weight and Molecular Mass Formula

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The Ratio of Partial Pressures of 2 immiscible liquids in a mixture. Check FAQs

P A:B = \frac{n A}{n B}

P_A:B - Ratio of Partial Pressures of 2 Immiscible Liquids?n_A - Number of Moles of Liquid A?n_B - Number of Moles of Liquid B?

Ratio of Partial Pressure of 2 Immiscible Liquids given Number of Moles Example

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Here is how the Ratio of Partial Pressure of 2 Immiscible Liquids given Number of Moles equation looks like with Values.

Here is how the Ratio of Partial Pressure of 2 Immiscible Liquids given Number of Moles equation looks like with Units.

Here is how the Ratio of Partial Pressure of 2 Immiscible Liquids given Number of Moles equation looks like.

10.8182 = \frac{119}{11}

10.8182 = \frac{119mol}{11mol}

10.8182 = \frac{119}{11}

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Immiscible Liquids » fx Ratio of Partial Pressure of 2 Immiscible Liquids given Number of Moles

Ratio of Partial Pressure of 2 Immiscible Liquids given Number of Moles Solution

Follow our step by step solution on how to calculate Ratio of Partial Pressure of 2 Immiscible Liquids given Number of Moles?

FIRST Step Consider the formula

P A:B = \frac{n A}{n B}

Next Step Substitute values of Variables

∴

P A:B = \frac{119mol}{11mol}

Next Step Prepare to Evaluate

∴

P A:B = \frac{119}{11}

Next Step Evaluate

∴

P A:B = 10.8181818181818

LAST Step Rounding Answer

∴

P A:B = 10.8182

Ratio of Partial Pressure of 2 Immiscible Liquids given Number of Moles Formula Elements

Variables

Ratio of Partial Pressures of 2 Immiscible Liquids

The Ratio of Partial Pressures of 2 immiscible liquids in a mixture.

Symbol: P_A:B

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Formulas to find Ratio of Partial Pressures of 2 Immiscible Liquids

Number of Moles of Liquid A

The Number of moles of Liquid A in a mixture.

Symbol: n_A

Measurement: Amount of SubstanceUnit: mol

Note: Value should be greater than 0.

Formulas to find Number of Moles of Liquid A

Number of Moles of Liquid B

The Number of Moles of Liquid B in a mixture.

Symbol: n_B

Measurement: Amount of SubstanceUnit: mol

Note: Value should be greater than 0.

Formulas to find Number of Moles of Liquid B

Other Formulas to find Ratio of Partial Pressures of 2 Immiscible Liquids

Go Ratio of Partial Vapour Pressures of 2 Immiscible Liquids given Weight and Molecular Mass

P A:B = \frac{W A \cdot M B}{W B \cdot M A}

Other formulas in Immiscible Liquids category

Go Total Pressure of Mixture of Two Immiscible Liquids

P = P A ° + P B °

Go Partial Vapour Pressure of Immiscible Liquid given Partial Pressure of other Liquid

P A ° = \frac{W A \cdot M B \cdot P B °}{M A \cdot W B}

Go Weight of Liquid in Mixture of 2 Immiscible Liquids given Weight of other Liquid

W A = \frac{P A ° \cdot M A \cdot W B}{P B ° \cdot M B}

Go Ratio of Molecular Mass of 2 Immiscible Liquids

M A:B = \frac{P B ° \cdot W A}{P A ° \cdot W B}

How to Evaluate Ratio of Partial Pressure of 2 Immiscible Liquids given Number of Moles?

Ratio of Partial Pressure of 2 Immiscible Liquids given Number of Moles evaluator uses Ratio of Partial Pressures of 2 Immiscible Liquids = Number of Moles of Liquid A/Number of Moles of Liquid B to evaluate the Ratio of Partial Pressures of 2 Immiscible Liquids, The Ratio of Partial Pressure of 2 Immiscible Liquids given Number of Moles is the ratio of number of moles of both liquids present. Ratio of Partial Pressures of 2 Immiscible Liquids is denoted by P_A:B symbol.

How to evaluate Ratio of Partial Pressure of 2 Immiscible Liquids given Number of Moles using this online evaluator? To use this online evaluator for Ratio of Partial Pressure of 2 Immiscible Liquids given Number of Moles, enter Number of Moles of Liquid A (n_A) & Number of Moles of Liquid B (n_B) and hit the calculate button.

FAQs on Ratio of Partial Pressure of 2 Immiscible Liquids given Number of Moles

What is the formula to find Ratio of Partial Pressure of 2 Immiscible Liquids given Number of Moles?

The formula of Ratio of Partial Pressure of 2 Immiscible Liquids given Number of Moles is expressed as Ratio of Partial Pressures of 2 Immiscible Liquids = Number of Moles of Liquid A/Number of Moles of Liquid B. Here is an example- 10.81818 = 119/11.

How to calculate Ratio of Partial Pressure of 2 Immiscible Liquids given Number of Moles?

With Number of Moles of Liquid A (n_A) & Number of Moles of Liquid B (n_B) we can find Ratio of Partial Pressure of 2 Immiscible Liquids given Number of Moles using the formula - Ratio of Partial Pressures of 2 Immiscible Liquids = Number of Moles of Liquid A/Number of Moles of Liquid B.

What are the other ways to Calculate Ratio of Partial Pressures of 2 Immiscible Liquids?

Here are the different ways to Calculate Ratio of Partial Pressures of 2 Immiscible Liquids-

Ratio of Partial Pressures of 2 Immiscible Liquids=(Weight of Liquid A*Molecular Mass of Liquid B)/(Weight of Liquid B*Molecular Mass of Liquid A)

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